如果给出格式为YYYYMMDD的出生日期，如何以年计算年龄?是否可以使用Date()函数?
我正在寻找一个比我现在使用的更好的解决方案:
Var dob = '19800810'; var年=数字(dob.)substr (0, 4)); var月=数字(dob.)Substr (4, 2)) - 1; var day =数字(dob.)2) substr(6日); var today = new Date(); var age = today.getFullYear() -年份; if (today.getMonth() < month || (today.getMonth() == month && today.getDate() < day)) { 年龄——; ｝ 警报(年龄);
当前回答
试试这个:
$('#Datepicker').change(function(){
var $bef = $('#Datepicker').val();
var $today = new Date();
var $before = new Date($bef);
var $befores = $before.getFullYear();
var $todays = $today.getFullYear();
var $bmonth = $before.getMonth();
var $tmonth = $today.getMonth();
var $bday = $before.getDate();
var $tday = $today.getDate();
if ($bmonth>$tmonth)
{$('#age').val($todays-$befores);}
if ($bmonth==$tmonth)
{
if ($tday > $bday) {$('#age').val($todays-$befores-1);}
else if ($tday <= $bday) {$('#age').val($todays-$befores);}
}
else if ($bmonth<$tmonth)
{ $('#age').val($todays-$befores-1);}
})
其他回答
我有一个漂亮的答案，虽然它不是我的代码。不幸的是，我忘记了原来的帖子。
function calculateAge(y, m, d) {
var _birth = parseInt("" + y + affixZero(m) + affixZero(d));
var today = new Date();
var _today = parseInt("" + today.getFullYear() + affixZero(today.getMonth() + 1) + affixZero(today.getDate()));
return parseInt((_today - _birth) / 10000);
}
function affixZero(int) {
if (int < 10) int = "0" + int;
return "" + int;
}
var age = calculateAge(1980, 4, 22);
alert(age);
看这个例子，你从这里得到完整的年、月、日信息
function getAge(dateString) {
var today = new Date();
var birthDate = new Date(dateString);
var age = today.getFullYear() - birthDate.getFullYear();
var m = today.getMonth() - birthDate.getMonth();
var da = today.getDate() - birthDate.getDate();
if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) {
age--;
}
if(m<0){
m +=12;
}
if(da<0){
da +=30;
}
return age+" years "+ Math.abs(m) + "months"+ Math.abs(da) + " days";
}
alert('age: ' + getAge("1987/08/31"));
[http://jsfiddle.net/tapos00/2g70ue5y/][1]
下面是我能想到的最简单、最准确的解决方案:
Date.prototype.getAge = function (date) {
if (!date) date = new Date();
return ~~((date.getFullYear() + date.getMonth() / 100
+ date.getDate() / 10000) - (this.getFullYear() +
this.getMonth() / 100 + this.getDate() / 10000));
}
下面是一个考虑每年2月29日至2月28日的例子。
Date.prototype.getAge = function (date) {
if (!date) date = new Date();
var feb = (date.getMonth() == 1 || this.getMonth() == 1);
return ~~((date.getFullYear() + date.getMonth() / 100 +
(feb && date.getDate() == 29 ? 28 : date.getDate())
/ 10000) - (this.getFullYear() + this.getMonth() / 100 +
(feb && this.getDate() == 29 ? 28 : this.getDate())
/ 10000));
}
它甚至适用于负年龄!
如果你需要以月为单位的年龄(天是近似值):
birthDay=28;
birthMonth=7;
birthYear=1974;
var today = new Date();
currentDay=today.getUTCDate();
currentMonth=today.getUTCMonth() + 1;
currentYear=today.getFullYear();
//calculate the age in months:
Age = (currentYear-birthYear)*12 + (currentMonth-birthMonth) + (currentDay-birthDay)/30;
短而准确(但不是超级可读):
let age = (bdate, now = new Date(), then = new Date(bdate)) => now.getFullYear() - then.getFullYear() - (now < new Date(now.getFullYear(), then.getMonth(), then.getDate()));
