我如何从字符串变量使用Swift删除最后一个字符?在文档中找不到。

下面是完整的例子:

var expression = "45+22"
expression = expression.substringToIndex(countElements(expression) - 1)

当前回答

另一种方法如果你想从末尾删除一个或多个字符。

var myStr = "Hello World!"
myStr = (myStr as NSString).substringToIndex((myStr as NSString).length-XX)

其中XX是要删除的字符数。

其他回答

Swift 3:当你想删除尾随字符串:

func replaceSuffix(_ suffix: String, replacement: String) -> String {
    if hasSuffix(suffix) {
        let sufsize = suffix.count < count ? -suffix.count : 0
        let toIndex = index(endIndex, offsetBy: sufsize)
        return substring(to: toIndex) + replacement
    }
    else
    {
        return self
    }
}
import UIKit

var str1 = "Hello, playground"
str1.removeLast()
print(str1)

var str2 = "Hello, playground"
str2.removeLast(3)
print(str2)

var str3 = "Hello, playground"
str3.removeFirst(2)
print(str3)

Output:-
Hello, playgroun
Hello, playgro
llo, playground
var str = "Hello, playground"

extension String {
    var stringByDeletingLastCharacter: String {
        return dropLast(self)
    }
}

println(str.stringByDeletingLastCharacter)   // "Hello, playgroun"

全局的dropLast()函数作用于序列,因此也作用于字符串:

var expression  = "45+22"
expression = dropLast(expression)  // "45+2"

// in Swift 2.0 (according to cromanelli's comment below)
expression = String(expression.characters.dropLast())

函数的作用是:删除字符串的最后一个元素。

var expression = "45+22"
expression = expression.dropLast()