它是可能的,在PHP中,在不使用递归或引用的情况下扁平化(bi/multi)维数组?

我只对值感兴趣,所以键可以忽略,我认为在array_map()和array_values()的行。


当前回答

/**
 * For merging values of a multidimensional array into one 
 *
 * $array = [
 *     0 => [
 *         0 => 'a1',
 *         1 => 'b1',
 *         2 => 'c1',
 *         3 => 'd1'
 *     ],
 *     1 => [
 *         0 => 'a2',
 *         1 => 'b2',
 *         2 => 'c2',
 *     ]
 * ];
 *
 * becomes : 
 *
 * $array = [
 *     0 => 'a1',
 *     1 => 'b1',
 *     2 => 'c1',
 *     3 => 'd1',
 *     4 => 'a2',
 *     5 => 'b2',
 *     6 => 'c2',
 *     
 * ]
 */
array_reduce
(
    $multiArray
    , function ($lastItem, $currentItem) {
        $lastItem = $lastItem ?: array();
        return array_merge($lastItem, array_values($currentItem));
    }
);

依据片段

其他回答

我需要用HTML输入格式表示PHP多维数组。

$test = [
    'a' => [
        'b' => [
            'c' => ['a', 'b']
        ]
    ],
    'b' => 'c',
    'c' => [
        'd' => 'e'
    ]
];

$flatten = function ($input, $parent = []) use (&$flatten) {
    $return = [];

    foreach ($input as $k => $v) {
        if (is_array($v)) {
            $return = array_merge($return, $flatten($v, array_merge($parent, [$k])));
        } else {
            if ($parent) {
                $key = implode('][', $parent) . '][' . $k . ']';

                if (substr_count($key, ']') != substr_count($key, '[')) {
                    $key = preg_replace('/\]/', '', $key, 1);
                }
            } else {
                $key = $k;
            }           

            $return[$key] = $v;
        }
    }

    return $return;
};

die(var_dump( $flatten($test) ));

array(4) {
  ["a[b][c][0]"]=>
  string(1) "a"
  ["a[b][c][1]"]=>
  string(1) "b"
  ["b"]=>
  string(1) "c"
  ["c[d]"]=>
  string(1) "e"
}

您可以使用标准PHP库(SPL)来“隐藏”递归。

$a = array(1,2,array(3,4, array(5,6,7), 8), 9);
$it = new RecursiveIteratorIterator(new RecursiveArrayIterator($a));
foreach($it as $v) {
  echo $v, " ";
}

打印

1 2 3 4 5 6 7 8 9 

试试下面这个简单的函数:

function _flatten_array($arr) {
  while ($arr) {
    list($key, $value) = each($arr); 
    is_array($value) ? $arr = $value : $out[$key] = $value;
    unset($arr[$key]);
  }
  return (array)$out;
}

所以从这里:

array (
  'und' => 
  array (
    'profiles' => 
    array (
      0 => 
      array (
        'commerce_customer_address' => 
        array (
          'und' => 
          array (
            0 => 
            array (
              'first_name' => 'First name',
              'last_name' => 'Last name',
              'thoroughfare' => 'Address 1',
              'premise' => 'Address 2',
              'locality' => 'Town/City',
              'administrative_area' => 'County',
              'postal_code' => 'Postcode',
            ),
          ),
        ),
      ),
    ),
  ),
)

你会得到:

array (
  'first_name' => 'First name',
  'last_name' => 'Last name',
  'thoroughfare' => 'Address 1',
  'premise' => 'Address 2',
  'locality' => 'Town/City',
  'administrative_area' => 'County',
  'postal_code' => 'Postcode',
)

任何想要解决这个问题的人;这里有一个选择:

获取具有不同键值配置的数组的数组:

$test_array = array(
    array('test' => 0, 0, 0, 0),
    array(0, 0, 'merp' => array('herp' => 'derp'), 0),
    array(0, 0, 0, 0),
    array(0, 0, 0, 0)
);
$it = new RecursiveIteratorIterator(new RecursiveArrayIterator($test_array));
var_dump( iterator_to_array($it, false) ) ; 

这将只从每个数组中获取值,并返回单个平面数组。

result值的输出:

0 0 0 0 0 0 derp 0 0 0 0 0 0 0 0 0

你可以用茴香酒来做:

 $result = Arrays::flatten($multidimensional);

看到: