如何在Linux系统中将Spring Boot应用程序打包为可执行jar as a Service ?这是推荐的方法吗,还是应该将这个应用程序转换为war并将其安装到Tomcat中?
目前,我可以从屏幕会话运行Spring引导应用程序,这很好,但需要在服务器重新启动后手动启动。
我正在寻找的是一般的建议/方向或样本init。D脚本,如果我的方法与可执行jar是适当的。
如何在Linux系统中将Spring Boot应用程序打包为可执行jar as a Service ?这是推荐的方法吗,还是应该将这个应用程序转换为war并将其安装到Tomcat中?
目前,我可以从屏幕会话运行Spring引导应用程序,这很好,但需要在服务器重新启动后手动启动。
我正在寻找的是一般的建议/方向或样本init。D脚本,如果我的方法与可执行jar是适当的。
当前回答
创建一个名为your-app的脚本。服务(rest-app.service)。 我们应该把这个脚本放在/etc/systemd/system目录下。 下面是脚本的示例内容
[Unit]
Description=Spring Boot REST Application
After=syslog.target
[Service]
User=javadevjournal
ExecStart=/var/rest-app/restdemo.jar
SuccessExitStatus=200
[Install]
WantedBy=multi-user.target
下一个:
service rest-app start
参考文献
在这里输入链接描述
其他回答
Following up on Chad's excellent answer, if you get an error of "Error: Could not find or load main class" - and you spend a couple hours trying to troubleshoot it, whether your executing a shell script that starts your java app or starting it from systemd itself - and you know your classpath is 100% correct, e.g. manually running the shell script works as well as running what you have in systemd execstart. Be sure you're running things as the correct user! In my case, I had tried different users, after quite a while of troubleshooting - i finally had a hunch, put root as the user - voila, the app started correctly. After determining it was a wrong user issue, I chown -R user:user the folder and subfolders and the app ran correctly as the specified user and group so no longer needed to run it as root (bad security).
对于SpringBoot 2.4.4,除了由 @ismael
我在maven pom.xml中有以下内容,使其成为可执行jar
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<configuration>
<executable>true</executable>
</configuration>
<executions>
<execution>
<goals>
<goal>repackage</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
下面是一个脚本,它将可执行jar部署为systemd服务。
它为服务和.service文件创建一个用户,并将jar文件放在/var下,并对特权进行一些基本的锁定。
#!/bin/bash
# Argument: The jar file to deploy
APPSRCPATH=$1
# Argument: application name, no spaces please, used as folder name under /var
APPNAME=$2
# Argument: the user to use when running the application, may exist, created if not exists
APPUSER=$3
# Help text
USAGE="
Usage: sudo $0 <jar-file> <app-name> <runtime-user>
If an app with the name <app-name> already exist, it is stopped and deleted.
If the <runtime-user> does not already exist, it is created.
"
# Check that we are root
if [ ! "root" = "$(whoami)" ]; then
echo "Must be root. Please use e.g. sudo"
echo "$USAGE"
exit
fi
# Check arguments
if [ "$#" -ne 3 -o ${#APPSRCPATH} = 0 -o ${#APPNAME} = 0 -o ${#APPUSER} = 0 ]; then
echo "Incorrect number of parameters."
echo "$USAGE"
exit
fi
if [ ! -f $APPSRCPATH ]; then
echo "Can't find jar file $APPSRCPATH"
echo "$USAGE"
exit
fi
# Infered values
APPFILENAME=$(basename $APPSRCPATH)
APPFOLDER=/var/javaapps/$APPNAME
APPDESTPATH=$APPFOLDER/$APPFILENAME
# Stop the service if it already exist and is running
systemctl stop $APPNAME >/dev/null 2>&1
# Create the app folder, deleting any previous content
rm -fr $APPFOLDER
mkdir -p $APPFOLDER
# Create the user if it does not exist
if id "$APPUSER" >/dev/null 2>&1; then
echo "Using existing user $APPUSER"
else
adduser --disabled-password --gecos "" $APPUSER
echo "Created user $APPUSER"
fi
# Place app in app folder, setting owner and rights
cp $APPSRCPATH $APPDESTPATH
chown $APPUSER $APPDESTPATH
chmod 500 $APPDESTPATH
echo "Added or updated the $APPDESTPATH file"
# Create the .service file used by systemd
echo "
[Unit]
Description=$APPNAME
After=syslog.target
[Service]
User=$APPUSER
ExecStart=/usr/bin/java -jar $APPDESTPATH
SuccessExitStatus=143
[Install]
WantedBy=multi-user.target
" > /etc/systemd/system/$APPNAME.service
echo "Created the /etc/systemd/system/$APPNAME.service file"
# Reload the daemon
systemctl daemon-reload
# Start the deployed app
systemctl start $APPNAME
systemctl status $APPNAME
例子:
在这个问题中,@PbxMan的回答可以让你开始:
在Linux上运行Java应用程序作为服务
编辑:
还有另一种不太好的方式在重启时启动进程,使用cron:
@reboot user-to-run-under /usr/bin/java -jar /path/to/application.jar
这是可行的,但不能为应用程序提供良好的启动/停止界面。你仍然可以简单地杀死它……
作为Windows服务
如果你想在windows机器上运行,请下载winsw.exe
http://repo.jenkins-ci.org/releases/com/sun/winsw/winsw/2.1.2/
之后,将其重命名为jar文件名(例如:your-app.jar)
winsw.exe -> your-app.exe
现在创建一个xml文件your-app.xml,并将以下内容复制到该文件中
<?xml version="1.0" encoding="UTF-8"?>
<service>
<id>your-app</id>
<name>your-app</name>
<description>your-app as a Windows Service</description>
<executable>java</executable>
<arguments>-jar "your-app.jar"</arguments>
<logmode>rotate</logmode>
</service>
确保exe和xml以及jar文件在同一个文件夹中。
在此之后,在管理员权限下打开命令提示符并将其安装到windows服务。
your-app.exe install
eg -> D:\Springboot\your-app.exe install
如果失败了
Error: Registry key 'Software\JavaSoft\Java Runtime Environment'\CurrentVersion' has value '1.8', but '1.7' is required.
然后试试下面的方法:
Delete java.exe, javaw.exe and javaws.exe from C:\Windows\System32
就是这样:).
在windows下卸载服务
your-app.exe uninstall
查看/运行/停止服务: win+r并输入Administrative tools,然后从中选择服务。然后右击选择选项-运行/停止