我的代码工作得很完美:每次单击导航抽屉中的项目时,项目就会被选中。

当然,我想启动应用程序与默认片段(家),但导航抽屉没有选择的项目。如何以编程方式选择该项目?

public class BaseApp extends AppCompatActivity {

    //Defining Variables
    protected String LOGTAG = "LOGDEBUG";
    protected Toolbar toolbar;
    protected NavigationView navigationView;
    protected DrawerLayout drawerLayout;

    private DateManager db = null;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.base_layout);

        navigationView = (NavigationView) findViewById(R.id.navigation_view);


        // set the home/dashboard at startup

        FragmentTransaction fragmentTransaction = getSupportFragmentManager().beginTransaction();
        fragmentTransaction.replace(R.id.frame, new DashboardFragment());
        fragmentTransaction.commit();

        setNavDrawer();
    }

    private void setNavDrawer(){

        // Initializing Toolbar and setting it as the actionbar
        toolbar = (Toolbar) findViewById(R.id.toolbar);
        setSupportActionBar(toolbar);

        //Initializing NavigationView

        //Setting Navigation View Item Selected Listener to handle the item click of the navigation menu
        navigationView.setNavigationItemSelectedListener(new NavigationView.OnNavigationItemSelectedListener() {

            // This method will trigger on item Click of navigation menu
            @Override
            public boolean onNavigationItemSelected(MenuItem menuItem) {


                //Checking if the item is in checked state or not, if not make it in checked state

                // I THINK THAT I NEED EDIT HERE...

                if (menuItem.isChecked()) menuItem.setChecked(false);
                else menuItem.setChecked(true);

                //Closing drawer on item click
                drawerLayout.closeDrawers();


                //Check to see which item was being clicked and perform appropriate action
                switch (menuItem.getItemId()) {    

                    //Replacing the main content with ContentFragment 

                    case R.id.home:

                        DashboardFragment dashboardFragment = new DashboardFragment();
                        FragmentTransaction fragmentTransaction = getSupportFragmentManager().beginTransaction();
                        fragmentTransaction.replace(R.id.frame, dashboardFragment,"DASHBOARD_FRAGMENT");
                        fragmentTransaction.commit();
                        return true;
[...]

我认为我需要在这里进行编辑:

if (menuItem.isChecked()) menuItem.setChecked(false);
                    else menuItem.setChecked(true);

或者在onCreate中在App启动时使用FragmentTransaction。

谢谢你的支持。


当前回答

您可以用下面的一行代码突出显示和选择项目:

navigationView.getMenu().performIdentifierAction(R.id.posts, 0);

来源:https://stackoverflow.com/a/31044917/383761

其他回答

出于某种原因,最好使用ID来查找MenuItem。

drawer.getMenu().findItem(R.id.action_something).setChecked(true);

下面的代码用于选择第一个项目并在菜单中突出显示所选的第一个项目。

onNavigationItemSelected(mNavigationView.getMenu().getItem(0).setChecked(true));

你可以这样做, nav_view.getMenu () .findItem (R.id.menutem) .setChecked(真正的)

最简单的方法是从xml中选择它,如下所示:

<menu>
   <group android:checkableBehavior="single">
         <item
              android:checked="true"
              android:id="@+id/nav_home"
              android:icon="@drawable/nav_home"
              android:title="@string/main_screen_title_home" />

注意这一行android:checked="true"

以下代码将只使菜单项被选中:

navigationView.setCheckedItem (id);

要选择并打开菜单项,请在上面的行后添加以下代码。

onNavigationItemSelected (navigationView.getMenu () .getItem (0));