我有问题理解如何使用Python电子邮件附件。我已经成功地通过smtplib电子邮件发送了简单的消息。有人能解释一下如何在电子邮件中发送附件吗?我知道网上还有其他的帖子,但作为一个Python初学者,我发现它们很难理解。


当前回答

我知道这是一个老问题,但我认为一定有一种比其他例子更简单的方法来做到这一点,因此我做了一个库,在不污染代码库的情况下干净地解决这个问题。包含附件非常简单:

from redmail import EmailSender
from pathlib import Path

# Configure an email sender
email = EmailSender(
    host="<SMTP HOST>", port=0,
    user_name="me@example.com", password="<PASSWORD>"
)

# Send an email
email.send(
    sender="me@example.com",
    receivers=["you@example.com"],
    subject="An example email"
    attachments={
        "myfile.txt": Path("path/to/a_file.txt"),
        "myfile.html": "<h1>Content of a HTML attachment</h1>"
    }
)

你也可以直接附加字节,Pandas DataFrame(根据键中的文件扩展名转换为格式),Matplotlib图或枕头图像。这个库很可能是你需要一个电子邮件发送者的所有功能(它比附件要多得多)。

如何安装:

pip install redmail

你喜欢怎么用就怎么用。我还写了大量的文档:https://red-mail.readthedocs.io/en/latest/

其他回答

因为这里有很多关于Python 3的答案,但没有一个说明如何使用Python 3.6中经过彻底检查的电子邮件库,这里是从当前电子邮件示例文档中快速复制+粘贴。 (我略去了一些内容,以去除猜测正确MIME类型之类的多余内容。)

以Python >3.5为目标的现代代码不应该再使用email.message.Message API(包括各种MIMEText、MIMEMultipart、MIMEBase等类)或更老的mimetypes。

from email.message import EmailMessage
import smtplib

msg = EmailMessage()
msg["Subject"] = "Our family reunion"
msg["From"] = "me <sender@example.org>"
msg["To"] = "recipient <victim@example.net>"
# definitely don't mess with the .preamble

msg.set_content("Hello, victim! Look at these pictures")

with open("path/to/attachment.png", "rb") as fp:
    msg.add_attachment(
        fp.read(), maintype="image", subtype="png")

# Notice how smtplib now includes a send_message() method
with smtplib.SMTP("localhost") as s:
    s.send_message(msg)

The modern email.message.EmailMessage API is now quite a bit more versatile and logical than the older version of the library. There are still a few kinks around the presentation in the documentation (it's not obvious how to change the Content-Disposition: of an attachment, for example; and the discussion of the policy module is probably too obscure for most newcomers) and fundamentally, you still need to have some sort of idea of what the MIME structure should look like (though the library now finally takes care of a lot of the nitty-gritty around that). Perhaps see What are the "parts" in a multipart email? for a brief introduction.

Using localhost as your SMTP server obviously only works if you actually have an SMTP server running on your local computer. Properly getting email off your system is a fairly complex separate question. For simple requirements, probably use your existing email account and your provider's email server (search for examples of using port 587 with Google, Yahoo, or whatever you have - what exactly works depends somewhat on the provider; some will only support port 465, or legacy port 25 which is however now by and large impossible to use on public-facing servers because of spam filtering).

Gmail版本,使用Python 3.6(请注意,您需要更改Gmail设置,以便能够通过smtp从它发送电子邮件:

import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.application import MIMEApplication
from os.path import basename


def send_mail(send_from: str, subject: str, text: str, 
send_to: list, files= None):

    send_to= default_address if not send_to else send_to

    msg = MIMEMultipart()
    msg['From'] = send_from
    msg['To'] = ', '.join(send_to)  
    msg['Subject'] = subject

    msg.attach(MIMEText(text))

    for f in files or []:
        with open(f, "rb") as fil: 
            ext = f.split('.')[-1:]
            attachedfile = MIMEApplication(fil.read(), _subtype = ext)
            attachedfile.add_header(
                'content-disposition', 'attachment', filename=basename(f) )
        msg.attach(attachedfile)


    smtp = smtplib.SMTP(host="smtp.gmail.com", port= 587) 
    smtp.starttls()
    smtp.login(username,password)
    smtp.sendmail(send_from, send_to, msg.as_string())
    smtp.close()

用法:

username = 'my-address@gmail.com'
password = 'top-secret'
default_address = ['my-address2@gmail.com'] 

send_mail(send_from= username,
subject="test",
text="text",
send_to= None,
files= # pass a list with the full filepaths here...
)

