如果你想在另一个div中滚动项目，

function isScrolledIntoView (elem, divID) 

{

    var docViewTop = $('#' + divID).scrollTop();


    var docViewBottom = docViewTop + $('#' + divID).height();

    var elemTop = $(elem).offset().top;
    var elemBottom = elemTop + $(elem).height();

    return ((elemBottom <= docViewBottom) && (elemTop >= docViewTop)); 
}

我在我的应用程序中有这样一个方法，但它不使用jQuery:

/* Get the TOP position of a given element. */
function getPositionTop(element){
    var offset = 0;
    while(element) {
        offset += element["offsetTop"];
        element = element.offsetParent;
    }
    return offset;
}

/* Is a given element is visible or not? */
function isElementVisible(eltId) {
    var elt = document.getElementById(eltId);
    if (!elt) {
        // Element not found.
        return false;
    }
    // Get the top and bottom position of the given element.
    var posTop = getPositionTop(elt);
    var posBottom = posTop + elt.offsetHeight;
    // Get the top and bottom position of the *visible* part of the window.
    var visibleTop = document.body.scrollTop;
    var visibleBottom = visibleTop + document.documentElement.offsetHeight;
    return ((posBottom >= visibleTop) && (posTop <= visibleBottom));
}

编辑:此方法适用于I.E.(至少版本6)。请阅读评论以了解FF的兼容性。

这里有另一个解决方案:

<script type="text/javascript">
$.fn.is_on_screen = function(){
    var win = $(window);
    var viewport = {
        top : win.scrollTop(),
        left : win.scrollLeft()
    };
    viewport.right = viewport.left + win.width();
    viewport.bottom = viewport.top + win.height();

    var bounds = this.offset();
    bounds.right = bounds.left + this.outerWidth();
    bounds.bottom = bounds.top + this.outerHeight();

    return (!(viewport.right < bounds.left || viewport.left > bounds.right ||    viewport.bottom < bounds.top || viewport.top > bounds.bottom));
 };

if( $('.target').length > 0 ) { // if target element exists in DOM
    if( $('.target').is_on_screen() ) { // if target element is visible on screen after DOM loaded
        $('.log').html('<div class="alert alert-success">target element is visible on screen</div>'); // log info       
    } else {
        $('.log').html('<div class="alert">target element is not visible on screen</div>'); // log info
    }
}
$(window).on('scroll', function(){ // bind window scroll event
if( $('.target').length > 0 ) { // if target element exists in DOM
    if( $('.target').is_on_screen() ) { // if target element is visible on screen after DOM loaded
        $('.log').html('<div class="alert alert-success">target element is visible on screen</div>'); // log info
    } else {
        $('.log').html('<div class="alert">target element is not visible on screen</div>'); // log info
    }
}
});
</script>

在JSFiddle中可以看到

一个基于这个答案的例子，检查一个元素是否有75%可见(即小于25%的元素在屏幕之外)。

function isScrolledIntoView(el) {
  // check for 75% visible
  var percentVisible = 0.75;
  var elemTop = el.getBoundingClientRect().top;
  var elemBottom = el.getBoundingClientRect().bottom;
  var elemHeight = el.getBoundingClientRect().height;
  var overhang = elemHeight * (1 - percentVisible);

  var isVisible = (elemTop >= -overhang) && (elemBottom <= window.innerHeight + overhang);
  return isVisible;
}

如果你想在另一个div中滚动项目，

function isScrolledIntoView (elem, divID) 

{

    var docViewTop = $('#' + divID).scrollTop();


    var docViewBottom = docViewTop + $('#' + divID).height();

    var elemTop = $(elem).offset().top;
    var elemBottom = elemTop + $(elem).height();

    return ((elemBottom <= docViewBottom) && (elemTop >= docViewTop)); 
}

jQuery有一个名为inview的插件，它添加了一个新的inview事件。

下面是jQuery插件不使用事件的代码:

$.extend($.expr[':'],{
    inView: function(a) {
        var st = (document.documentElement.scrollTop || document.body.scrollTop),
            ot = $(a).offset().top,
            wh = (window.innerHeight && window.innerHeight < $(window).height()) ? window.innerHeight : $(window).height();
        return ot > st && ($(a).height() + ot) < (st + wh);
    }
});

(function( $ ) {
    $.fn.inView = function() {
        var st = (document.documentElement.scrollTop || document.body.scrollTop),
        ot = $(this).offset().top,
        wh = (window.innerHeight && window.innerHeight < $(window).height()) ? window.innerHeight : $(window).height();

        return ot > st && ($(this).height() + ot) < (st + wh);
    };
})( jQuery );

我在一个叫James的家伙的评论中发现了这一点(http://remysharp.com/2009/01/26/element-in-view-event-plugin/)