我如何找到一个Bash脚本位于该脚本内部的目录的路径?

我想用Bash脚本作为另一个应用程序的启动器,我想将工作目录更改为Bash脚本所在的目录,所以我可以在该目录中的文件上运行,如下:

$ ./application

当前回答

dirname ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}

如果您想跟随同步链接,请使用您上面的路径上的阅读链接,重复或非重复。

#
# Location: test1/test2/test_script.sh
#
echo $0
echo $_
echo ${BASH_SOURCE}
echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}

cur_file="${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}"
cur_dir="$(dirname "${cur_file}")"
source "${cur_dir}/func_def.sh"

function test_within_func_inside {
    echo ${BASH_SOURCE}
    echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
}

echo "Testing within function inside"
test_within_func_inside

echo "Testing within function outside"
test_within_func_outside

#
# Location: test1/test2/func_def.sh
#
function test_within_func_outside {
    echo ${BASH_SOURCE}
    echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
}

BASH - 来源

一个序列变量,其成员是源文件名,在 FUNCNAME序列变量中定义了相应的序列函数名称。

功能

这个变量可以使用 BASH_LINENO 和 BASH_SOURCE. FUNCNAME 的每个元素都有相应的元素在 BASH_LINENO 和 BASH_SOURCE 描述呼叫板. 例如, ${FUNCNAME[$i]} 被呼叫从文件 ${BASH_SOURCE[$i+1]} 到线号 ${BASH_LINENO[$i]}。

(源:Bash手册)

其他回答

我用三种不同的处决尝试了追踪。

echo $(实际上是 $_)

. application         # /correct/path/to/dir or /path/to/temporary_dir
bash application      # /path/to/bash
/PATH/TO/application  # /correct/path/to/dir

echo $(相当于 $(相当于 $0))

. application         # failed with `realpath: missing operand`
bash application      # /correct/path/to/dir
/PATH/TO/application  # /correct/path/to/dir

echo $(相当于 $BASH_SOURCE)

$BASH_SOURCE 基本上与 ${BASH_SOURCE[0]} 相同。

. application         # /correct/path/to/dir
bash application      # /correct/path/to/dir
/PATH/TO/application  # /correct/path/to/dir

只有$(实际上是$BASH_SOURCE)似乎是可靠的。

dirname ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}

如果您想跟随同步链接,请使用您上面的路径上的阅读链接,重复或非重复。

#
# Location: test1/test2/test_script.sh
#
echo $0
echo $_
echo ${BASH_SOURCE}
echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}

cur_file="${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}"
cur_dir="$(dirname "${cur_file}")"
source "${cur_dir}/func_def.sh"

function test_within_func_inside {
    echo ${BASH_SOURCE}
    echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
}

echo "Testing within function inside"
test_within_func_inside

echo "Testing within function outside"
test_within_func_outside

#
# Location: test1/test2/func_def.sh
#
function test_within_func_outside {
    echo ${BASH_SOURCE}
    echo ${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
}

BASH - 来源

一个序列变量,其成员是源文件名,在 FUNCNAME序列变量中定义了相应的序列函数名称。

功能

这个变量可以使用 BASH_LINENO 和 BASH_SOURCE. FUNCNAME 的每个元素都有相应的元素在 BASH_LINENO 和 BASH_SOURCE 描述呼叫板. 例如, ${FUNCNAME[$i]} 被呼叫从文件 ${BASH_SOURCE[$i+1]} 到线号 ${BASH_LINENO[$i]}。

(源:Bash手册)

如果你的Bash脚本是一个同链接,那么这就是如何做到这一点:

#!/usr/bin/env bash

dirn="$(dirname "$0")"
rl="$(readlink "$0")";
exec_dir="$(dirname $(dirname "$rl"))";
my_path="$dirn/$exec_dir";
X="$(cd $(dirname ${my_path}) && pwd)/$(basename ${my_path})"

X 是包含您的 Bash 脚本的目录(原始文件,而不是同链接)。我向上帝发誓这项工作,这是我唯一知道如何正确地做到这一点。

此单行在 Cygwin 上工作,即使脚本已被从 Windows 称为 bash -c <script>:

set mydir="$(cygpath "$(dirname "$0")")"

