假设我们有一个名为imageFile的自定义类,这个类包含两个属性:

class imageFile  {
    var fileName = String()
    var fileID = Int()
}

很多都存储在一个数组中:

var images : Array = []

var aImage = imageFile()
aImage.fileName = "image1.png"
aImage.fileID = 101
images.append(aImage)

aImage = imageFile()
aImage.fileName = "image1.png"
aImage.fileID = 202
images.append(aImage)

我如何排序的图像数组由'fileID'升序或降序?


当前回答

[为Swift 3更新了sort(by:)]这,利用一个尾随闭包:

images.sorted { $0.fileID < $1.fileID }

根据ASC或DESC分别使用<或>。如果你想修改图像数组,那么使用以下命令:

images.sort { $0.fileID < $1.fileID }

如果你要重复这样做,并且更喜欢定义一个函数,一种方法是:

func sorterForFileIDASC(this:imageFile, that:imageFile) -> Bool {
  return this.fileID < that.fileID
}

然后用as:

images.sort(by: sorterForFileIDASC)

其他回答

首先,将Array声明为类型化数组,以便在迭代时调用方法:

var images : [imageFile] = []

然后你可以简单地做:

斯威夫特2

images.sorted({ $0.fileID > $1.fileID })

斯威夫特3

images.sorted(by: { $0.fileID > $1.fileID })

斯威夫特5

images.sorted { $0.fileId > $1.fileID }

上面的例子按降序给出了结果。

如果您想对自定义对象的原始数组进行排序。在Swift 2.1中有另一种方法

var myCustomerArray = [Customer]()
myCustomerArray.sortInPlace {(customer1:Customer, customer2:Customer) -> Bool in
    customer1.id < customer2.id
}

其中id为整数。您也可以对String属性使用相同的<操作符。

你可以通过下面的例子了解更多关于它的用法: Swift2:附近的顾客

我是这样做的,而且很管用:

var图像=[图像文件]() 图片社。* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

如果你要在多个地方对这个数组排序,让你的数组类型Comparable是有意义的。

class MyImageType: Comparable, Printable {
    var fileID: Int

    // For Printable
    var description: String {
        get {
            return "ID: \(fileID)"
        }
    }

    init(fileID: Int) {
        self.fileID = fileID
    }
}

// For Comparable
func <(left: MyImageType, right: MyImageType) -> Bool {
    return left.fileID < right.fileID
}

// For Comparable
func ==(left: MyImageType, right: MyImageType) -> Bool {
    return left.fileID == right.fileID
}

let one = MyImageType(fileID: 1)
let two = MyImageType(fileID: 2)
let twoA = MyImageType(fileID: 2)
let three = MyImageType(fileID: 3)

let a1 = [one, three, two]

// return a sorted array
println(sorted(a1)) // "[ID: 1, ID: 2, ID: 3]"

var a2 = [two, one, twoA, three]

// sort the array 'in place'
sort(&a2)
println(a2) // "[ID: 1, ID: 2, ID: 2, ID: 3]"

几乎每个人都给出了如何直接,让我来展示一下演变:

你可以使用Array的实例方法:

// general form of closure
images.sortInPlace({ (image1: imageFile, image2: imageFile) -> Bool in return image1.fileID > image2.fileID })

// types of closure's parameters and return value can be inferred by Swift, so they are omitted along with the return arrow (->)
images.sortInPlace({ image1, image2 in return image1.fileID > image2.fileID })

// Single-expression closures can implicitly return the result of their single expression by omitting the "return" keyword
images.sortInPlace({ image1, image2 in image1.fileID > image2.fileID })

// closure's argument list along with "in" keyword can be omitted, $0, $1, $2, and so on are used to refer the closure's first, second, third arguments and so on
images.sortInPlace({ $0.fileID > $1.fileID })

// the simplification of the closure is the same
images = images.sort({ (image1: imageFile, image2: imageFile) -> Bool in return image1.fileID > image2.fileID })
images = images.sort({ image1, image2 in return image1.fileID > image2.fileID })
images = images.sort({ image1, image2 in image1.fileID > image2.fileID })
images = images.sort({ $0.fileID > $1.fileID })

关于排序的工作原理的详细解释,请参见排序函数。