我有问题理解如何使用Python电子邮件附件。我已经成功地通过smtplib电子邮件发送了简单的消息。有人能解释一下如何在电子邮件中发送附件吗?我知道网上还有其他的帖子,但作为一个Python初学者,我发现它们很难理解。
当前回答
我知道这是一个老问题,但我认为一定有一种比其他例子更简单的方法来做到这一点,因此我做了一个库,在不污染代码库的情况下干净地解决这个问题。包含附件非常简单:
from redmail import EmailSender
from pathlib import Path
# Configure an email sender
email = EmailSender(
host="<SMTP HOST>", port=0,
user_name="me@example.com", password="<PASSWORD>"
)
# Send an email
email.send(
sender="me@example.com",
receivers=["you@example.com"],
subject="An example email"
attachments={
"myfile.txt": Path("path/to/a_file.txt"),
"myfile.html": "<h1>Content of a HTML attachment</h1>"
}
)
你也可以直接附加字节,Pandas DataFrame(根据键中的文件扩展名转换为格式),Matplotlib图或枕头图像。这个库很可能是你需要一个电子邮件发送者的所有功能(它比附件要多得多)。
如何安装:
pip install redmail
你喜欢怎么用就怎么用。我还写了大量的文档:https://red-mail.readthedocs.io/en/latest/
其他回答
下面是Python 3.6及更新版本的更新版本,使用Python标准库中经过大修的电子邮件模块的EmailMessage类。
import mimetypes
import os
import smtplib
from email.message import EmailMessage
username = "user@example.com"
password = "password"
smtp_url = "smtp.example.com"
port = 587
def send_mail(subject: str, send_from: str, send_to: str, message: str, directory: str, filename: str):
# Create the email message
msg = EmailMessage()
msg['Subject'] = subject
msg['From'] = send_from
msg['To'] = send_to
# Set email content
msg.set_content(message)
path = directory + filename
if os.path.exists(path):
ctype, encoding = mimetypes.guess_type(path)
if ctype is None or encoding is not None:
# No guess could be made, or the file is encoded (compressed), so
# use a generic bag-of-bits type.
ctype = 'application/octet-stream'
maintype, subtype = ctype.split('/', 1)
# Add email attachment
with open(path, 'rb') as fp:
msg.add_attachment(fp.read(),
maintype=maintype,
subtype=subtype,
filename=filename)
smtp = smtplib.SMTP(smtp_url, port)
smtp.starttls() # for using port 587
smtp.login(username, password)
smtp.send_message(msg)
smtp.quit()
你可以在这里找到更多的例子。
Gmail版本,使用Python 3.6(请注意,您需要更改Gmail设置,以便能够通过smtp从它发送电子邮件:
import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.application import MIMEApplication
from os.path import basename
def send_mail(send_from: str, subject: str, text: str,
send_to: list, files= None):
send_to= default_address if not send_to else send_to
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = ', '.join(send_to)
msg['Subject'] = subject
msg.attach(MIMEText(text))
for f in files or []:
with open(f, "rb") as fil:
ext = f.split('.')[-1:]
attachedfile = MIMEApplication(fil.read(), _subtype = ext)
attachedfile.add_header(
'content-disposition', 'attachment', filename=basename(f) )
msg.attach(attachedfile)
smtp = smtplib.SMTP(host="smtp.gmail.com", port= 587)
smtp.starttls()
smtp.login(username,password)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.close()
用法:
username = 'my-address@gmail.com'
password = 'top-secret'
default_address = ['my-address2@gmail.com']
send_mail(send_from= username,
subject="test",
text="text",
send_to= None,
files= # pass a list with the full filepaths here...
)
要与任何其他电子邮件提供商一起使用,只需更改smtp配置。
这是另一个:
import smtplib
from os.path import basename
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
def send_mail(send_from, send_to, subject, text, files=None,
server="127.0.0.1"):
assert isinstance(send_to, list)
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(MIMEText(text))
for f in files or []:
with open(f, "rb") as fil:
part = MIMEApplication(
fil.read(),
Name=basename(f)
)
# After the file is closed
part['Content-Disposition'] = 'attachment; filename="%s"' % basename(f)
msg.attach(part)
smtp = smtplib.SMTP(server)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.close()
这和第一个例子差不多……但顺便来一下应该更容易些。
from email.mime.multipart import MIMEMultipart
from email.mime.image import MIMEImage
from email.mime.text import MIMEText
import smtplib
msg = MIMEMultipart()
password = "password"
msg['From'] = "from_address"
msg['To'] = "to_address"
msg['Subject'] = "Attached Photo"
msg.attach(MIMEImage(file("abc.jpg").read()))
file = "file path"
fp = open(file, 'rb')
img = MIMEImage(fp.read())
fp.close()
msg.attach(img)
server = smtplib.SMTP('smtp.gmail.com: 587')
server.starttls()
server.login(msg['From'], password)
server.sendmail(msg['From'], msg['To'], msg.as_string())
server.quit()
你也可以在你的电子邮件中指定你想要的附件类型,例如我使用pdf:
def send_email_pdf_figs(path_to_pdf, subject, message, destination, password_path=None):
## credits: http://linuxcursor.com/python-programming/06-how-to-send-pdf-ppt-attachment-with-html-body-in-python-script
from socket import gethostname
#import email
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import smtplib
import json
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
with open(password_path) as f:
config = json.load(f)
server.login('me@gmail.com', config['password'])
# Craft message (obj)
msg = MIMEMultipart()
message = f'{message}\nSend from Hostname: {gethostname()}'
msg['Subject'] = subject
msg['From'] = 'me@gmail.com'
msg['To'] = destination
# Insert the text to the msg going by e-mail
msg.attach(MIMEText(message, "plain"))
# Attach the pdf to the msg going by e-mail
with open(path_to_pdf, "rb") as f:
#attach = email.mime.application.MIMEApplication(f.read(),_subtype="pdf")
attach = MIMEApplication(f.read(),_subtype="pdf")
attach.add_header('Content-Disposition','attachment',filename=str(path_to_pdf))
msg.attach(attach)
# send msg
server.send_message(msg)
灵感/信用:http://linuxcursor.com/python-programming/06-how-to-send-pdf-ppt- attachment-html -body-in-python脚本
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