我在我的应用程序中有同样的问题。我已经解决了这个问题，只是调用super.onBackPressed();并在当前类上调用commitAllowingStateLoss()。

我有同样的问题，得到IllegalStateException，但替换所有调用commit()与commitAllowingStateLoss()没有帮助。

罪魁祸首是调用DialogFragment.show()。

我用

try {
    dialog.show(transaction, "blah blah");
}
catch(IllegalStateException e) {
    return;
}

这样就成功了。好吧，我没有展示对话，但在这种情况下，这是可以的。

这是我的应用程序中唯一一个我第一次调用FragmentManager.beginTransaction()但从未调用commit()的地方，所以当我寻找“commit()”时，我没有找到它。

有趣的是，用户从未离开该应用。相反，出现的AdMob插页广告才是罪魁祸首。

这是我迄今为止遇到的最愚蠢的错误。我有一个片段应用程序工作完美的API < 11，并强制关闭API > 11。

我真的不知道他们在saveInstance调用的活动生命周期内改变了什么，但我在这里是我如何解决这个问题的:

@Override
protected void onSaveInstanceState(Bundle outState) {
    //No call for super(). Bug on API Level > 11.
}

我只是不调用.super()，一切都很好。我希望这将为您节省一些时间。

编辑:经过进一步研究，这是支持包中的一个已知错误。

如果你需要保存实例，并添加一些东西到你的outState Bundle，你可以使用以下方法:

@Override
protected void onSaveInstanceState(Bundle outState) {
    outState.putString("WORKAROUND_FOR_BUG_19917_KEY", "WORKAROUND_FOR_BUG_19917_VALUE");
    super.onSaveInstanceState(outState);
}

EDIT2:如果您试图在Activity在后台消失后执行事务，也可能会发生这种情况。为了避免这种情况，你应该使用commitAllowingStateLoss()

EDIT3: The above solutions were fixing issues in the early support.v4 libraries from what I can remember. But if you still have issues with this you MUST also read @AlexLockwood 's blog : Fragment Transactions & Activity State Loss Summary from the blog post (but I strongly recommend you to read it) : NEVER commit() transactions after onPause() on pre-Honeycomb, and onStop() on post-Honeycomb Be careful when committing transactions inside Activity lifecycle methods. Use onCreate(), onResumeFragments() and onPostResume() Avoid performing transactions inside asynchronous callback methods Use commitAllowingStateLoss() only as a last resort

我在我的应用程序中有同样的问题。我已经解决了这个问题，只是调用super.onBackPressed();并在当前类上调用commitAllowingStateLoss()。

I noticed something very interesting. I have in my app the option to open the phone's gallery and the device asks what app to use, there I click on the gray area away from the dialog and saw this issue. I noticed how my activity goes from onPause, onSaveInstanceState back to onResume, it doesn't happen to visit onCreateView. I am doing transactions at onResume. So what I ended up doing is setting a flag being negated onPause, but being true onCreateView. if the flag is true onResume then do onCommit, otherwise commitAllowingStateLoss. I could go on and waste so much time but I wanted to check the lifecycle. I have a device which is sdkversion 23, and I don't get this issue, but I have another one which is 21, and there I see it.

我有这个问题。但是我认为这个问题与commit和commitAllowStateLoss无关。

下面的堆栈跟踪和异常消息是关于commit()的。

java.lang.IllegalStateException: Can not perform this action after onSaveInstanceState
at android.support.v4.app.FragmentManagerImpl.checkStateLoss(FragmentManager.java:1341)
at android.support.v4.app.FragmentManagerImpl.enqueueAction(FragmentManager.java:1352)
at android.support.v4.app.BackStackRecord.commitInternal(BackStackRecord.java:595)
at android.support.v4.app.BackStackRecord.commit(BackStackRecord.java:574)

但是这个异常是由onBackPressed()引起的

java.lang.IllegalStateException: Can not perform this action after onSaveInstanceState
at android.support.v4.app.FragmentManagerImpl.checkStateLoss(Unknown Source)
at android.support.v4.app.FragmentManagerImpl.popBackStackImmediate(Unknown Source)
at android.support.v4.app.FragmentActivity.onBackPressed(Unknown Source)

它们都是由checkStateLoss()引起的

private void checkStateLoss() {
    if (mStateSaved) {
        throw new IllegalStateException(
                "Can not perform this action after onSaveInstanceState");
    }
    if (mNoTransactionsBecause != null) {
        throw new IllegalStateException(
                "Can not perform this action inside of " + mNoTransactionsBecause);
    }

mStateSaved在onSaveInstanceState之后为真。

这个问题很少发生。我从来没有遇到过这个问题。我不能再出现这个问题。

我找到了25517号

它可能在下列情况下发生

Back键在onSaveInstanceState之后，但在新活动开始之前被调用。 在代码中使用onStop()

我不确定问题的根源是什么。 所以我用了一个丑陋的方法。

@Override
public void onBackPressed() {

    try{
        super.onBackPressed();
    }catch (IllegalStateException e){
        // can output some information here
        finish();
    }
}