我尝试了下面的代码…

string pass = "";
Console.Write("Enter your password: ");
ConsoleKeyInfo key;

do
{
    key = Console.ReadKey(true);

    // Backspace Should Not Work
    if (key.Key != ConsoleKey.Backspace)
    {
        pass += key.KeyChar;
        Console.Write("*");
    }
    else
    {
        Console.Write("\b");
    }
}
// Stops Receving Keys Once Enter is Pressed
while (key.Key != ConsoleKey.Enter);

Console.WriteLine();
Console.WriteLine("The Password You entered is : " + pass);

但是这样的话,退格键在输入密码时就不起作用了。 任何建议吗?


当前回答

下面是我的简单版本。 每次你按下一个键,从控制台删除所有,并绘制尽可能多的'*'作为密码字符串的长度。

int chr = 0;
string pass = "";
const int ENTER = 13;
const int BS = 8;

do
{
   chr = Console.ReadKey().KeyChar;
   Console.Clear(); //imediately clear the char you printed

   //if the char is not 'return' or 'backspace' add it to pass string
   if (chr != ENTER && chr != BS) pass += (char)chr;

   //if you hit backspace remove last char from pass string
   if (chr == BS) pass = pass.Remove(pass.Length-1, 1);

   for (int i = 0; i < pass.Length; i++)
   {
      Console.Write('*');
   }
} 
 while (chr != ENTER);

Console.Write("\n");
Console.Write(pass);

Console.Read(); //just to see the pass

其他回答

下面是我的简单版本。 每次你按下一个键,从控制台删除所有,并绘制尽可能多的'*'作为密码字符串的长度。

int chr = 0;
string pass = "";
const int ENTER = 13;
const int BS = 8;

do
{
   chr = Console.ReadKey().KeyChar;
   Console.Clear(); //imediately clear the char you printed

   //if the char is not 'return' or 'backspace' add it to pass string
   if (chr != ENTER && chr != BS) pass += (char)chr;

   //if you hit backspace remove last char from pass string
   if (chr == BS) pass = pass.Remove(pass.Length-1, 1);

   for (int i = 0; i < pass.Length; i++)
   {
      Console.Write('*');
   }
} 
 while (chr != ENTER);

Console.Write("\n");
Console.Write(pass);

Console.Read(); //just to see the pass

您可以将键附加到一个累加链表中。

当接收到退格键时,从列表中删除最后一个键。

当您接收到enter键时,将列表折叠成字符串并执行其余工作。

我在shermy的香草c# 3.5 . net解决方案中发现了一个bug,否则它会很有魅力。我还结合了Damian leszczyzynski - Vash的SecureString思想,但如果你喜欢,你可以使用普通字符串。

错误:如果在密码提示期间按退格键,并且当前密码长度为0,则在密码掩码中错误地插入了星号。要修复此错误,请修改以下方法。

    public static string ReadPassword(char mask)
    {
        const int ENTER = 13, BACKSP = 8, CTRLBACKSP = 127;
        int[] FILTERED = { 0, 27, 9, 10 /*, 32 space, if you care */ }; // const


        SecureString securePass = new SecureString();

        char chr = (char)0;

        while ((chr = System.Console.ReadKey(true).KeyChar) != ENTER)
        {
            if (((chr == BACKSP) || (chr == CTRLBACKSP)) 
                && (securePass.Length > 0))
            {
                System.Console.Write("\b \b");
                securePass.RemoveAt(securePass.Length - 1);

            }
            // Don't append * when length is 0 and backspace is selected
            else if (((chr == BACKSP) || (chr == CTRLBACKSP)) && (securePass.Length == 0))
            {
            }

            // Don't append when a filtered char is detected
            else if (FILTERED.Count(x => chr == x) > 0)
            {
            }

            // Append and write * mask
            else
            {
                securePass.AppendChar(chr);
                System.Console.Write(mask);
            }
        }

        System.Console.WriteLine();
        IntPtr ptr = new IntPtr();
        ptr = Marshal.SecureStringToBSTR(securePass);
        string plainPass = Marshal.PtrToStringBSTR(ptr);
        Marshal.ZeroFreeBSTR(ptr);
        return plainPass;
    }

采取顶部的答案,以及从其评论的建议,并将其修改为使用SecureString而不是String,测试所有控制键,而不是错误或在密码长度为0时向屏幕写入额外的“*”,我的解决方案是:

public static SecureString getPasswordFromConsole(String displayMessage) {
    SecureString pass = new SecureString();
    Console.Write(displayMessage);
    ConsoleKeyInfo key;

    do {
        key = Console.ReadKey(true);

        // Backspace Should Not Work
        if (!char.IsControl(key.KeyChar)) {
            pass.AppendChar(key.KeyChar);
            Console.Write("*");
        } else {
            if (key.Key == ConsoleKey.Backspace && pass.Length > 0) {
                pass.RemoveAt(pass.Length - 1);
                Console.Write("\b \b");
            }
        }
    }
    // Stops Receving Keys Once Enter is Pressed
    while (key.Key != ConsoleKey.Enter);
    return pass;
}

读取控制台输入是困难的,你需要处理特殊的键,如Ctrl, Alt,还有光标键和退格/删除。在一些键盘布局中,像瑞典式Ctrl甚至需要输入直接存在于美国键盘上的键。我相信尝试使用“低级”console . readkey (true)来处理这个问题是非常困难的,所以最简单和最健壮的方法是在输入密码时禁用“控制台输入回声”,使用一点WINAPI。

下面的示例是基于从std::cin问题读取密码的答案。

    private enum StdHandle
    {
        Input = -10,
        Output = -11,
        Error = -12,
    }

    private enum ConsoleMode
    {
        ENABLE_ECHO_INPUT = 4
    }

    [DllImport("kernel32.dll", SetLastError = true)]
    private static extern IntPtr GetStdHandle(StdHandle nStdHandle);

    [DllImport("kernel32.dll", SetLastError = true)]
    [return: MarshalAs(UnmanagedType.Bool)]
    private static extern bool GetConsoleMode(IntPtr hConsoleHandle, out int lpMode);

    [DllImport("kernel32.dll", SetLastError = true)]
    [return: MarshalAs(UnmanagedType.Bool)]
    private static extern bool SetConsoleMode(IntPtr hConsoleHandle, int dwMode);

    public static string ReadPassword()
    {
        IntPtr stdInputHandle = GetStdHandle(StdHandle.Input);
        if (stdInputHandle == IntPtr.Zero)
        {
            throw new InvalidOperationException("No console input");
        }

        int previousConsoleMode;
        if (!GetConsoleMode(stdInputHandle , out previousConsoleMode))
        {
            throw new Win32Exception(Marshal.GetLastWin32Error(), "Could not get console mode.");
        }

        // disable console input echo
        if (!SetConsoleMode(stdInputHandle , previousConsoleMode & ~(int)ConsoleMode.ENABLE_ECHO_INPUT))
        {
            throw new Win32Exception(Marshal.GetLastWin32Error(), "Could not disable console input echo.");
        }

        // just read the password using standard Console.ReadLine()
        string password = Console.ReadLine();

        // reset console mode to previous
        if (!SetConsoleMode(stdInputHandle , previousConsoleMode))
        {
            throw new Win32Exception(Marshal.GetLastWin32Error(), "Could not reset console mode.");
        }

        return password;
    }