我在一个android应用程序上工作,我有一个可绘制的,我正在从源图像加载。在这个图像上,我想将所有的白色像素转换为不同的颜色,比如蓝色,然后缓存生成的Drawable对象,以便以后使用它。
例如,我有一个20x20的PNG文件,中间有一个白色的圆圈,圆圈之外的一切都是透明的。把白色圆圈变成蓝色并缓存结果的最好方法是什么?如果我想使用源图像来创建几个新的Drawables(比如蓝色、红色、绿色、橙色等),答案会改变吗?
我猜我想在某种程度上使用一个ColorMatrix,但我不确定如何。
我在一个android应用程序上工作,我有一个可绘制的,我正在从源图像加载。在这个图像上,我想将所有的白色像素转换为不同的颜色,比如蓝色,然后缓存生成的Drawable对象,以便以后使用它。
例如,我有一个20x20的PNG文件,中间有一个白色的圆圈,圆圈之外的一切都是透明的。把白色圆圈变成蓝色并缓存结果的最好方法是什么?如果我想使用源图像来创建几个新的Drawables(比如蓝色、红色、绿色、橙色等),答案会改变吗?
我猜我想在某种程度上使用一个ColorMatrix,但我不确定如何。
当前回答
太晚了,但以防有人需要:
fun setDrawableColor(drawable: Drawable, color: Int) :Drawable {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
drawable.colorFilter = BlendModeColorFilter(color, BlendMode.SRC_ATOP)
return drawable
} else {
drawable.setColorFilter(color, PorterDuff.Mode.SRC_ATOP)
return drawable
}
}
其他回答
根据isWorking字段更改可绘制颜色的简短示例。
我的形状xml:
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" >
<solid android:color="@android:color/holo_blue_bright" />
<corners android:radius="30dp" />
<size
android:height="15dp"
android:width="15dp" />
</shape>
我的改变方法:
private Drawable getColoredDrawable(int drawableResId, boolean isworking) {
Drawable d = getResources().getDrawable(R.drawable.shape);
ColorFilter filter = new LightingColorFilter(
isworking ? Color.GREEN : Color.RED,
isworking ? Color.GREEN : Color.RED);
d.setColorFilter(filter);
return d;
}
用法示例:
text1.setCompoundDrawablesWithIntrinsicBounds(getColoredDrawable(R.drawable.shape, isworking()), null, null, null);
查看这个示例代码"ColorMatrixSample.java"
/*
* Copyright (C) 2007 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package com.example.android.apis.graphics;
import com.example.android.apis.R;
import android.app.Activity;
import android.content.Context;
import android.graphics.*;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
public class ColorMatrixSample extends GraphicsActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(new SampleView(this));
}
private static class SampleView extends View {
private Paint mPaint = new Paint(Paint.ANTI_ALIAS_FLAG);
private ColorMatrix mCM = new ColorMatrix();
private Bitmap mBitmap;
private float mSaturation;
private float mAngle;
public SampleView(Context context) {
super(context);
mBitmap = BitmapFactory.decodeResource(context.getResources(),
R.drawable.balloons);
}
private static void setTranslate(ColorMatrix cm, float dr, float dg,
float db, float da) {
cm.set(new float[] {
2, 0, 0, 0, dr,
0, 2, 0, 0, dg,
0, 0, 2, 0, db,
0, 0, 0, 1, da });
}
private static void setContrast(ColorMatrix cm, float contrast) {
float scale = contrast + 1.f;
float translate = (-.5f * scale + .5f) * 255.f;
cm.set(new float[] {
scale, 0, 0, 0, translate,
0, scale, 0, 0, translate,
0, 0, scale, 0, translate,
0, 0, 0, 1, 0 });
}
private static void setContrastTranslateOnly(ColorMatrix cm, float contrast) {
float scale = contrast + 1.f;
float translate = (-.5f * scale + .5f) * 255.f;
cm.set(new float[] {
1, 0, 0, 0, translate,
0, 1, 0, 0, translate,
0, 0, 1, 0, translate,
0, 0, 0, 1, 0 });
}
private static void setContrastScaleOnly(ColorMatrix cm, float contrast) {
float scale = contrast + 1.f;
float translate = (-.5f * scale + .5f) * 255.f;
cm.set(new float[] {
scale, 0, 0, 0, 0,
0, scale, 0, 0, 0,
0, 0, scale, 0, 0,
0, 0, 0, 1, 0 });
}
@Override protected void onDraw(Canvas canvas) {
Paint paint = mPaint;
float x = 20;
float y = 20;
canvas.drawColor(Color.WHITE);
paint.setColorFilter(null);
canvas.drawBitmap(mBitmap, x, y, paint);
ColorMatrix cm = new ColorMatrix();
mAngle += 2;
if (mAngle > 180) {
mAngle = 0;
}
//convert our animated angle [-180...180] to a contrast value of [-1..1]
float contrast = mAngle / 180.f;
setContrast(cm, contrast);
paint.setColorFilter(new ColorMatrixColorFilter(cm));
canvas.drawBitmap(mBitmap, x + mBitmap.getWidth() + 10, y, paint);
setContrastScaleOnly(cm, contrast);
paint.setColorFilter(new ColorMatrixColorFilter(cm));
canvas.drawBitmap(mBitmap, x, y + mBitmap.getHeight() + 10, paint);
setContrastTranslateOnly(cm, contrast);
paint.setColorFilter(new ColorMatrixColorFilter(cm));
canvas.drawBitmap(mBitmap, x, y + 2*(mBitmap.getHeight() + 10),
paint);
invalidate();
}
}
}
有关的API可在此下载:
如果你有一个纯色的可绘制对象,你想把它改成不同的纯色,你可以使用ColorMatrixColorFilter。透明度得以保留。
int iColor = Color.parseColor(color);
int red = (iColor & 0xFF0000) / 0xFFFF;
int green = (iColor & 0xFF00) / 0xFF;
int blue = iColor & 0xFF;
float[] matrix = { 0, 0, 0, 0, red,
0, 0, 0, 0, green,
0, 0, 0, 0, blue,
0, 0, 0, 1, 0 };
ColorFilter colorFilter = new ColorMatrixColorFilter(matrix);
drawable.setColorFilter(colorFilter);
试试这段代码:
ImageView lineColorCode = (ImageView)convertView.findViewById(R.id.line_color_code);
int color = Color.parseColor("#AE6118"); //The color u want
lineColorCode.setColorFilter(color);
当你使用一个库来为你做这件事时,这是非常非常简单的。 试试这个库
你可以这样调用:
Icon.on(holderView).color(R.color.your_color).icon(R.mipmap.your_icon).put();