这个答案似乎并不存在。

directories = [ x for x in os.listdir('.') if os.path.isdir(x) ]

这个答案似乎并不存在。

directories = [ x for x in os.listdir('.') if os.path.isdir(x) ]

这个函数，对于给定的父目录，递归地遍历它的所有目录，并打印它在其中找到的所有文件名。也有用。

import os

def printDirectoryFiles(directory):
   for filename in os.listdir(directory):  
        full_path=os.path.join(directory, filename)
        if not os.path.isdir(full_path): 
            print( full_path + "\n")


def checkFolders(directory):

    dir_list = next(os.walk(directory))[1]

    #print(dir_list)

    for dir in dir_list:           
        print(dir)
        checkFolders(directory +"/"+ dir) 

    printDirectoryFiles(directory)       

main_dir="C:/Users/S0082448/Desktop/carpeta1"

checkFolders(main_dir)


input("Press enter to exit ;")

全路径，计算路径为。，..， \\， ..\\…\ \文件夹等:

import os, pprint
pprint.pprint([os.path.join(os.path.abspath(path), x[0]) \
    for x in os.walk(os.path.abspath(path))])

比上面的要好得多，因为你不需要几个os.path.join()，你将直接获得完整的路径(如果你愿意的话)，你可以在Python 3.5及以上版本中这样做。

subfolders = [ f.path for f in os.scandir(folder) if f.is_dir() ]

这将给出子目录的完整路径。 如果您只想要子目录的名称，请使用f.name而不是f.path

https://docs.python.org/3/library/os.html#os.scandir

稍微OT:如果你需要递归所有子文件夹和/或递归所有文件，看看这个函数，它比os更快。Walk & glob将返回所有子文件夹以及这些(子)子文件夹中的所有文件的列表:https://stackoverflow.com/a/59803793/2441026

如果你只需要递归的所有子文件夹:

def fast_scandir(dirname):
    subfolders= [f.path for f in os.scandir(dirname) if f.is_dir()]
    for dirname in list(subfolders):
        subfolders.extend(fast_scandir(dirname))
    return subfolders

返回所有子文件夹及其完整路径的列表。这个还是比os快。走，比glob快多了。

所有功能的分析

tl;博士: -如果你想获取一个文件夹的所有直接子目录，请使用os.scandir。 —如果您想获取所有子目录，甚至是嵌套的子目录，请使用os。行走或者——稍微快一点——上面的fast_scandir函数。 —不要使用操作系统。只遍历顶级子目录，因为它可能比os.scandir慢数百倍(!)。

If you run the code below, make sure to run it once so that your OS will have accessed the folder, discard the results and run the test, otherwise results will be screwed. You might want to mix up the function calls, but I tested it, and it did not really matter. All examples will give the full path to the folder. The pathlib example as a (Windows)Path object. The first element of os.walk will be the base folder. So you will not get only subdirectories. You can use fu.pop(0) to remove it. None of the results will use natural sorting. This means results will be sorted like this: 1, 10, 2. To get natural sorting (1, 2, 10), please have a look at https://stackoverflow.com/a/48030307/2441026

结果:

os.scandir      took   1 ms. Found dirs: 439
os.walk         took 463 ms. Found dirs: 441 -> it found the nested one + base folder.
glob.glob       took  20 ms. Found dirs: 439
pathlib.iterdir took  18 ms. Found dirs: 439
os.listdir      took  18 ms. Found dirs: 439

用W7x64测试，Python 3.8.1。

# -*- coding: utf-8 -*-
# Python 3


import time
import os
from glob import glob
from pathlib import Path


directory = r"<insert_folder>"
RUNS = 1


def run_os_walk():
    a = time.time_ns()
    for i in range(RUNS):
        fu = [x[0] for x in os.walk(directory)]
    print(f"os.walk\t\t\ttook {(time.time_ns() - a) / 1000 / 1000 / RUNS:.0f} ms. Found dirs: {len(fu)}")


def run_glob():
    a = time.time_ns()
    for i in range(RUNS):
        fu = glob(directory + "/*/")
    print(f"glob.glob\t\ttook {(time.time_ns() - a) / 1000 / 1000 / RUNS:.0f} ms. Found dirs: {len(fu)}")


def run_pathlib_iterdir():
    a = time.time_ns()
    for i in range(RUNS):
        dirname = Path(directory)
        fu = [f for f in dirname.iterdir() if f.is_dir()]
    print(f"pathlib.iterdir\ttook {(time.time_ns() - a) / 1000 / 1000 / RUNS:.0f} ms. Found dirs: {len(fu)}")


def run_os_listdir():
    a = time.time_ns()
    for i in range(RUNS):
        dirname = Path(directory)
        fu = [os.path.join(directory, o) for o in os.listdir(directory) if os.path.isdir(os.path.join(directory, o))]
    print(f"os.listdir\t\ttook {(time.time_ns() - a) / 1000 / 1000 / RUNS:.0f} ms. Found dirs: {len(fu)}")


def run_os_scandir():
    a = time.time_ns()
    for i in range(RUNS):
        fu = [f.path for f in os.scandir(directory) if f.is_dir()]
    print(f"os.scandir\t\ttook {(time.time_ns() - a) / 1000 / 1000 / RUNS:.0f} ms.\tFound dirs: {len(fu)}")


if __name__ == '__main__':
    run_os_scandir()
    run_os_walk()
    run_glob()
    run_pathlib_iterdir()
    run_os_listdir()

我们可以使用os.walk()来获取所有文件夹的列表

import os

path = os.getcwd()

pathObject = os.walk(path)

这个pathObject是一个对象，我们可以通过

arr = [x for x in pathObject]

arr is of type [('current directory', [array of folder in current directory], [files in current directory]),('subdirectory', [array of folder in subdirectory], [files in subdirectory]) ....]

我们可以通过遍历arr并打印中间的数组来获得所有子目录的列表

for i in arr:
   for j in i[1]:
      print(j)

这将打印所有子目录。

获取所有文件:

for i in arr:
   for j in i[2]:
      print(i[0] + "/" + j)