您可能正在寻找delete关键字。

var obj = { };
obj.theProperty = 1;
delete obj.theProperty;

来piggypack本的回答如何解决这个问题使用lodash的_。pickBy，你也可以在姐妹库中解决这个问题:Underscore.js的_.pick。

var obj = {name: 'John', age: null};

var compacted = _.pick(obj, function(value) {
  return value !== null && value !== undefined;
});

参见:JSFiddle示例

递归地删除null, undefined，空对象和空数组，返回一个副本(ES6版本)

export function skipEmpties(dirty) {
    let item;
    if (Array.isArray(dirty)) {
        item = dirty.map(x => skipEmpties(x)).filter(value => value !== undefined);
        return item.length ? item : undefined;
    } else if (dirty && typeof dirty === 'object') {
        item = {};
        Object.keys(dirty).forEach(key => {
            const value = skipEmpties(dirty[key]);
            if (value !== undefined) {
                item[key] = value;
            }
        });
        return Object.keys(item).length ? item : undefined;
    } else {
        return dirty === null ? undefined : dirty;
    }
}

Lodash:

_.omitBy({a: 1, b: null}, (v) => !v)

下面是一个使用ES6从对象中删除null值的函数式方法，而不需要只使用reduce来改变对象:

const stripNulls = (obj) => {
  return Object.keys(obj).reduce((acc, current) => {
    if (obj[current] !== null) {
      return { ...acc, [current]: obj[current] }
    }
    return acc
  }, {})
}

这是另一种选择

打字稿:

function objectDefined <T>(obj: T): T {
  const acc: Partial<T> = {};
  for (const key in obj) {
    if (obj[key] !== undefined) acc[key] = obj[key];
  }
  return acc as T;
}

Javascript:

function objectDefined(obj) {
  const acc = {};
  for (const key in obj) {
    if (obj[key] !== undefined) acc[key] = obj[key];
  }
  return acc;
}