当你滚动时，你可以使用jquery插件“onScreen”来检查元素是否在当前视口中。 当选择器出现在屏幕上时，插件将选择器的":onScreen"设置为true。 这是插件的链接，你可以把它包含在你的项目中。 “http://benpickles.github.io/onScreen/jquery.onscreen.min.js”

你可以试试下面这个适合我的例子。

$(document).scroll(function() {
    if($("#div2").is(':onScreen')) {
        console.log("Element appeared on Screen");
        //do all your stuffs here when element is visible.
    }
    else {
        console.log("Element not on Screen");
        //do all your stuffs here when element is not visible.
    }
});

HTML代码:

<div id="div1" style="width: 400px; height: 1000px; padding-top: 20px; position: relative; top: 45px"></div> <br>
<hr /> <br>
<div id="div2" style="width: 400px; height: 200px"></div>

CSS:

#div1 {
    background-color: red;
}
#div2 {
    background-color: green;
}

我需要检查可滚动DIV容器内元素的可见性

    //p = DIV container scrollable
    //e = element
    function visible_in_container(p, e) {
        var z = p.getBoundingClientRect();
        var r = e.getBoundingClientRect();

        // Check style visiblilty and off-limits
        return e.style.opacity > 0 && e.style.display !== 'none' &&
               e.style.visibility !== 'hidden' &&
               !(r.top > z.bottom || r.bottom < z.top ||
                 r.left > z.right || r.right < z.left);
    }

这是我的纯JavaScript解决方案，如果它隐藏在一个可滚动的容器。

演示在这里(尝试调整窗口的大小)

var visibleY = function(el){
  var rect = el.getBoundingClientRect(), top = rect.top, height = rect.height, 
    el = el.parentNode
  // Check if bottom of the element is off the page
  if (rect.bottom < 0) return false
  // Check its within the document viewport
  if (top > document.documentElement.clientHeight) return false
  do {
    rect = el.getBoundingClientRect()
    if (top <= rect.bottom === false) return false
    // Check if the element is out of view due to a container scrolling
    if ((top + height) <= rect.top) return false
    el = el.parentNode
  } while (el != document.body)
  return true
};

编辑2016-03-26:我已经更新了解决方案，以考虑滚动过去的元素，所以它隐藏在可滚动容器的顶部。 编辑2018-10-08:更新到当滚动到屏幕上方的视图外时处理。

用香草语回答:

function isScrolledIntoView(el) {
    var rect = el.getBoundingClientRect();
    var elemTop = rect.top;
    var elemBottom = rect.bottom;

    // Only completely visible elements return true:
    var isVisible = (elemTop >= 0) && (elemBottom <= window.innerHeight);
    // Partially visible elements return true:
    //isVisible = elemTop < window.innerHeight && elemBottom >= 0;
    return isVisible;
}

我改编了这个简短的jQuery函数扩展，你可以自由使用(MIT许可)。

/**
 * returns true if an element is visible, with decent performance
 * @param [scope] scope of the render-window instance; default: window
 * @returns {boolean}
 */
jQuery.fn.isOnScreen = function(scope){
    var element = this;
    if(!element){
        return;
    }
    var target = $(element);
    if(target.is(':visible') == false){
        return false;
    }
    scope = $(scope || window);
    var top = scope.scrollTop();
    var bot = top + scope.height();
    var elTop = target.offset().top;
    var elBot = elTop + target.height();

    return ((elBot <= bot) && (elTop >= top));
};

唯一的插件一直为我做这件事，是:https://github.com/customd/jquery-visible

我最近将这个插件移植到GWT，因为我不想仅仅为了使用这个插件而添加jquery作为依赖。下面是我的(简单的)端口(只包括我用例所需的功能):

public static boolean isVisible(Element e)
{
    //vp = viewPort, b = bottom, l = left, t = top, r = right
    int vpWidth   = Window.getClientWidth();
    int vpHeight = Window.getClientHeight();


    boolean tViz = ( e.getAbsoluteTop() >= 0 && e.getAbsoluteTop()<  vpHeight);
    boolean bViz = (e.getAbsoluteBottom() >  0 && e.getAbsoluteBottom() <= vpHeight);
    boolean lViz = (e.getAbsoluteLeft() >= 0 && e.getAbsoluteLeft() < vpWidth);
    boolean rViz = (e.getAbsoluteRight()  >  0 && e.getAbsoluteRight()  <= vpWidth);

    boolean vVisible   = tViz && bViz;
    boolean hVisible   = lViz && rViz;

    return hVisible && vVisible;
}