这个解决方案适用于所有的类

Swift 5解决方案:

extension NSObject {
  var className: String {
    return String(describing: type(of: self))
  }

  class var className: String {
    return String(describing: self)
  }
}

用法:

class TextFieldCell: UITableVIewCell {
}

class LoginViewController: UIViewController {
  let cellClassName = TextFieldCell.className
}

你可以像这样使用Swift标准库函数_stdlib_getDemangledTypeName:

let name = _stdlib_getDemangledTypeName(myViewController)

斯威夫特3.0

字符串(描述:MyViewController.self)

斯威夫特5:

方式1:

print("Class: \(String(describing: self)), Function: \(#function), line: \(#line)")

输出:

Class: <Test.ViewController: 0x7ffaabc0a3d0>, Function: viewDidLoad(), line: 15

方式2:

print("Class: \(String(describing: type(of: self))), Function: \(#function), line: \(#line)")

输出:

Class: ViewController, Function: viewDidLoad(), line: 16

来自实例的字符串:

String(describing: self)

类型中的字符串:

String(describing: YourType.self)

例子:

struct Foo {

    // Instance Level
    var typeName: String {
        return String(describing: Foo.self)
    }

    // Instance Level - Alternative Way
    var otherTypeName: String {
        let thisType = type(of: self)
        return String(describing: thisType)
    }

    // Type Level
    static var typeName: String {
        return String(describing: self)
    }

}

Foo().typeName       // = "Foo"
Foo().otherTypeName  // = "Foo"
Foo.typeName         // = "Foo"

用类、结构和enum测试。

试着反映了()。类self或实例dynamicType的摘要。在获取dynamicType之前解开可选项，否则dynamicType是可选包装器。

class SampleClass { class InnerClass{} }
let sampleClassName = reflect(SampleClass.self).summary;
let instance = SampleClass();
let instanceClassName = reflect(instance.dynamicType).summary;
let innerInstance = SampleClass.InnerClass();
let InnerInstanceClassName = reflect(innerInstance.dynamicType).summary.pathExtension;
let tupleArray = [(Int,[String:Int])]();
let tupleArrayTypeName = reflect(tupleArray.dynamicType).summary;

摘要是描述了泛型类型的类路径。要从摘要中获得简单的类名，请尝试此方法。

func simpleClassName( complexClassName:String ) -> String {
    var result = complexClassName;
    var range = result.rangeOfString( "<" );
    if ( nil != range ) { result = result.substringToIndex( range!.startIndex ); }
    range = result.rangeOfString( "." );
    if ( nil != range ) { result = result.pathExtension; }
    return result;
}