人们使用什么技巧来管理交互式R会话的可用内存?我使用下面的函数[基于Petr Pikal和David Hinds在2004年发布的r-help列表]来列出(和/或排序)最大的对象,并偶尔rm()其中一些对象。但到目前为止最有效的解决办法是……在64位Linux下运行,有充足的内存。

大家还有什么想分享的妙招吗?请每人寄一份。

# improved list of objects
.ls.objects <- function (pos = 1, pattern, order.by,
                        decreasing=FALSE, head=FALSE, n=5) {
    napply <- function(names, fn) sapply(names, function(x)
                                         fn(get(x, pos = pos)))
    names <- ls(pos = pos, pattern = pattern)
    obj.class <- napply(names, function(x) as.character(class(x))[1])
    obj.mode <- napply(names, mode)
    obj.type <- ifelse(is.na(obj.class), obj.mode, obj.class)
    obj.size <- napply(names, object.size)
    obj.dim <- t(napply(names, function(x)
                        as.numeric(dim(x))[1:2]))
    vec <- is.na(obj.dim)[, 1] & (obj.type != "function")
    obj.dim[vec, 1] <- napply(names, length)[vec]
    out <- data.frame(obj.type, obj.size, obj.dim)
    names(out) <- c("Type", "Size", "Rows", "Columns")
    if (!missing(order.by))
        out <- out[order(out[[order.by]], decreasing=decreasing), ]
    if (head)
        out <- head(out, n)
    out
}
# shorthand
lsos <- function(..., n=10) {
    .ls.objects(..., order.by="Size", decreasing=TRUE, head=TRUE, n=n)
}

当前回答

确保在可重复的脚本中记录您的工作。不时地重新打开R,然后source()您的脚本。您将清除不再使用的任何东西,作为一个额外的好处,您将测试您的代码。

其他回答

Tip for dealing with objects requiring heavy intermediate calculation: When using objects that require a lot of heavy calculation and intermediate steps to create, I often find it useful to write a chunk of code with the function to create the object, and then a separate chunk of code that gives me the option either to generate and save the object as an rmd file, or load it externally from an rmd file I have already previously saved. This is especially easy to do in R Markdown using the following code-chunk structure.

```{r Create OBJECT}

COMPLICATED.FUNCTION <- function(...) { Do heavy calculations needing lots of memory;
                                        Output OBJECT; }

```
```{r Generate or load OBJECT}

LOAD <- TRUE
SAVE <- TRUE
#NOTE: Set LOAD to TRUE if you want to load saved file
#NOTE: Set LOAD to FALSE if you want to generate the object from scratch
#NOTE: Set SAVE to TRUE if you want to save the object externally

if(LOAD) { 
  OBJECT <- readRDS(file = 'MySavedObject.rds') 
} else {
  OBJECT <- COMPLICATED.FUNCTION(x, y, z)
  if (SAVE) { saveRDS(file = 'MySavedObject.rds', object = OBJECT) } }

```

With this code structure, all I need to do is to change LOAD depending on whether I want to generate the object, or load it directly from an existing saved file. (Of course, I have to generate it and save it the first time, but after this I have the option of loading it.) Setting LOAD <- TRUE bypasses use of my complicated function and avoids all of the heavy computation therein. This method still requires enough memory to store the object of interest, but it saves you from having to calculate it each time you run your code. For objects that require a lot of heavy calculation of intermediate steps (e.g., for calculations involving loops over large arrays) this can save a substantial amount of time and computation.

请注意这些数据。table包的tables()似乎是Dirk的.ls.objects()自定义函数的一个很好的替代品(在前面的回答中有详细说明),尽管只是针对data.frames/tables,而不是矩阵,数组,列表。

在将数据框架传递给回归函数的data=参数时,我积极地使用子集参数,只选择所需的变量。如果我忘记向公式和select=向量添加变量,确实会导致一些错误,但由于减少了对象的复制,它仍然节省了大量时间,并显著减少了内存占用。假设我有400万条记录和110个变量(我确实有)。例子:

# library(rms); library(Hmisc) for the cph,and rcs functions
Mayo.PrCr.rbc.mdl <- 
cph(formula = Surv(surv.yr, death) ~ age + Sex + nsmkr + rcs(Mayo, 4) + 
                                     rcs(PrCr.rat, 3) +  rbc.cat * Sex, 
     data = subset(set1HLI,  gdlab2 & HIVfinal == "Negative", 
                           select = c("surv.yr", "death", "PrCr.rat", "Mayo", 
                                      "age", "Sex", "nsmkr", "rbc.cat")
   )            )

通过设置上下文和策略:gdlab2变量是一个逻辑向量,它是为一组实验室测试的所有正常或几乎正常值的数据集中的主题构建的,而HIVfinal是一个字符向量,总结了艾滋病毒的初步和确认测试。

Rm (list=ls())是一种让你保持诚实和保持事物可重复性的好方法。

基于@德克和@托尼的回答,我做了一个小小的更新。结果是在漂亮的大小值之前输出[1],所以我取出了捕获。解决问题的输出:

.ls.objects <- function (pos = 1, pattern, order.by,
                     decreasing=FALSE, head=FALSE, n=5) {
napply <- function(names, fn) sapply(names, function(x)
    fn(get(x, pos = pos)))
names <- ls(pos = pos, pattern = pattern)
obj.class <- napply(names, function(x) as.character(class(x))[1])
obj.mode <- napply(names, mode)
obj.type <- ifelse(is.na(obj.class), obj.mode, obj.class)
obj.prettysize <- napply(names, function(x) {
    format(utils::object.size(x),  units = "auto") })
obj.size <- napply(names, utils::object.size)

obj.dim <- t(napply(names, function(x)
    as.numeric(dim(x))[1:2]))
vec <- is.na(obj.dim)[, 1] & (obj.type != "function")
obj.dim[vec, 1] <- napply(names, length)[vec]
out <- data.frame(obj.type, obj.size, obj.prettysize, obj.dim)
names(out) <- c("Type", "Size", "PrettySize", "Rows", "Columns")
if (!missing(order.by))
    out <- out[order(out[[order.by]], decreasing=decreasing), ]
if (head)
    out <- head(out, n)

return(out)
}

# shorthand
lsos <- function(..., n=10) {
    .ls.objects(..., order.by="Size", decreasing=TRUE, head=TRUE, n=n)
}

lsos()