我如何从字符串变量使用Swift删除最后一个字符?在文档中找不到。
下面是完整的例子:
var expression = "45+22"
expression = expression.substringToIndex(countElements(expression) - 1)
我如何从字符串变量使用Swift删除最后一个字符?在文档中找不到。
下面是完整的例子:
var expression = "45+22"
expression = expression.substringToIndex(countElements(expression) - 1)
当前回答
斯威夫特4
var welcome = "Hello World!"
welcome = String(welcome[..<welcome.index(before:welcome.endIndex)])
or
welcome.remove(at: welcome.index(before: welcome.endIndex))
or
welcome = String(welcome.dropLast())
其他回答
使用新的Substring类型用法:
斯威夫特4:
var before: String = "Hello world!"
var lastCharIndex: Int = before.endIndex
var after:String = String(before[..<lastCharIndex])
print(after) // Hello world
短:
var before: String = "Hello world!"
after = String(before[..<before.endIndex])
print(after) // Hello world
斯威夫特4:
let choppedString = String(theString.dropLast())
在Swift 2中,这样做:
let choppedString = String(theString.characters.dropLast())
我推荐这个链接来了解Swift字符串。
我更喜欢下面的实现,因为我不必担心,即使字符串是空的
let str = "abc"
str.popLast()
// Prints ab
str = ""
str.popLast() // It returns the Character? which is an optional
// Print <emptystring>
import UIKit
var str1 = "Hello, playground"
str1.removeLast()
print(str1)
var str2 = "Hello, playground"
str2.removeLast(3)
print(str2)
var str3 = "Hello, playground"
str3.removeFirst(2)
print(str3)
Output:-
Hello, playgroun
Hello, playgro
llo, playground
使用函数removeAtIndex(i: String.Index)
var s = "abc"
s.removeAtIndex(s.endIndex.predecessor()) // "ab"