短而准确(但不是超级可读):

let age = (bdate, now = new Date(), then = new Date(bdate)) => now.getFullYear() - then.getFullYear() - (now < new Date(now.getFullYear(), then.getMonth(), then.getDate()));

还有另一个解决方案:

/**
 * Calculate age by birth date.
 *
 * @param int birthYear Year as YYYY.
 * @param int birthMonth Month as number from 1 to 12.
 * @param int birthDay Day as number from 1 to 31.
 * @return int
 */
function getAge(birthYear, birthMonth, birthDay) {
  var today = new Date();
  var birthDate = new Date(birthYear, birthMonth-1, birthDay);
  var age = today.getFullYear() - birthDate.getFullYear();
  var m = today.getMonth() - birthDate.getMonth();
  if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) {
    age--;
  }
  return age;
}

我检查了之前展示的例子，它们并不是在所有情况下都有效，因此我自己写了一个脚本。我测试过了，效果很好。

function getAge(birth) {
   var today = new Date();
   var curr_date = today.getDate();
   var curr_month = today.getMonth() + 1;
   var curr_year = today.getFullYear();

   var pieces = birth.split('/');
   var birth_date = pieces[0];
   var birth_month = pieces[1];
   var birth_year = pieces[2];

   if (curr_month == birth_month && curr_date >= birth_date) return parseInt(curr_year-birth_year);
   if (curr_month == birth_month && curr_date < birth_date) return parseInt(curr_year-birth_year-1);
   if (curr_month > birth_month) return parseInt(curr_year-birth_year);
   if (curr_month < birth_month) return parseInt(curr_year-birth_year-1);
}

var age = getAge('18/01/2011');
alert(age);

这对我来说是最优雅的方式:

const getAge = (birthDateString) => { const today = new Date(); const birthDate = new Date(birthDateString); const yearsDifference = today.getFullYear() - birthDate.getFullYear(); 如果( 今天。getmonth () < birthDate.getMonth() || . getmonth ( (today.getMonth() === birthDate.getMonth() && today.getDate() < birthDate.getDate())) ) { 返回yearsDifference - 1; ｝ 返回yearsDifference; }; console.log (getAge (' 2018-03-12 '));

我有一个漂亮的答案，虽然它不是我的代码。不幸的是，我忘记了原来的帖子。

function calculateAge(y, m, d) {
    var _birth = parseInt("" + y + affixZero(m) + affixZero(d));
    var  today = new Date();
    var _today = parseInt("" + today.getFullYear() + affixZero(today.getMonth() + 1) + affixZero(today.getDate()));
    return parseInt((_today - _birth) / 10000);
}
function affixZero(int) {
    if (int < 10) int = "0" + int;
    return "" + int;
}
var age = calculateAge(1980, 4, 22);
alert(age);

我在这里测试的所有答案(大约一半)都认为2000-02-29到2001-02-28是0年，而从2000-02-29到2001-03-01最有可能是1年，即1年零1天。这里有一个getYearDiff函数来修复这个问题。它只适用于d0 < d1:

function getYearDiff(d0, d1) {

    d1 = d1 || new Date();

    var m = d0.getMonth();
    var years = d1.getFullYear() - d0.getFullYear();

    d0.setFullYear(d0.getFullYear() + years);

    if (d0.getMonth() != m) d0.setDate(0);

    return d0 > d1? --years : years;
}