如何将字典的str表示,如下面的字符串,转换为字典?
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
我不喜欢使用eval。我还能用什么?
主要原因是,我同事写的一个类,将所有输入转换为字符串。我没有心情去修改他的课程,去处理这个问题。
如何将字典的str表示,如下面的字符串,转换为字典?
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
我不喜欢使用eval。我还能用什么?
主要原因是,我同事写的一个类,将所有输入转换为字符串。我没有心情去修改他的课程,去处理这个问题。
当前回答
string = "{'server1':'value','server2':'value'}"
#Now removing { and }
s = string.replace("{" ,"")
finalstring = s.replace("}" , "")
#Splitting the string based on , we get key value pairs
list = finalstring.split(",")
dictionary ={}
for i in list:
#Get Key Value pairs separately to store in dictionary
keyvalue = i.split(":")
#Replacing the single quotes in the leading.
m= keyvalue[0].strip('\'')
m = m.replace("\"", "")
dictionary[m] = keyvalue[1].strip('"\'')
print dictionary
其他回答
不使用任何库(python2):
dict_format_string = "{'1':'one', '2' : 'two'}"
d = {}
elems = filter(str.isalnum,dict_format_string.split("'"))
values = elems[1::2]
keys = elems[0::2]
d.update(zip(keys,values))
注意:由于它有硬编码的分割(“'”)将只适用于数据是“单引号”的字符串。
注2:在python3中,您需要将filter()包装为list()以获取list。
使用json.loads:
>>> import json
>>> h = '{"foo":"bar", "foo2":"bar2"}'
>>> d = json.loads(h)
>>> d
{u'foo': u'bar', u'foo2': u'bar2'}
>>> type(d)
<type 'dict'>
string = "{'server1':'value','server2':'value'}"
#Now removing { and }
s = string.replace("{" ,"")
finalstring = s.replace("}" , "")
#Splitting the string based on , we get key value pairs
list = finalstring.split(",")
dictionary ={}
for i in list:
#Get Key Value pairs separately to store in dictionary
keyvalue = i.split(":")
#Replacing the single quotes in the leading.
m= keyvalue[0].strip('\'')
m = m.replace("\"", "")
dictionary[m] = keyvalue[1].strip('"\'')
print dictionary
你可以使用内置的ast.literal_eval:
>>> import ast
>>> ast.literal_eval("{'muffin' : 'lolz', 'foo' : 'kitty'}")
{'muffin': 'lolz', 'foo': 'kitty'}
这比使用eval更安全。正如它自己的文件所说:
>>> help(ast.literal_eval) Help on function literal_eval in module ast: literal_eval(node_or_string) Safely evaluate an expression node or a string containing a Python expression. The string or node provided may only consist of the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None.
例如:
>>> eval("shutil.rmtree('mongo')")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<string>", line 1, in <module>
File "/opt/Python-2.6.1/lib/python2.6/shutil.py", line 208, in rmtree
onerror(os.listdir, path, sys.exc_info())
File "/opt/Python-2.6.1/lib/python2.6/shutil.py", line 206, in rmtree
names = os.listdir(path)
OSError: [Errno 2] No such file or directory: 'mongo'
>>> ast.literal_eval("shutil.rmtree('mongo')")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/opt/Python-2.6.1/lib/python2.6/ast.py", line 68, in literal_eval
return _convert(node_or_string)
File "/opt/Python-2.6.1/lib/python2.6/ast.py", line 67, in _convert
raise ValueError('malformed string')
ValueError: malformed string
以OP为例:
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
我们可以使用Yaml来处理string中的这种非标准json:
>>> import yaml
>>> s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
>>> s
"{'muffin' : 'lolz', 'foo' : 'kitty'}"
>>> yaml.load(s)
{'muffin': 'lolz', 'foo': 'kitty'}