从HttpResponseMessage获取内容/消息

我试图获得HttpResponseMessage的内容。它应该是:{"message":"Action "不存在!"，"success":false}，但我不知道，如何从HttpResponseMessage中获取它。

HttpClient httpClient = new HttpClient();
HttpResponseMessage response = await httpClient.GetAsync("http://****?action=");
txtBlock.Text = Convert.ToString(response); //wrong!

在这种情况下，txtBlock的值是:

StatusCode: 200, ReasonPhrase: 'OK', Version: 1.1, Content: System.Net.Http.StreamContent, Headers:
{
  Vary: Accept-Encoding
  Keep-Alive: timeout=15, max=100
  Connection: Keep-Alive
  Date: Wed, 10 Apr 2013 20:46:37 GMT
  Server: Apache/2.2.16
  Server: (Debian)
  X-Powered-By: PHP/5.3.3-7+squeeze14
  Content-Length: 55
  Content-Type: text/html
}

当前回答

你可以使用GetStringAsync方法:

var uri = new Uri("http://yoururlhere");
var response = await client.GetStringAsync(uri);

2016-09-05 08:04:53

其他回答

你可以使用GetStringAsync方法:

var uri = new Uri("http://yoururlhere");
var response = await client.GetStringAsync(uri);

2016-09-05 08:04:53

我认为最简单的方法就是把最后一行改成

txtBlock.Text = await response.Content.ReadAsStringAsync(); //right!

这样就不需要引入任何流阅读器，也不需要任何扩展方法。

2015-04-07 10:47:17

鲁迪翁斯塔登的回答

txtBlock.Text = await response.Content.ReadAsStringAsync();

但如果你不想让方法异步，你可以使用

txtBlock.Text = response.Content.ReadAsStringAsync();
txtBlock.Text.Wait();

Wait()很重要，因为我们正在进行异步操作，必须等待任务完成后才能继续。

2018-10-26 12:11:31

你需要调用GetResponse()。

Stream receiveStream = response.GetResponseStream ();
StreamReader readStream = new StreamReader (receiveStream, Encoding.UTF8);
txtBlock.Text = readStream.ReadToEnd();

2013-04-10 20:58:22

截至2022-02年的更新答案:

var stream = httpResponseMessage.Content.ReadAsStream();
var ms = new MemoryStream();
stream.CopyTo(ms);
var responseBodyBytes = ms.ToArray();

2022-02-20 15:16:29

从HttpResponseMessage获取内容/消息

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