这是我迄今为止遇到的最愚蠢的错误。我有一个片段应用程序工作完美的API < 11，并强制关闭API > 11。

我真的不知道他们在saveInstance调用的活动生命周期内改变了什么，但我在这里是我如何解决这个问题的:

@Override
protected void onSaveInstanceState(Bundle outState) {
    //No call for super(). Bug on API Level > 11.
}

我只是不调用.super()，一切都很好。我希望这将为您节省一些时间。

编辑:经过进一步研究，这是支持包中的一个已知错误。

如果你需要保存实例，并添加一些东西到你的outState Bundle，你可以使用以下方法:

@Override
protected void onSaveInstanceState(Bundle outState) {
    outState.putString("WORKAROUND_FOR_BUG_19917_KEY", "WORKAROUND_FOR_BUG_19917_VALUE");
    super.onSaveInstanceState(outState);
}

EDIT2:如果您试图在Activity在后台消失后执行事务，也可能会发生这种情况。为了避免这种情况，你应该使用commitAllowingStateLoss()

EDIT3: The above solutions were fixing issues in the early support.v4 libraries from what I can remember. But if you still have issues with this you MUST also read @AlexLockwood 's blog : Fragment Transactions & Activity State Loss Summary from the blog post (but I strongly recommend you to read it) : NEVER commit() transactions after onPause() on pre-Honeycomb, and onStop() on post-Honeycomb Be careful when committing transactions inside Activity lifecycle methods. Use onCreate(), onResumeFragments() and onPostResume() Avoid performing transactions inside asynchronous callback methods Use commitAllowingStateLoss() only as a last resort

I noticed something very interesting. I have in my app the option to open the phone's gallery and the device asks what app to use, there I click on the gray area away from the dialog and saw this issue. I noticed how my activity goes from onPause, onSaveInstanceState back to onResume, it doesn't happen to visit onCreateView. I am doing transactions at onResume. So what I ended up doing is setting a flag being negated onPause, but being true onCreateView. if the flag is true onResume then do onCommit, otherwise commitAllowingStateLoss. I could go on and waste so much time but I wanted to check the lifecycle. I have a device which is sdkversion 23, and I don't get this issue, but I have another one which is 21, and there I see it.

这对我很管用……我自己发现的…希望对你有所帮助!

1)不要有全局的“静态”FragmentManager / FragmentTransaction。

2) onCreate，总是初始化FragmentManager再次!

样本如下:-

public abstract class FragmentController extends AnotherActivity{
protected FragmentManager fragmentManager;
protected FragmentTransaction fragmentTransaction;
protected Bundle mSavedInstanceState;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    mSavedInstanceState = savedInstanceState;
    setDefaultFragments();
}

protected void setDefaultFragments() {
    fragmentManager = getSupportFragmentManager();
    //check if on orientation change.. do not re-add fragments!
    if(mSavedInstanceState == null) {
        //instantiate the fragment manager

        fragmentTransaction = fragmentManager.beginTransaction();

        //the navigation fragments
        NavigationFragment navFrag = new NavigationFragment();
        ToolbarFragment toolFrag = new ToolbarFragment();

        fragmentTransaction.add(R.id.NavLayout, navFrag, "NavFrag");
        fragmentTransaction.add(R.id.ToolbarLayout, toolFrag, "ToolFrag");
        fragmentTransaction.commitAllowingStateLoss();

        //add own fragment to the nav (abstract method)
        setOwnFragment();
    }
}

当我试图在onActivityForResult()方法中显示片段时，我总是得到这个，所以接下来的问题是:

我的活动暂停和停止，这意味着，onSaveInstanceState()已经被调用(对于pre-Honeycomb和post-Honeycomb设备)。 在任何结果的情况下，我使事务显示/隐藏片段，这导致这个IllegalStateException。

接下来我做的是:

增加了确定我想要的动作是否完成的值(例如，从camere - isPhotoTaken中拍摄照片)-它可以是布尔值或整数值，这取决于你需要多少不同的事务。 在重写onResumeFragments()方法中，我检查了我的值，并在我需要的片段事务之后。在这种情况下，commit()没有在onSaveInstanceState之后执行，因为状态是在onResumeFragments()方法中返回的。

我也有同样的问题，经过一天的分析，所有的文章，博客和stackoverflow，我找到了一个简单的解决方案。完全不要使用savedInstanceState，这是一行代码的条件。在片段代码上:

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(null);
    .....

经过研究，这个问题的解决方案是做你的片段提交在onresume。

来源:https://wenchaojames.wordpress.com/2013/01/12/illegalstateexception-from-onactivityresult/