我正在使用datetime Python模块。我希望从当前日期计算6个月的日期。有人能帮我一下吗?
我想从当前日期生成一个6个月后的日期的原因是为了生成一个回顾日期。如果用户在系统中输入数据,系统将有从输入数据之日起6个月的审查日期。
我正在使用datetime Python模块。我希望从当前日期计算6个月的日期。有人能帮我一下吗?
我想从当前日期生成一个6个月后的日期的原因是为了生成一个回顾日期。如果用户在系统中输入数据,系统将有从输入数据之日起6个月的审查日期。
当前回答
我发现这个解决方法很好。(使用python-dateutil扩展名)
from datetime import date
from dateutil.relativedelta import relativedelta
six_months = date.today() + relativedelta(months=+6)
这种方法的优势在于,它可以处理28天、30天、31天的问题。这在处理业务规则和场景(比如发票生成等)时非常有用。
$ date(2010,12,31)+relativedelta(months=+1)
datetime.date(2011, 1, 31)
$ date(2010,12,31)+relativedelta(months=+2)
datetime.date(2011, 2, 28)
其他回答
我知道这是6个月,但是如果你要添加一个月,答案在谷歌中显示为“在python中添加月”:
import calendar
date = datetime.date.today() //Or your date
datetime.timedelta(days=calendar.monthrange(date.year,date.month)[1])
这将计算当前月份的天数,并将它们添加到当前日期,如果您在日期上迭代,则使用365/12将AD年的1/12会导致短/长月份出现问题。
当我需要添加几个月或几年的时间,并且不想导入更多的库时,我就会这样做。
import datetime
__author__ = 'Daniel Margarido'
# Check if the int given year is a leap year
# return true if leap year or false otherwise
def is_leap_year(year):
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
return True
else:
return False
else:
return True
else:
return False
THIRTY_DAYS_MONTHS = [4, 6, 9, 11]
THIRTYONE_DAYS_MONTHS = [1, 3, 5, 7, 8, 10, 12]
# Inputs -> month, year Booth integers
# Return the number of days of the given month
def get_month_days(month, year):
if month in THIRTY_DAYS_MONTHS: # April, June, September, November
return 30
elif month in THIRTYONE_DAYS_MONTHS: # January, March, May, July, August, October, December
return 31
else: # February
if is_leap_year(year):
return 29
else:
return 28
# Checks the month of the given date
# Selects the number of days it needs to add one month
# return the date with one month added
def add_month(date):
current_month_days = get_month_days(date.month, date.year)
next_month_days = get_month_days(date.month + 1, date.year)
delta = datetime.timedelta(days=current_month_days)
if date.day > next_month_days:
delta = delta - datetime.timedelta(days=(date.day - next_month_days) - 1)
return date + delta
def add_year(date):
if is_leap_year(date.year):
delta = datetime.timedelta(days=366)
else:
delta = datetime.timedelta(days=365)
return date + delta
# Validates if the expected_value is equal to the given value
def test_equal(expected_value, value):
if expected_value == value:
print "Test Passed"
return True
print "Test Failed : " + str(expected_value) + " is not equal to " str(value)
return False
# Test leap year
print "---------- Test leap year ----------"
test_equal(True, is_leap_year(2012))
test_equal(True, is_leap_year(2000))
test_equal(False, is_leap_year(1900))
test_equal(False, is_leap_year(2002))
test_equal(False, is_leap_year(2100))
test_equal(True, is_leap_year(2400))
test_equal(True, is_leap_year(2016))
# Test add month
print "---------- Test add month ----------"
test_equal(datetime.date(2016, 2, 1), add_month(datetime.date(2016, 1, 1)))
test_equal(datetime.date(2016, 6, 16), add_month(datetime.date(2016, 5, 16)))
test_equal(datetime.date(2016, 3, 15), add_month(datetime.date(2016, 2, 15)))
test_equal(datetime.date(2017, 1, 12), add_month(datetime.date(2016, 12, 12)))
test_equal(datetime.date(2016, 3, 1), add_month(datetime.date(2016, 1, 31)))
test_equal(datetime.date(2015, 3, 1), add_month(datetime.date(2015, 1, 31)))
test_equal(datetime.date(2016, 3, 1), add_month(datetime.date(2016, 1, 30)))
test_equal(datetime.date(2016, 4, 30), add_month(datetime.date(2016, 3, 30)))
test_equal(datetime.date(2016, 5, 1), add_month(datetime.date(2016, 3, 31)))
# Test add year
print "---------- Test add year ----------"
test_equal(datetime.date(2016, 2, 2), add_year(datetime.date(2015, 2, 2)))
test_equal(datetime.date(2001, 2, 2), add_year(datetime.date(2000, 2, 2)))
test_equal(datetime.date(2100, 2, 2), add_year(datetime.date(2099, 2, 2)))
test_equal(datetime.date(2101, 2, 2), add_year(datetime.date(2100, 2, 2)))
test_equal(datetime.date(2401, 2, 2), add_year(datetime.date(2400, 2, 2)))
只需创建一个datetime.date()对象,调用add_month(date)来添加一个月,调用add_year(date)来添加一个年。
假设你的datetime变量叫做date:
date=datetime.datetime(year=date.year+int((date.month+6)/12),
month=(date.month+6)%13 + (1 if (date.month +
months>12) else 0), day=date.day)
我认为这样做会比手动添加天数更安全:
import datetime
today = datetime.date.today()
def addMonths(dt, months = 0):
new_month = months + dt.month
year_inc = 0
if new_month>12:
year_inc +=1
new_month -=12
return dt.replace(month = new_month, year = dt.year+year_inc)
newdate = addMonths(today, 6)
我有一个更好的办法来解决“2月31日”的问题:
def add_months(start_date, months):
import calendar
year = start_date.year + (months / 12)
month = start_date.month + (months % 12)
day = start_date.day
if month > 12:
month = month % 12
year = year + 1
days_next = calendar.monthrange(year, month)[1]
if day > days_next:
day = days_next
return start_date.replace(year, month, day)
我认为它也适用于负数(减去月份),但我还没有对此进行过多测试。