一个漂亮的简单的jQuery解决方案:

$("form").bind("keypress", function (e) {
    if (e.keyCode == 13) {
        return false;
    }
});

您可以创建一个JavaScript方法来检查是否按下了Enter键，如果按下了，就停止提交。

<script type="text/javascript">
  function noenter() {
  return !(window.event && window.event.keyCode == 13); }
</script>

只需在submit方法上调用它。

第4.10.22.2节隐式提交的W3C HTML5规范说:

A form element's default button is the first submit button in tree order whose form owner is that form element. If the user agent supports letting the user submit a form implicitly (for example, on some platforms hitting the "enter" key while a text field is focused implicitly submits the form), then doing so for a form whose default button has a defined activation behavior must cause the user agent to run synthetic click activation steps on that default button. Note: Consequently, if the default button is disabled, the form is not submitted when such an implicit submission mechanism is used. (A button has no activation behavior when disabled.)

因此，一种符合标准的禁用表单隐式提交的方法是将禁用的提交按钮作为表单中的第一个提交按钮:

<form action="...">
  <!-- Prevent implicit submission of the form -->
  <button type="submit" disabled style="display: none" aria-hidden="true"></button>

  <!-- ... -->

  <button type="submit">Submit</button>
</form>

这种方法的一个很好的特性是它不需要JavaScript;无论是否启用JavaScript，都需要一个符合标准的web浏览器来防止隐式表单提交。

这将禁用页面上所有表单的输入键，并且不阻止在文本区域输入。

    // disable form submit with enter

    $('form input:not([type="submit"])').keydown((e) => {
        if (e.keyCode === 13) {
            e.preventDefault();
            return false;
        }
        return true;
    });

一个漂亮的简单的jQuery解决方案:

$("form").bind("keypress", function (e) {
    if (e.keyCode == 13) {
        return false;
    }
});

我还不能评论，所以我会发布一个新的答案

接受的答案是ok-ish，但它不是停止提交在numpad进入。至少在当前版本的Chrome中是这样。我不得不改变这个键码条件，然后它工作。

if(event.keyCode == 13 || event.keyCode == 169) {...}