我如何找到一个Bash脚本位于该脚本内部的目录的路径?
我想用Bash脚本作为另一个应用程序的启动器,我想将工作目录更改为Bash脚本所在的目录,所以我可以在该目录中的文件上运行,如下:
$ ./application
我如何找到一个Bash脚本位于该脚本内部的目录的路径?
我想用Bash脚本作为另一个应用程序的启动器,我想将工作目录更改为Bash脚本所在的目录,所以我可以在该目录中的文件上运行,如下:
$ ./application
当前回答
我相信我得到了这个一个,我迟到了派对,但我认为有些人会欣赏它在这里,如果他们通过这个条纹。
#!/bin/sh # dash bash ksh # !zsh (issues). G. Nixon, 12/2013. Public domain.
## 'linkread' or 'fullpath' or (you choose) is a little tool to recursively
## dereference symbolic links (ala 'readlink') until the originating file
## is found. This is effectively the same function provided in stdlib.h as
## 'realpath' and on the command line in GNU 'readlink -f'.
## Neither of these tools, however, are particularly accessible on the many
## systems that do not have the GNU implementation of readlink, nor ship
## with a system compiler (not to mention the requisite knowledge of C).
## This script is written with portability and (to the extent possible, speed)
## in mind, hence the use of printf for echo and case statements where they
## can be substituded for test, though I've had to scale back a bit on that.
## It is (to the best of my knowledge) written in standard POSIX shell, and
## has been tested with bash-as-bin-sh, dash, and ksh93. zsh seems to have
## issues with it, though I'm not sure why; so probably best to avoid for now.
## Particularly useful (in fact, the reason I wrote this) is the fact that
## it can be used within a shell script to find the path of the script itself.
## (I am sure the shell knows this already; but most likely for the sake of
## security it is not made readily available. The implementation of "$0"
## specificies that the $0 must be the location of **last** symbolic link in
## a chain, or wherever it resides in the path.) This can be used for some
## ...interesting things, like self-duplicating and self-modifiying scripts.
## Currently supported are three errors: whether the file specified exists
## (ala ENOENT), whether its target exists/is accessible; and the special
## case of when a sybolic link references itself "foo -> foo": a common error
## for beginners, since 'ln' does not produce an error if the order of link
## and target are reversed on the command line. (See POSIX signal ELOOP.)
## It would probably be rather simple to write to use this as a basis for
## a pure shell implementation of the 'symlinks' util included with Linux.
## As an aside, the amount of code below **completely** belies the amount
## effort it took to get this right -- but I guess that's coding for you.
##===-------------------------------------------------------------------===##
for argv; do :; done # Last parameter on command line, for options parsing.
## Error messages. Use functions so that we can sub in when the error occurs.
recurses(){ printf "Self-referential:\n\t$argv ->\n\t$argv\n" ;}
dangling(){ printf "Broken symlink:\n\t$argv ->\n\t"$(readlink "$argv")"\n" ;}
errnoent(){ printf "No such file: "$@"\n" ;} # Borrow a horrible signal name.
# Probably best not to install as 'pathfull', if you can avoid it.
pathfull(){ cd "$(dirname "$@")"; link="$(readlink "$(basename "$@")")"
## 'test and 'ls' report different status for bad symlinks, so we use this.
if [ ! -e "$@" ]; then if $(ls -d "$@" 2>/dev/null) 2>/dev/null; then
errnoent 1>&2; exit 1; elif [ ! -e "$@" -a "$link" = "$@" ]; then
recurses 1>&2; exit 1; elif [ ! -e "$@" ] && [ ! -z "$link" ]; then
dangling 1>&2; exit 1; fi
fi
## Not a link, but there might be one in the path, so 'cd' and 'pwd'.
if [ -z "$link" ]; then if [ "$(dirname "$@" | cut -c1)" = '/' ]; then
printf "$@\n"; exit 0; else printf "$(pwd)/$(basename "$@")\n"; fi; exit 0
fi
## Walk the symlinks back to the origin. Calls itself recursivly as needed.
while [ "$link" ]; do
cd "$(dirname "$link")"; newlink="$(readlink "$(basename "$link")")"
case "$newlink" in
"$link") dangling 1>&2 && exit 1 ;;
'') printf "$(pwd)/$(basename "$link")\n"; exit 0 ;;
*) link="$newlink" && pathfull "$link" ;;
esac
done
printf "$(pwd)/$(basename "$newlink")\n"
}
## Demo. Install somewhere deep in the filesystem, then symlink somewhere
## else, symlink again (maybe with a different name) elsewhere, and link
## back into the directory you started in (or something.) The absolute path
## of the script will always be reported in the usage, along with "$0".
if [ -z "$argv" ]; then scriptname="$(pathfull "$0")"
# Yay ANSI l33t codes! Fancy.
printf "\n\033[3mfrom/as: \033[4m$0\033[0m\n\n\033[1mUSAGE:\033[0m "
printf "\033[4m$scriptname\033[24m [ link | file | dir ]\n\n "
printf "Recursive readlink for the authoritative file, symlink after "
printf "symlink.\n\n\n \033[4m$scriptname\033[24m\n\n "
printf " From within an invocation of a script, locate the script's "
printf "own file\n (no matter where it has been linked or "
printf "from where it is being called).\n\n"
else pathfull "$@"
fi
其他回答
這是Linux的特點,但你可以使用:
SELF=$(readlink /proc/$$/fd/255)
选择的答案非常好,我把我的解决方案发送给任何人寻找更短的替代方案,这些解决方案仍然涉及来源、执行、完整路径、相对路径和同步链接,最后,这将在 macOS 上工作,因为不能假设GNU的核心路径的阅读链接版本可用。
GOTCHA是它不使用Bash,但它很容易在Bash脚本中使用,虽然OP没有在解决方案的语言上设置任何限制,但它可能是最好的,大多数人已经留在Bash世界中。
PHP 可在 macOS 默认情况下,并安装在其他平台上,但不一定是默认情况下. 我意识到这是一个缺点,但我会留下这个在这里,任何人来自搜索引擎,无论如何。
export SOURCE_DIRECTORY="$(php -r 'echo dirname(realpath($argv[1]));' -- "${BASH_SOURCE[0]}")"
还有另一个选项:
SELF=$(SELF=$(dirname "$0") && bash -c "cd \"$SELF\" && pwd")
echo "$SELF"
它在 macOS 上也起作用,确定了频道路径,并且不会改变当前的目录。
最短、最优雅的方式就是:
#!/bin/bash
DIRECTORY=$(cd `dirname $0` && pwd)
echo $DIRECTORY
它会在所有平台上工作,而且非常干净。
更多详细信息可在“该 bash 脚本在哪个目录?”中找到。
最高答案在所有情况下都没有工作......
因此,让我们看看一个例子,这些替代的解决方案,为描述的任务,询问到一个特定的文件的真正绝对路径:
PATH_TO_SCRIPT=`realpath -s $0`
PATH_TO_SCRIPT_DIR=`dirname $PATH_TO_SCRIPT`
但最好你应该使用这个先进的版本,也支持使用路径与空间(或可能甚至一些其他特殊的字符):
PATH_TO_SCRIPT=`realpath -s "$0"`
PATH_TO_SCRIPT_DIR=`dirname "$PATH_TO_SCRIPT"`