我正在寻找一种方法来检测单击事件是否发生在组件之外,如本文所述。jQueryclosest()用于查看单击事件的目标是否将dom元素作为其父元素之一。如果存在匹配项,则单击事件属于其中一个子项,因此不被视为在组件之外。
因此,在我的组件中,我想将一个单击处理程序附加到窗口。当处理程序启动时,我需要将目标与组件的dom子级进行比较。
click事件包含类似“path”的财产,它似乎保存了事件经过的dom路径。我不知道该比较什么,或者如何最好地遍历它,我想肯定有人已经把它放在了一个聪明的效用函数中。。。不
这是我的方法(演示-https://jsfiddle.net/agymay93/4/):
我创建了一个名为WatchClickOutside的特殊组件,它可以像这样使用(我假设JSX语法):
<WatchClickOutside onClickOutside={this.handleClose}>
<SomeDropdownEtc>
</WatchClickOutside>
以下是WatchClickOutside组件的代码:
import React, { Component } from 'react';
export default class WatchClickOutside extends Component {
constructor(props) {
super(props);
this.handleClick = this.handleClick.bind(this);
}
componentWillMount() {
document.body.addEventListener('click', this.handleClick);
}
componentWillUnmount() {
// remember to remove all events to avoid memory leaks
document.body.removeEventListener('click', this.handleClick);
}
handleClick(event) {
const {container} = this.refs; // get container that we'll wait to be clicked outside
const {onClickOutside} = this.props; // get click outside callback
const {target} = event; // get direct click event target
// if there is no proper callback - no point of checking
if (typeof onClickOutside !== 'function') {
return;
}
// if target is container - container was not clicked outside
// if container contains clicked target - click was not outside of it
if (target !== container && !container.contains(target)) {
onClickOutside(event); // clicked outside - fire callback
}
}
render() {
return (
<div ref="container">
{this.props.children}
</div>
);
}
}
这已经有很多答案了,但它们没有解决e.stopPropagation()和阻止单击要关闭的元素之外的react链接的问题。
由于React有自己的人工事件处理程序,您无法将文档用作事件侦听器的基础。在这之前,您需要e.stopPropagation(),因为React使用文档本身。如果改用document.querySelector('body')。您可以防止点击React链接。下面是我如何实现单击外部并关闭的示例。这使用ES6和React 16.3。
import React, { Component } from 'react';
class App extends Component {
constructor(props) {
super(props);
this.state = {
isOpen: false,
};
this.insideContainer = React.createRef();
}
componentWillMount() {
document.querySelector('body').addEventListener("click", this.handleClick, false);
}
componentWillUnmount() {
document.querySelector('body').removeEventListener("click", this.handleClick, false);
}
handleClick(e) {
/* Check that we've clicked outside of the container and that it is open */
if (!this.insideContainer.current.contains(e.target) && this.state.isOpen === true) {
e.preventDefault();
e.stopPropagation();
this.setState({
isOpen: false,
})
}
};
togggleOpenHandler(e) {
e.preventDefault();
this.setState({
isOpen: !this.state.isOpen,
})
}
render(){
return(
<div>
<span ref={this.insideContainer}>
<a href="#open-container" onClick={(e) => this.togggleOpenHandler(e)}>Open me</a>
</span>
<a href="/" onClick({/* clickHandler */})>
Will not trigger a click when inside is open.
</a>
</div>
);
}
}
export default App;
因为对我来说!ref.current.contains(e.target)无法工作,因为ref中包含的DOM元素正在更改,我提出了一个稍微不同的解决方案:
function useClickOutside<T extends HTMLElement>(
element: T | null,
onClickOutside: () => void,
) {
useEffect(() => {
function handleClickOutside(event: MouseEvent) {
const xCoord = event.clientX;
const yCoord = event.clientY;
if (element) {
const { right, x, bottom, y } = element.getBoundingClientRect();
if (xCoord < right && xCoord > x && yCoord < bottom && yCoord > y) {
return;
}
onClickOutside();
}
}
document.addEventListener('click', handleClickOutside);
return () => {
document.removeEventListener('click', handleClickOutside);
};
}, [element, onClickOutside]);
https://stackoverflow.com/a/42234988/9536897解决方案在手机上不起作用。
您可以尝试:
// returns true if the element or one of its parents has the class classname
hasSomeParentTheClass(element, classname) {
if(element.target)
element=element.target;
if (element.className&& element.className.split(" ").indexOf(classname) >= 0) return true;
return (
element.parentNode &&
this.hasSomeParentTheClass(element.parentNode, classname)
);
}
componentDidMount() {
const fthis = this;
$(window).click(function (element) {
if (!fthis.hasSomeParentTheClass(element, "myClass"))
fthis.setState({ pharmacyFocus: null });
});
}
在视图中,将className赋给特定元素。