如何在各种语言中实现以下函数?
计算圆周长上的(x,y)点,给定输入值:
半径 角 起源(可选参数,如果语言支持)
如何在各种语言中实现以下函数?
计算圆周长上的(x,y)点,给定输入值:
半径 角 起源(可选参数,如果语言支持)
当前回答
当你有复数的时候谁还需要三角函数
#include <complex.h>
#include <math.h>
#define PI 3.14159265358979323846
typedef complex double Point;
Point point_on_circle ( double radius, double angle_in_degrees, Point centre )
{
return centre + radius * cexp ( PI * I * ( angle_in_degrees / 180.0 ) );
}
其他回答
当你有复数的时候谁还需要三角函数
#include <complex.h>
#include <math.h>
#define PI 3.14159265358979323846
typedef complex double Point;
Point point_on_circle ( double radius, double angle_in_degrees, Point centre )
{
return centre + radius * cexp ( PI * I * ( angle_in_degrees / 180.0 ) );
}
在给定的距离下计算圆周上的点。 相比之下…… 这可能在游戏AI中很有用,当在一个直接路径上移动一个固体物体时。
public static Point DestinationCoordinatesArc(Int32 startingPointX, Int32 startingPointY,
Int32 circleOriginX, Int32 circleOriginY, float distanceToMove,
ClockDirection clockDirection, float radius)
{
// Note: distanceToMove and radius parameters are float type to avoid integer division
// which will discard remainder
var theta = (distanceToMove / radius) * (clockDirection == ClockDirection.Clockwise ? 1 : -1);
var destinationX = circleOriginX + (startingPointX - circleOriginX) * Math.Cos(theta) - (startingPointY - circleOriginY) * Math.Sin(theta);
var destinationY = circleOriginY + (startingPointX - circleOriginX) * Math.Sin(theta) + (startingPointY - circleOriginY) * Math.Cos(theta);
// Round to avoid integer conversion truncation
return new Point((Int32)Math.Round(destinationX), (Int32)Math.Round(destinationY));
}
/// <summary>
/// Possible clock directions.
/// </summary>
public enum ClockDirection
{
[Description("Time moving forwards.")]
Clockwise,
[Description("Time moving moving backwards.")]
CounterClockwise
}
private void ButtonArcDemo_Click(object sender, EventArgs e)
{
Brush aBrush = (Brush)Brushes.Black;
Graphics g = this.CreateGraphics();
var startingPointX = 125;
var startingPointY = 75;
for (var count = 0; count < 62; count++)
{
var point = DestinationCoordinatesArc(
startingPointX: startingPointX, startingPointY: startingPointY,
circleOriginX: 75, circleOriginY: 75,
distanceToMove: 5,
clockDirection: ClockDirection.Clockwise, radius: 50);
g.FillRectangle(aBrush, point.X, point.Y, 1, 1);
startingPointX = point.X;
startingPointY = point.Y;
// Pause to visually observe/confirm clock direction
System.Threading.Thread.Sleep(35);
Debug.WriteLine($"DestinationCoordinatesArc({point.X}, {point.Y}");
}
}
int x = (int)(radius * Math.Cos(degree * Math.PI / 180F)) + cCenterX;
int y = (int)(radius * Math.Sin(degree * Math.PI / 180F)) + cCenterY;
cCenterX和cCenterY是圆的中心点
圆的参数方程是
x = cx + r * cos(a)
y = cy + r * sin(a)
r是半径,cx cy是原点,a是角度。
这很容易适应任何带有基本三角函数的语言。请注意,大多数语言会在三角函数中使用弧度作为角度,因此,而不是在0..360度,你在0。2π弧度。
我在c#中的实现:
public static PointF PointOnCircle(float radius, float angleInDegrees, PointF origin)
{
// Convert from degrees to radians via multiplication by PI/180
float x = (float)(radius * Math.Cos(angleInDegrees * Math.PI / 180F)) + origin.X;
float y = (float)(radius * Math.Sin(angleInDegrees * Math.PI / 180F)) + origin.Y;
return new PointF(x, y);
}