要与任何其他电子邮件提供商一起使用,只需更改smtp配置。

下面是Python 3.6及更新版本的更新版本,使用Python标准库中经过大修的电子邮件模块的EmailMessage类。

import mimetypes
import os
import smtplib
from email.message import EmailMessage

username = "user@example.com"
password = "password"
smtp_url = "smtp.example.com"
port = 587


def send_mail(subject: str, send_from: str, send_to: str, message: str, directory: str, filename: str):
    # Create the email message
    msg = EmailMessage()
    msg['Subject'] = subject
    msg['From'] = send_from
    msg['To'] = send_to
    # Set email content
    msg.set_content(message)

    path = directory + filename

    if os.path.exists(path):
        ctype, encoding = mimetypes.guess_type(path)
        if ctype is None or encoding is not None:
            # No guess could be made, or the file is encoded (compressed), so
            # use a generic bag-of-bits type.
            ctype = 'application/octet-stream'
        maintype, subtype = ctype.split('/', 1)
        # Add email attachment
        with open(path, 'rb') as fp:
            msg.add_attachment(fp.read(),
                           maintype=maintype,
                           subtype=subtype,
                           filename=filename)

    smtp = smtplib.SMTP(smtp_url, port)
    smtp.starttls() # for using port 587
    smtp.login(username, password)
    smtp.send_message(msg)
    smtp.quit()

你可以在这里找到更多的例子。

这里目前给出的答案都不能正确地与GMail、Outlook 2016等客户机的文件名中的非ascii符号一起工作,以及其他不支持RFC 2231的客户机(例如,参见这里)。下面的Python 3代码改编自其他一些stackoverflow的答案(对不起,没有保存原始链接)和Python 2.7的odoo/openerp代码(参见ir_mail_server.py)。它可以正确地与GMail和其他设备一起工作,并且还使用SSL。

import smtplib, ssl
from os.path import basename
from email.mime.base import MIMEBase
from mimetypes import guess_type
from email.encoders import encode_base64
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
from email.charset import Charset


def try_coerce_ascii(string_utf8):
    """Attempts to decode the given utf8-encoded string
       as ASCII after coercing it to UTF-8, then return
       the confirmed 7-bit ASCII string.
 
       If the process fails (because the string
       contains non-ASCII characters) returns ``None``.
    """
    try:
        string_utf8.encode('ascii')
    except UnicodeEncodeError:
        return
    return string_utf8


def encode_header_param(param_text):
    """Returns an appropriate RFC 2047 encoded representation of the given
       header parameter value, suitable for direct assignation as the
       param value (e.g. via Message.set_param() or Message.add_header())
       RFC 2822 assumes that headers contain only 7-bit characters,
       so we ensure it is the case, using RFC 2047 encoding when needed.
 
       :param param_text: unicode or utf-8 encoded string with header value
       :rtype: string
       :return: if ``param_text`` represents a plain ASCII string,
                return the same 7-bit string, otherwise returns an
                ASCII string containing the RFC2047 encoded text.
    """
    if not param_text: return ""
    param_text_ascii = try_coerce_ascii(param_text)
    return param_text_ascii if param_text_ascii\
         else Charset('utf8').header_encode(param_text)


smtp_server = '<someserver.com>'
smtp_port = 465  # Default port for SSL
sender_email = '<sender_email@some.com>'
sender_password = '<PASSWORD>'
receiver_emails = ['<receiver_email_1@some.com>', '<receiver_email_2@some.com>']
subject = 'Test message'
message = """\
Hello! This is a test message with attachments.

This message is sent from Python."""

files = ['<path1>/файл1.pdf', '<path2>/файл2.png']


# Create a secure SSL context
context = ssl.create_default_context()

msg = MIMEMultipart()
msg['From'] = sender_email
msg['To'] = COMMASPACE.join(receiver_emails)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject

msg.attach(MIMEText(message))

for f in files:
    mimetype, _ = guess_type(f)
    mimetype = mimetype.split('/', 1)
    with open(f, "rb") as fil:
        part = MIMEBase(mimetype[0], mimetype[1])
        part.set_payload(fil.read())
        encode_base64(part)
    filename_rfc2047 = encode_header_param(basename(f))

    # The default RFC 2231 encoding of Message.add_header() works in Thunderbird but not GMail
    # so we fix it by using RFC 2047 encoding for the filename instead.
    part.set_param('name', filename_rfc2047)
    part.add_header('Content-Disposition', 'attachment', filename=filename_rfc2047)
    msg.attach(part)

with smtplib.SMTP_SSL(smtp_server, smtp_port, context=context) as server:
    server.login(sender_email, sender_password)
    server.sendmail(sender_email, receiver_emails, msg.as_string())

我知道这是一个老问题,但我认为一定有一种比其他例子更简单的方法来做到这一点,因此我做了一个库,在不污染代码库的情况下干净地解决这个问题。包含附件非常简单:

from redmail import EmailSender
from pathlib import Path

# Configure an email sender
email = EmailSender(
    host="<SMTP HOST>", port=0,
    user_name="me@example.com", password="<PASSWORD>"
)

# Send an email
email.send(
    sender="me@example.com",
    receivers=["you@example.com"],
    subject="An example email"
    attachments={
        "myfile.txt": Path("path/to/a_file.txt"),
        "myfile.html": "<h1>Content of a HTML attachment</h1>"
    }
)

你也可以直接附加字节,Pandas DataFrame(根据键中的文件扩展名转换为格式),Matplotlib图或枕头图像。这个库很可能是你需要一个电子邮件发送者的所有功能(它比附件要多得多)。

如何安装:

pip install redmail

你喜欢怎么用就怎么用。我还写了大量的文档:https://red-mail.readthedocs.io/en/latest/