我们可以使用os.walk()来获取所有文件夹的列表

import os

path = os.getcwd()

pathObject = os.walk(path)

这个pathObject是一个对象，我们可以通过

arr = [x for x in pathObject]

arr is of type [('current directory', [array of folder in current directory], [files in current directory]),('subdirectory', [array of folder in subdirectory], [files in subdirectory]) ....]

我们可以通过遍历arr并打印中间的数组来获得所有子目录的列表

for i in arr:
   for j in i[1]:
      print(j)

这将打印所有子目录。

获取所有文件:

for i in arr:
   for j in i[2]:
      print(i[0] + "/" + j)

下面是基于@Blair Conrad的例子的几个简单函数

import os

def get_subdirs(dir):
    "Get a list of immediate subdirectories"
    return next(os.walk(dir))[1]

def get_subfiles(dir):
    "Get a list of immediate subfiles"
    return next(os.walk(dir))[2]

下面这个类将能够获得一个给定目录中的文件，文件夹和所有子文件夹的列表

import os
import json

class GetDirectoryList():
    def __init__(self, path):
        self.main_path = path
        self.absolute_path = []
        self.relative_path = []


    def get_files_and_folders(self, resp, path):
        all = os.listdir(path)
        resp["files"] = []
        for file_folder in all:
            if file_folder != "." and file_folder != "..":
                if os.path.isdir(path + "/" + file_folder):
                    resp[file_folder] = {}
                    self.get_files_and_folders(resp=resp[file_folder], path= path + "/" + file_folder)
                else:
                    resp["files"].append(file_folder)
                    self.absolute_path.append(path.replace(self.main_path + "/", "") + "/" + file_folder)
                    self.relative_path.append(path + "/" + file_folder)
        return resp, self.relative_path, self.absolute_path

    @property
    def get_all_files_folder(self):
        self.resp = {self.main_path: {}}
        all = self.get_files_and_folders(self.resp[self.main_path], self.main_path)
        return all

if __name__ == '__main__':
    mylib = GetDirectoryList(path="sample_folder")
    file_list = mylib.get_all_files_folder
    print (json.dumps(file_list))

而样本目录看起来像

sample_folder/
    lib_a/
        lib_c/
            lib_e/
                __init__.py
                a.txt
            __init__.py
            b.txt
            c.txt
        lib_d/
            __init__.py
        __init__.py
        d.txt
    lib_b/
        __init__.py
        e.txt
    __init__.py

结果

[
  {
    "files": [
      "__init__.py"
    ],
    "lib_b": {
      "files": [
        "__init__.py",
        "e.txt"
      ]
    },
    "lib_a": {
      "files": [
        "__init__.py",
        "d.txt"
      ],
      "lib_c": {
        "files": [
          "__init__.py",
          "c.txt",
          "b.txt"
        ],
        "lib_e": {
          "files": [
            "__init__.py",
            "a.txt"
          ]
        }
      },
      "lib_d": {
        "files": [
          "__init__.py"
        ]
      }
    }
  },
  [
    "sample_folder/lib_b/__init__.py",
    "sample_folder/lib_b/e.txt",
    "sample_folder/__init__.py",
    "sample_folder/lib_a/lib_c/lib_e/__init__.py",
    "sample_folder/lib_a/lib_c/lib_e/a.txt",
    "sample_folder/lib_a/lib_c/__init__.py",
    "sample_folder/lib_a/lib_c/c.txt",
    "sample_folder/lib_a/lib_c/b.txt",
    "sample_folder/lib_a/lib_d/__init__.py",
    "sample_folder/lib_a/__init__.py",
    "sample_folder/lib_a/d.txt"
  ],
  [
    "lib_b/__init__.py",
    "lib_b/e.txt",
    "sample_folder/__init__.py",
    "lib_a/lib_c/lib_e/__init__.py",
    "lib_a/lib_c/lib_e/a.txt",
    "lib_a/lib_c/__init__.py",
    "lib_a/lib_c/c.txt",
    "lib_a/lib_c/b.txt",
    "lib_a/lib_d/__init__.py",
    "lib_a/__init__.py",
    "lib_a/d.txt"
  ]
]

import os
path = "test/"
files = [x[0] + "/" + y for x in os.walk(path) if len(x[-1]) > 0 for y in x[-1]]

由于我在使用Python 3.4和Windows UNC路径时偶然发现了这个问题，下面是这个环境的一个变体:

from pathlib import WindowsPath

def SubDirPath (d):
    return [f for f in d.iterdir() if f.is_dir()]

subdirs = SubDirPath(WindowsPath(r'\\file01.acme.local\home$'))
print(subdirs)

Pathlib是Python 3.4中的新功能，它使得在不同操作系统下使用路径更加容易: https://docs.python.org/3.4/library/pathlib.html

import os

d = '.'
[os.path.join(d, o) for o in os.listdir(d) 
                    if os.path.isdir(os.path.join(d,o))]