float(nan')表示nan(不是数字)。但我该如何检查呢?


当前回答

用于浮球类型

>>> import pandas as pd
>>> value = float(nan)
>>> type(value)
>>> <class 'float'>
>>> pd.isnull(value)
True
>>>
>>> value = 'nan'
>>> type(value)
>>> <class 'str'>
>>> pd.isnull(value)
False

其他回答

判断变量是NaN还是None的所有方法:

无类型

In [1]: from numpy import math

In [2]: a = None
In [3]: not a
Out[3]: True

In [4]: len(a or ()) == 0
Out[4]: True

In [5]: a == None
Out[5]: True

In [6]: a is None
Out[6]: True

In [7]: a != a
Out[7]: False

In [9]: math.isnan(a)
Traceback (most recent call last):
  File "<ipython-input-9-6d4d8c26d370>", line 1, in <module>
    math.isnan(a)
TypeError: a float is required

In [10]: len(a) == 0
Traceback (most recent call last):
  File "<ipython-input-10-65b72372873e>", line 1, in <module>
    len(a) == 0
TypeError: object of type 'NoneType' has no len()

NaN类型

In [11]: b = float('nan')
In [12]: b
Out[12]: nan

In [13]: not b
Out[13]: False

In [14]: b != b
Out[14]: True

In [15]: math.isnan(b)
Out[15]: True

如何从混合数据类型列表中删除NaN(float)项

如果在可迭代的中有混合类型,这里有一个不使用numpy的解决方案:

from math import isnan

Z = ['a','b', float('NaN'), 'd', float('1.1024')]

[x for x in Z if not (
                      type(x) == float # let's drop all float values…
                      and isnan(x) # … but only if they are nan
                      )]
['a', 'b', 'd', 1.1024]

短路求值意味着不会对非“float”类型的值调用isnan,因为False和(…)很快求值为False,而无需对右侧求值。

测试NaN的通常方法是查看它是否等于自身:

def isNaN(num):
    return num != num

numpy.isnan(数字)告诉你它是不是NaN。

下面是一个答案:

符合IEEE 754标准的NaN实现例如:python的NaN:float(NaN'),numpy.NaN。。。任何其他对象:string或其他任何对象(遇到异常时不会引发异常)

按照标准实现的NaN是唯一一个与自身的不平等比较应返回True的值:

def is_nan(x):
    return (x != x)

还有一些例子:

import numpy as np
values = [float('nan'), np.nan, 55, "string", lambda x : x]
for value in values:
    print(f"{repr(value):<8} : {is_nan(value)}")

输出:

nan      : True
nan      : True
55       : False
'string' : False
<function <lambda> at 0x000000000927BF28> : False