总结:

FULL_PATH_TO_SCRIPT="$(realpath "${BASH_SOURCE[-1]}")"

# OR, if you do NOT need it to work for **sourced** scripts too:
# FULL_PATH_TO_SCRIPT="$(realpath "$0")"

# OR, depending on which path you want, in case of nested `source` calls
# FULL_PATH_TO_SCRIPT="$(realpath "${BASH_SOURCE[0]}")"

# OR, add `-s` to NOT expand symlinks in the path:
# FULL_PATH_TO_SCRIPT="$(realpath -s "${BASH_SOURCE[-1]}")"

SCRIPT_DIRECTORY="$(dirname "$FULL_PATH_TO_SCRIPT")"
SCRIPT_FILENAME="$(basename "$FULL_PATH_TO_SCRIPT")"

细节:

在很多情况下,所有你需要获得的是你刚刚打电话的脚本的完整路径. 这可以很容易地通过 realpath 实现. 请注意, realpath 是 GNU 核心工具的一部分. 如果你没有它已经安装(它是默认的在 Ubuntu 上),你可以安装它与 sudo apt 更新 && sudo apt 安装核心工具。

#!/bin/bash

# A. Obtain the full path, and expand (walk down) symbolic links
# A.1. `"$0"` works only if the file is **run**, but NOT if it is **sourced**.
# FULL_PATH_TO_SCRIPT="$(realpath "$0")"
# A.2. `"${BASH_SOURCE[-1]}"` works whether the file is sourced OR run, and even
# if the script is called from within another bash function!
# NB: if `"${BASH_SOURCE[-1]}"` doesn't give you quite what you want, use
# `"${BASH_SOURCE[0]}"` instead in order to get the first element from the array.
FULL_PATH_TO_SCRIPT="$(realpath "${BASH_SOURCE[-1]}")"
# B.1. `"$0"` works only if the file is **run**, but NOT if it is **sourced**.
# FULL_PATH_TO_SCRIPT_KEEP_SYMLINKS="$(realpath -s "$0")"
# B.2. `"${BASH_SOURCE[-1]}"` works whether the file is sourced OR run, and even
# if the script is called from within another bash function!
# NB: if `"${BASH_SOURCE[-1]}"` doesn't give you quite what you want, use
# `"${BASH_SOURCE[0]}"` instead in order to get the first element from the array.
FULL_PATH_TO_SCRIPT_KEEP_SYMLINKS="$(realpath -s "${BASH_SOURCE[-1]}")"

# You can then also get the full path to the directory, and the base
# filename, like this:
SCRIPT_DIRECTORY="$(dirname "$FULL_PATH_TO_SCRIPT")"
SCRIPT_FILENAME="$(basename "$FULL_PATH_TO_SCRIPT")"

# Now print it all out
echo "FULL_PATH_TO_SCRIPT = \"$FULL_PATH_TO_SCRIPT\""
echo "SCRIPT_DIRECTORY    = \"$SCRIPT_DIRECTORY\""
echo "SCRIPT_FILENAME     = \"$SCRIPT_FILENAME\""

如果您在脚本中使用“$0”而不是“${BASH_SOURCE[-1]}”,则在运行脚本时,您将获得相同的输出,而不是在提取脚本时,您将获得此不需要的输出:

~/GS/dev/eRCaGuy_hello_world/bash$ . get_script_path.sh 
FULL_PATH_TO_SCRIPT               = "/bin/bash"
SCRIPT_DIRECTORY                  = "/bin"
SCRIPT_FILENAME                   = "bash"

路径与路径之间的区别:

请注意,直路也成功地走下象征性链接来确定并指向他们的目标,而不是指向象征性链接。 如果你不想要这种行为(有时我不),然后添加到上面的直路命令,使该线看起来像这样:

# Obtain the full path, but do NOT expand (walk down) symbolic links; in
# other words: **keep** the symlinks as part of the path!
FULL_PATH_TO_SCRIPT="$(realpath -s "${BASH_SOURCE[-1]}")"

参考:

[我的答案] Unix 和 Linux:确定路径到源头 Shell 脚本