它很简单，就像这样关闭指定的文本，例如<b>"你的文本在这里:"</b>

<string name="headquarters">"<b>"Headquarters:"</b>" Mooresville, North Carolina, U.S.</string>

结果: 总部:美国北卡罗来纳州穆尔斯维尔

这是我的完整的解决方案，动态字符串值与大小写检查。

/**
 * Makes a portion of String formatted in BOLD.
 *
 * @param completeString       String from which a portion needs to be extracted and formatted.<br> eg. I am BOLD.
 * @param targetStringToFormat Target String value to format. <br>eg. BOLD
 * @param matchCase Match by target character case or not. If true, BOLD != bold
 * @return A string with a portion formatted in BOLD. <br> I am <b>BOLD</b>.
 */
public static SpannableStringBuilder formatAStringPortionInBold(String completeString, String targetStringToFormat, boolean matchCase) {
    //Null complete string return empty
    if (TextUtils.isEmpty(completeString)) {
        return new SpannableStringBuilder("");
    }

    SpannableStringBuilder str = new SpannableStringBuilder(completeString);
    int start_index = 0;

    //if matchCase is true, match exact string
    if (matchCase) {
        if (TextUtils.isEmpty(targetStringToFormat) || !completeString.contains(targetStringToFormat)) {
            return str;
        }

        start_index = str.toString().indexOf(targetStringToFormat);
    } else {
        //else find in lower cases
        if (TextUtils.isEmpty(targetStringToFormat) || !completeString.toLowerCase().contains(targetStringToFormat.toLowerCase())) {
            return str;
        }

        start_index = str.toString().toLowerCase().indexOf(targetStringToFormat.toLowerCase());
    }

    int end_index = start_index + targetStringToFormat.length();
    str.setSpan(new StyleSpan(BOLD), start_index, end_index, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
    return str;
}

如。completeString = "I am BOLD"

情况下,我 if *targetStringToFormat* = "bold" and *matchCase* = true

返回“I am BOLD”(因为BOLD != BOLD)

案例二世 if *targetStringToFormat* = "bold" and *matchCase* = false

返回“I am BOLD”

应用:

myTextView.setText(formatAStringPortionInBold("I am BOLD", "bold", false))

希望有帮助!

val phone = "+45xxxxxx"

val phoneText = "<font color=#757B7F><b>${phone}</b></font>"

val wholeString = requireActivity().resources.getString(R.string.loginwith)+" "+phoneText

正如wtsang02所说，使用HTML是一种昂贵的开销。只使用本地解决方案。如果不需要修改字符串，只需使用SpannableString，而不是SpannableStringBuilder。

String boldText = "id";
String normalText = "name";
SpannableString str = new SpannableString(boldText + normalText);
str.setSpan(new StyleSpan(Typeface.BOLD), 0, boldText.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
textView.setText(str);

根据@mladj0ni的回答，我得到了下面的代码。问题是如果你使用String。格式，它剥离了HTML标记，所以你必须转义strings.xml中的括号符号:

strings.xml:

<string name="welcome_messages">Hello， %1$s!你有&lt;b>%2$d新消息&lt;/b>.</string> .</string> .

code.java:

String unspanned = String.format(Locale.US, "%s%s", getResources().getString(R.string. welcome_messages), 99);

Spanned spanned;
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {
    spanned = Html.fromHtml(unspanned, Html.FROM_HTML_MODE_LEGACY);
} else {
    spanned = Html.fromHtml(unspanned);
}

textView.setText(spanned);

它比SpannableStringBuilder简单。至于性能，如果只显示一个字符串，那么用户不会注意到解析它所花费的额外毫秒。

请在这里查看文档。

这不是最简单的解决方案吗?

<string name="string">Please provide your <b>Name</b> properly</string>

只要使用你想要的字符串:)

结果如下所示:

请填写您的姓名