如何在各种语言中实现以下函数?
计算圆周长上的(x,y)点,给定输入值:
半径 角 起源(可选参数,如果语言支持)
如何在各种语言中实现以下函数?
计算圆周长上的(x,y)点,给定输入值:
半径 角 起源(可选参数,如果语言支持)
当前回答
int x = (int)(radius * Math.Cos(degree * Math.PI / 180F)) + cCenterX;
int y = (int)(radius * Math.Sin(degree * Math.PI / 180F)) + cCenterY;
cCenterX和cCenterY是圆的中心点
其他回答
圆的参数方程是
x = cx + r * cos(a)
y = cy + r * sin(a)
r是半径,cx cy是原点,a是角度。
这很容易适应任何带有基本三角函数的语言。请注意,大多数语言会在三角函数中使用弧度作为角度,因此,而不是在0..360度,你在0。2π弧度。
在给定的距离下计算圆周上的点。 相比之下…… 这可能在游戏AI中很有用,当在一个直接路径上移动一个固体物体时。
public static Point DestinationCoordinatesArc(Int32 startingPointX, Int32 startingPointY,
Int32 circleOriginX, Int32 circleOriginY, float distanceToMove,
ClockDirection clockDirection, float radius)
{
// Note: distanceToMove and radius parameters are float type to avoid integer division
// which will discard remainder
var theta = (distanceToMove / radius) * (clockDirection == ClockDirection.Clockwise ? 1 : -1);
var destinationX = circleOriginX + (startingPointX - circleOriginX) * Math.Cos(theta) - (startingPointY - circleOriginY) * Math.Sin(theta);
var destinationY = circleOriginY + (startingPointX - circleOriginX) * Math.Sin(theta) + (startingPointY - circleOriginY) * Math.Cos(theta);
// Round to avoid integer conversion truncation
return new Point((Int32)Math.Round(destinationX), (Int32)Math.Round(destinationY));
}
/// <summary>
/// Possible clock directions.
/// </summary>
public enum ClockDirection
{
[Description("Time moving forwards.")]
Clockwise,
[Description("Time moving moving backwards.")]
CounterClockwise
}
private void ButtonArcDemo_Click(object sender, EventArgs e)
{
Brush aBrush = (Brush)Brushes.Black;
Graphics g = this.CreateGraphics();
var startingPointX = 125;
var startingPointY = 75;
for (var count = 0; count < 62; count++)
{
var point = DestinationCoordinatesArc(
startingPointX: startingPointX, startingPointY: startingPointY,
circleOriginX: 75, circleOriginY: 75,
distanceToMove: 5,
clockDirection: ClockDirection.Clockwise, radius: 50);
g.FillRectangle(aBrush, point.X, point.Y, 1, 1);
startingPointX = point.X;
startingPointY = point.Y;
// Pause to visually observe/confirm clock direction
System.Threading.Thread.Sleep(35);
Debug.WriteLine($"DestinationCoordinatesArc({point.X}, {point.Y}");
}
}
int x = (int)(radius * Math.Cos(degree * Math.PI / 180F)) + cCenterX;
int y = (int)(radius * Math.Sin(degree * Math.PI / 180F)) + cCenterY;
cCenterX和cCenterY是圆的中心点
在JavaScript (ES6)中实现:
/**
* Calculate x and y in circle's circumference
* @param {Object} input - The input parameters
* @param {number} input.radius - The circle's radius
* @param {number} input.angle - The angle in degrees
* @param {number} input.cx - The circle's origin x
* @param {number} input.cy - The circle's origin y
* @returns {Array[number,number]} The calculated x and y
*/
function pointsOnCircle({ radius, angle, cx, cy }){
angle = angle * ( Math.PI / 180 ); // Convert from Degrees to Radians
const x = cx + radius * Math.sin(angle);
const y = cy + radius * Math.cos(angle);
return [ x, y ];
}
用法:
const [ x, y ] = pointsOnCircle({ radius: 100, angle: 180, cx: 150, cy: 150 });
console.log( x, y );
Codepen
/** * Calculate x and y in circle's circumference * @param {Object} input - The input parameters * @param {number} input.radius - The circle's radius * @param {number} input.angle - The angle in degrees * @param {number} input.cx - The circle's origin x * @param {number} input.cy - The circle's origin y * @returns {Array[number,number]} The calculated x and y */ function pointsOnCircle({ radius, angle, cx, cy }){ angle = angle * ( Math.PI / 180 ); // Convert from Degrees to Radians const x = cx + radius * Math.sin(angle); const y = cy + radius * Math.cos(angle); return [ x, y ]; } const canvas = document.querySelector("canvas"); const ctx = canvas.getContext("2d"); function draw( x, y ){ ctx.clearRect( 0, 0, canvas.width, canvas.height ); ctx.beginPath(); ctx.strokeStyle = "orange"; ctx.arc( 100, 100, 80, 0, 2 * Math.PI); ctx.lineWidth = 3; ctx.stroke(); ctx.closePath(); ctx.beginPath(); ctx.fillStyle = "indigo"; ctx.arc( x, y, 6, 0, 2 * Math.PI); ctx.fill(); ctx.closePath(); } let angle = 0; // In degrees setInterval(function(){ const [ x, y ] = pointsOnCircle({ radius: 80, angle: angle++, cx: 100, cy: 100 }); console.log( x, y ); draw( x, y ); document.querySelector("#degrees").innerHTML = angle + "°"; document.querySelector("#points").textContent = x.toFixed() + "," + y.toFixed(); }, 100 ); <p>Degrees: <span id="degrees">0</span></p> <p>Points on Circle (x,y): <span id="points">0,0</span></p> <canvas width="200" height="200" style="border: 1px solid"></canvas>
当你有复数的时候谁还需要三角函数
#include <complex.h>
#include <math.h>
#define PI 3.14159265358979323846
typedef complex double Point;
Point point_on_circle ( double radius, double angle_in_degrees, Point centre )
{
return centre + radius * cexp ( PI * I * ( angle_in_degrees / 180.0 ) );
}