是否有一种方法使用SQL列出给定表的所有外键?我知道表名/模式,我可以把它插入。
当前回答
SELECT r.conname
,ct.table_name
,pg_catalog.pg_get_constraintdef(r.oid, true) as condef
FROM pg_catalog.pg_constraint r, information_schema.constraint_table_usage ct
WHERE r.contype = 'f'
AND r.conname = ct.constraint_name
ORDER BY 1
其他回答
SELECT
conrelid::regclass AS table_from,
conname,
pg_get_constraintdef(oid) as condef
FROM pg_catalog.pg_constraint r
也适用于所有约束条件。例如,使用pysql:
正确的解决方案,使用information_schema,使用多列键,在两个表中正确地连接不同名称的列,并且与ms sqlsever兼容:
select fks.TABLE_NAME as foreign_key_table_name
, fks.CONSTRAINT_NAME as foreign_key_constraint_name
, kcu_foreign.COLUMN_NAME as foreign_key_column_name
, rc.UNIQUE_CONSTRAINT_NAME as primary_key_constraint_name
, pks.TABLE_NAME as primary_key_table_name
, kcu_primary.COLUMN_NAME as primary_key_column_name
from INFORMATION_SCHEMA.TABLE_CONSTRAINTS fks -- foreign keys
inner join INFORMATION_SCHEMA.KEY_COLUMN_USAGE kcu_foreign -- the columns of the above keys
on fks.TABLE_CATALOG = kcu_foreign.TABLE_CATALOG
and fks.TABLE_SCHEMA = kcu_foreign.TABLE_SCHEMA
and fks.TABLE_NAME = kcu_foreign.TABLE_NAME
and fks.CONSTRAINT_NAME = kcu_foreign.CONSTRAINT_NAME
inner join INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS rc -- referenced constraints
on rc.CONSTRAINT_CATALOG = fks.CONSTRAINT_CATALOG
and rc.CONSTRAINT_SCHEMA = fks.CONSTRAINT_SCHEMA
and rc.CONSTRAINT_NAME = fks.CONSTRAINT_NAME
inner join INFORMATION_SCHEMA.TABLE_CONSTRAINTS pks -- primary keys (referenced by fks)
on rc.UNIQUE_CONSTRAINT_CATALOG = pks.CONSTRAINT_CATALOG
and rc.UNIQUE_CONSTRAINT_SCHEMA = pks.CONSTRAINT_SCHEMA
and rc.UNIQUE_CONSTRAINT_NAME = pks.CONSTRAINT_NAME
inner join INFORMATION_SCHEMA.KEY_COLUMN_USAGE kcu_primary
on pks.TABLE_CATALOG = kcu_primary.TABLE_CATALOG
and pks.TABLE_SCHEMA = kcu_primary.TABLE_SCHEMA
and pks.TABLE_NAME = kcu_primary.TABLE_NAME
and pks.CONSTRAINT_NAME = kcu_primary.CONSTRAINT_NAME
and kcu_foreign.ORDINAL_POSITION = kcu_primary.ORDINAL_POSITION -- this joins the columns
where fks.TABLE_SCHEMA = 'dbo' -- replace with schema name
and fks.TABLE_NAME = 'your_table_name' -- replace with table name
and fks.CONSTRAINT_TYPE = 'FOREIGN KEY'
and pks.CONSTRAINT_TYPE = 'PRIMARY KEY'
order by fks.constraint_name, kcu_foreign.ORDINAL_POSITION
注意:在potgresql和sqlserver的information_schema实现之间存在一些差异,这使得顶部答案在两个系统上给出不同的结果——一个显示外键表的列名,另一个显示主键表的列名。出于这个原因,我决定使用KEY_COLUMN_USAGE视图。
$1 ('my_schema')是模式,$2 ('my_table')是表名:
SELECT ss.conname constraint_name, a.attname column_name, ss.refnamespace fk_table_schema, ss.reflname fk_table_name, af.attname fk_column_name
FROM pg_attribute a, pg_attribute af,
(SELECT r.oid roid, c.conname, rf.relname reflname, information_schema._pg_expandarray(c.conkey) x,
nrf.nspname refnamespace, rf.oid rfoid, information_schema._pg_expandarray(cf.confkey) xf
FROM pg_namespace nr, pg_class r, pg_constraint c,
pg_namespace nrf, pg_class rf, pg_constraint cf
WHERE nr.oid = r.relnamespace
AND r.oid = c.conrelid
AND rf.oid = cf.confrelid
AND c.conname = cf.conname
AND nrf.oid = rf.relnamespace
AND nr.nspname = $1
AND r.relname = $2) ss
WHERE ss.roid = a.attrelid AND a.attnum = (ss.x).x AND NOT a.attisdropped
AND ss.rfoid = af.attrelid AND af.attnum = (ss.xf).x AND NOT af.attisdropped
ORDER BY ss.conname, a.attname;
你可以使用PostgreSQL系统目录。也许您可以查询pg_constraint来请求外键。 您还可以使用信息模式
只需替换'您的表名'在下面的查询与您的表名。
简短但贴心的赞,如果对你有用的话。
select * from information_schema.key_column_usage
where constraint_catalog=current_catalog and table_name='your_table_name'
and position_in_unique_constraint notnull;
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