我尝试了下面的代码…

string pass = "";
Console.Write("Enter your password: ");
ConsoleKeyInfo key;

do
{
    key = Console.ReadKey(true);

    // Backspace Should Not Work
    if (key.Key != ConsoleKey.Backspace)
    {
        pass += key.KeyChar;
        Console.Write("*");
    }
    else
    {
        Console.Write("\b");
    }
}
// Stops Receving Keys Once Enter is Pressed
while (key.Key != ConsoleKey.Enter);

Console.WriteLine();
Console.WriteLine("The Password You entered is : " + pass);

但是这样的话,退格键在输入密码时就不起作用了。 任何建议吗?


当前回答

控制台。写(“b \ b \”);将从屏幕上删除星号字符,但在else块中没有任何代码可以从传递字符串变量中删除先前输入的字符。

这里是相关的工作代码,应该做你需要的:

var pass = string.Empty;
ConsoleKey key;
do
{
    var keyInfo = Console.ReadKey(intercept: true);
    key = keyInfo.Key;

    if (key == ConsoleKey.Backspace && pass.Length > 0)
    {
        Console.Write("\b \b");
        pass = pass[0..^1];
    }
    else if (!char.IsControl(keyInfo.KeyChar))
    {
        Console.Write("*");
        pass += keyInfo.KeyChar;
    }
} while (key != ConsoleKey.Enter);

其他回答

我对退格做了一些修改

        string pass = "";
        Console.Write("Enter your password: ");
        ConsoleKeyInfo key;

        do
        {
            key = Console.ReadKey(true);

            // Backspace Should Not Work
            if (key.Key != ConsoleKey.Backspace)
            {
                pass += key.KeyChar;
                Console.Write("*");
            }
            else
            {
                pass = pass.Remove(pass.Length - 1);
                Console.Write("\b \b");
            }
        }
        // Stops Receving Keys Once Enter is Pressed
        while (key.Key != ConsoleKey.Enter);

        Console.WriteLine();
        Console.WriteLine("The Password You entered is : " + pass);

下面是我的简单版本。 每次你按下一个键,从控制台删除所有,并绘制尽可能多的'*'作为密码字符串的长度。

int chr = 0;
string pass = "";
const int ENTER = 13;
const int BS = 8;

do
{
   chr = Console.ReadKey().KeyChar;
   Console.Clear(); //imediately clear the char you printed

   //if the char is not 'return' or 'backspace' add it to pass string
   if (chr != ENTER && chr != BS) pass += (char)chr;

   //if you hit backspace remove last char from pass string
   if (chr == BS) pass = pass.Remove(pass.Length-1, 1);

   for (int i = 0; i < pass.Length; i++)
   {
      Console.Write('*');
   }
} 
 while (chr != ENTER);

Console.Write("\n");
Console.Write(pass);

Console.Read(); //just to see the pass

您可以将键附加到一个累加链表中。

当接收到退格键时,从列表中删除最后一个键。

当您接收到enter键时,将列表折叠成字符串并执行其余工作。

采取顶部的答案,以及从其评论的建议,并将其修改为使用SecureString而不是String,测试所有控制键,而不是错误或在密码长度为0时向屏幕写入额外的“*”,我的解决方案是:

public static SecureString getPasswordFromConsole(String displayMessage) {
    SecureString pass = new SecureString();
    Console.Write(displayMessage);
    ConsoleKeyInfo key;

    do {
        key = Console.ReadKey(true);

        // Backspace Should Not Work
        if (!char.IsControl(key.KeyChar)) {
            pass.AppendChar(key.KeyChar);
            Console.Write("*");
        } else {
            if (key.Key == ConsoleKey.Backspace && pass.Length > 0) {
                pass.RemoveAt(pass.Length - 1);
                Console.Write("\b \b");
            }
        }
    }
    // Stops Receving Keys Once Enter is Pressed
    while (key.Key != ConsoleKey.Enter);
    return pass;
}

为此,您应该使用System.Security.SecureString

public SecureString GetPassword()
{
    var pwd = new SecureString();
    while (true)
    {
        ConsoleKeyInfo i = Console.ReadKey(true);
        if (i.Key == ConsoleKey.Enter)
        {
            break;
        }
        else if (i.Key == ConsoleKey.Backspace)
        {
            if (pwd.Length > 0)
            {
                pwd.RemoveAt(pwd.Length - 1);
                Console.Write("\b \b");
            }
        }
        else if (i.KeyChar != '\u0000' ) // KeyChar == '\u0000' if the key pressed does not correspond to a printable character, e.g. F1, Pause-Break, etc
        {
            pwd.AppendChar(i.KeyChar);
            Console.Write("*");
        }
    }
    return pwd;
}