与时间模块在python是可能测量经过的时间?如果是,我该怎么做?

我需要这样做,以便如果光标在小部件中停留了一段时间,就会发生一个事件。


当前回答

在编程中,主要有两种测量时间的方法,结果不同:

>>> print(time.process_time()); time.sleep(10); print(time.process_time())
0.11751394000000001
0.11764988400000001  # took  0 seconds and a bit
>>> print(time.perf_counter()); time.sleep(10); print(time.perf_counter())
3972.465770326
3982.468109075       # took 10 seconds and a bit

Processor Time: This is how long this specific process spends actively being executed on the CPU. Sleep, waiting for a web request, or time when only other processes are executed will not contribute to this. Use time.process_time() Wall-Clock Time: This refers to how much time has passed "on a clock hanging on the wall", i.e. outside real time. Use time.perf_counter() time.time() also measures wall-clock time but can be reset, so you could go back in time time.monotonic() cannot be reset (monotonic = only goes forward) but has lower precision than time.perf_counter()

其他回答

瓦迪姆·申德的反应很棒。你也可以使用一个简单的装饰器,如下所示:

import datetime
def calc_timing(original_function):                            
    def new_function(*args,**kwargs):                        
        start = datetime.datetime.now()                     
        x = original_function(*args,**kwargs)                
        elapsed = datetime.datetime.now()                      
        print("Elapsed Time = {0}".format(elapsed-start))     
        return x                                             
    return new_function()  

@calc_timing
def a_func(*variables):
    print("do something big!")

更长的一段时间。

import time
start_time = time.time()
...
e = int(time.time() - start_time)
print('{:02d}:{:02d}:{:02d}'.format(e // 3600, (e % 3600 // 60), e % 60))

将打印

00:03:15

如果超过24小时

25:33:57

这是受到霍夫斯特回答的启发。谢谢你,罗格尔!

这是一个更新的Vadim Shender的聪明的代码与表格输出:

import collections
import time
from functools import wraps

PROF_DATA = collections.defaultdict(list)

def profile(fn):
    @wraps(fn)
    def with_profiling(*args, **kwargs):
        start_time = time.time()
        ret = fn(*args, **kwargs)
        elapsed_time = time.time() - start_time
        PROF_DATA[fn.__name__].append(elapsed_time)
        return ret
    return with_profiling

Metrics = collections.namedtuple("Metrics", "sum_time num_calls min_time max_time avg_time fname")

def print_profile_data():
    results = []
    for fname, elapsed_times in PROF_DATA.items():
        num_calls = len(elapsed_times)
        min_time = min(elapsed_times)
        max_time = max(elapsed_times)
        sum_time = sum(elapsed_times)
        avg_time = sum_time / num_calls
        metrics = Metrics(sum_time, num_calls, min_time, max_time, avg_time, fname)
        results.append(metrics)
    total_time = sum([m.sum_time for m in results])
    print("\t".join(["Percent", "Sum", "Calls", "Min", "Max", "Mean", "Function"]))
    for m in sorted(results, reverse=True):
        print("%.1f\t%.3f\t%d\t%.3f\t%.3f\t%.3f\t%s" % (100 * m.sum_time / total_time, m.sum_time, m.num_calls, m.min_time, m.max_time, m.avg_time, m.fname))
    print("%.3f Total Time" % total_time)

Time.time()就可以了。

import time

start = time.time()
# run your code
end = time.time()

elapsed = end - start

你可能想看看这个问题,但我认为没有必要。

您需要导入时间,然后使用time.time()方法来了解当前时间。

import time

start_time=time.time() #taking current time as starting time

#here your code

elapsed_time=time.time()-start_time #again taking current time - starting time