假设这个字符串:
The fox jumped over the log.
变成:
The fox jumped over the log.
在不分割和进入列表的情况下,最简单的实现方法(1-2行)是什么?
假设这个字符串:
The fox jumped over the log.
变成:
The fox jumped over the log.
在不分割和进入列表的情况下,最简单的实现方法(1-2行)是什么?
当前回答
import re
string = re.sub('[ \t\n]+', ' ', 'The quick brown \n\n \t fox')
这将删除所有的制表符,新行和多个空白与单一空白。
其他回答
string = 'This is a string full of spaces and taps'
string = string.split(' ')
while '' in string:
string.remove('')
string = ' '.join(string)
print(string)
结果:
这是一个充满空格和点击的字符串
>>> import re
>>> re.sub(' +', ' ', 'The quick brown fox')
'The quick brown fox'
令人惊讶的是,没有人发布一个简单的函数,它会比所有其他发布的解决方案快得多。是这样的:
def compactSpaces(s):
os = ""
for c in s:
if c != " " or (os and os[-1] != " "):
os += c
return os
import re
Text = " You can select below trims for removing white space!! BR Aliakbar "
# trims all white spaces
print('Remove all space:',re.sub(r"\s+", "", Text), sep='')
# trims left space
print('Remove leading space:', re.sub(r"^\s+", "", Text), sep='')
# trims right space
print('Remove trailing spaces:', re.sub(r"\s+$", "", Text), sep='')
# trims both
print('Remove leading and trailing spaces:', re.sub(r"^\s+|\s+$", "", Text), sep='')
# replace more than one white space in the string with one white space
print('Remove more than one space:',re.sub(' +', ' ',Text), sep='')
结果:作为代码
"Remove all space:Youcanselectbelowtrimsforremovingwhitespace!!BRAliakbar"
"Remove leading space:You can select below trims for removing white space!! BR Aliakbar"
"Remove trailing spaces: You can select below trims for removing white space!! BR Aliakbar"
"Remove leading and trailing spaces:You can select below trims for removing white space!! BR Aliakbar"
"Remove more than one space: You can select below trims for removing white space!! BR Aliakbar"
def unPretty(S):
# Given a dictionary, JSON, list, float, int, or even a string...
# return a string stripped of CR, LF replaced by space, with multiple spaces reduced to one.
return ' '.join(str(S).replace('\n', ' ').replace('\r', '').split())