更长的一段时间。

import time
start_time = time.time()
...
e = int(time.time() - start_time)
print('{:02d}:{:02d}:{:02d}'.format(e // 3600, (e % 3600 // 60), e % 60))

将打印

00:03:15

如果超过24小时

25:33:57

这是受到霍夫斯特回答的启发。谢谢你，罗格尔!

您需要导入时间，然后使用time.time()方法来了解当前时间。

import time

start_time=time.time() #taking current time as starting time

#here your code

elapsed_time=time.time()-start_time #again taking current time - starting time 

Time.time()就可以了。

import time

start = time.time()
# run your code
end = time.time()

elapsed = end - start

你可能想看看这个问题，但我认为没有必要。

在编程中，主要有两种测量时间的方法，结果不同:

>>> print(time.process_time()); time.sleep(10); print(time.process_time())
0.11751394000000001
0.11764988400000001  # took  0 seconds and a bit
>>> print(time.perf_counter()); time.sleep(10); print(time.perf_counter())
3972.465770326
3982.468109075       # took 10 seconds and a bit

Processor Time: This is how long this specific process spends actively being executed on the CPU. Sleep, waiting for a web request, or time when only other processes are executed will not contribute to this. Use time.process_time() Wall-Clock Time: This refers to how much time has passed "on a clock hanging on the wall", i.e. outside real time. Use time.perf_counter() time.time() also measures wall-clock time but can be reset, so you could go back in time time.monotonic() cannot be reset (monotonic = only goes forward) but has lower precision than time.perf_counter()

瓦迪姆·申德的反应很棒。你也可以使用一个简单的装饰器，如下所示:

import datetime
def calc_timing(original_function):                            
    def new_function(*args,**kwargs):                        
        start = datetime.datetime.now()                     
        x = original_function(*args,**kwargs)                
        elapsed = datetime.datetime.now()                      
        print("Elapsed Time = {0}".format(elapsed-start))     
        return x                                             
    return new_function()  

@calc_timing
def a_func(*variables):
    print("do something big!")

更长的一段时间。

import time
start_time = time.time()
...
e = int(time.time() - start_time)
print('{:02d}:{:02d}:{:02d}'.format(e // 3600, (e % 3600 // 60), e % 60))

将打印

00:03:15

如果超过24小时

25:33:57

这是受到霍夫斯特回答的启发。谢谢你，罗格尔!