我有一个varchar列的表，我想找到在这个列中有重复值的所有记录。我可以使用什么查询来查找重复项?
当前回答
SELECT
t.*,
(SELECT COUNT(*) FROM city AS tt WHERE tt.name=t.name) AS count
FROM `city` AS t
WHERE
(SELECT count(*) FROM city AS tt WHERE tt.name=t.name) > 1 ORDER BY count DESC
其他回答
SELECT t.*,(select count(*) from city as tt
where tt.name=t.name) as count
FROM `city` as t
where (
select count(*) from city as tt
where tt.name=t.name
) > 1 order by count desc
用你的表格替换城市。 将name替换为字段名
假设您的表名为TableABC，您想要的列是Col, T1的主键是key。
SELECT a.Key, b.Key, a.Col
FROM TableABC a, TableABC b
WHERE a.Col = b.Col
AND a.Key <> b.Key
与上面的答案相比，这种方法的优点是它给出了Key。
SELECT ColumnA, COUNT( * )
FROM Table
GROUP BY ColumnA
HAVING COUNT( * ) > 1
SELECT DISTINCT a.email FROM `users` a LEFT JOIN `users` b ON a.email = b.email WHERE a.id != b.id;
下面的代码将找到所有使用了不止一次的product_id。每个product_id只能得到一条记录。
SELECT product_id FROM oc_product_reward GROUP BY product_id HAVING count( product_id ) >1
代码取自:http://chandreshrana.blogspot.in/2014/12/find-duplicate-records-based-on-any.html
