如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
function object_to_array($data)
{
if (is_array($data) || is_object($data))
{
$result = array();
foreach ($data as $key => $value)
{
$result[$key] = object_to_array($value);
}
return $result;
}
return $data;
}
function array_to_object($data)
{
if (is_array($data) || is_object($data))
{
$result= new stdClass();
foreach ($data as $key => $value)
{
$result->$key = array_to_object($value);
}
return $result;
}
return $data;
}
其他回答
据我所知,没有内置的方法可以做到这一点,但它就像一个简单的循环一样简单:
$obj= new stdClass();
foreach ($array as $k=> $v) {
$obj->{$k} = $v;
}
如果你需要递归地构建你的对象,你可以详细说明。
多维数组转换为对象。此代码用于转换必应搜索API的尝试和捕获方法。
try {
// Perform the Web request and get the JSON response
$context = stream_context_create($options);
$results = file_get_contents($url . "?cc=" . $country . "&category=" . $type, false, $context);
$results = json_decode($results);
return response()->json($results);
} catch (\Exception $e) {
$results = array('value' => array(
(object) array(
"name" => "Unable to Retrive News",
"url" => "http://www.sample.com/",
"image" => (object) array("thumbnail" => (object) array("contentUrl" => "")),
"publishedAt" => "",
"description" => "")
)
);
$results = (object) $results;
return response()->json($results);
}
这里有三种方法:
Fake a real object: class convert { public $varible; public function __construct($array) { $this = $array; } public static function toObject($array) { $array = new convert($array); return $array; } } Convert the array into an object by casting it to an object: $array = array( // ... ); $object = (object) $array; Manually convert the array into an object: $object = object; foreach ($arr as $key => $value) { $object->{$key} = $value; }
我使用以下代码将Yaml文件关联数组解析为对象状态。
这将检查所有提供的数组中是否隐藏有对象,并将它们转换为对象。
/**
* Makes a config object from an array, making the first level keys properties a new object.
* Property values are converted to camelCase and are not set if one already exists.
* @param array $configArray Config array.
* @param boolean $strict To return an empty object if $configArray is not an array
* @return stdObject The config object
*/
public function makeConfigFromArray($configArray = [],$strict = true)
{
$object = new stdClass();
if (!is_array($configArray)) {
if(!$strict && !is_null($configArray)) {
return $configArray;
}
return $object;
}
foreach ($configArray as $name => $value) {
$_name = camel_case($name);
if(is_array($value)) {
$makeobject = true;
foreach($value as $key => $val) {
if(is_numeric(substr($key,0,1))) {
$makeobject = false;
}
if(is_array($val)) {
$value[$key] = $this->makeConfigFromArray($val,false);
}
}
if($makeobject) {
$object->{$name} = $object->{$_name} = $this->makeConfigFromArray($value,false);
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
return $object;
}
这将把yaml配置为
fields:
abc:
type: formfield
something:
- a
- b
- c
- d:
foo:
bar
到由以下数组组成的数组:
array:1 [
"fields" => array:1 [
"abc" => array:2 [
"type" => "formfield"
"something" => array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => array:1 [
"d" => array:1 [
"foo" => "bar"
]
]
]
]
]
]
以…为目标:
{#325
+"fields": {#326
+"abc": {#324
+"type": "formfield"
+"something": array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => {#328
+"d": {#327
+"foo": "bar"
}
}
]
}
}
}
容易:
$object = json_decode(json_encode($array));
例子:
$array = array(
'key' => array(
'k' => 'value',
),
'group' => array('a', 'b', 'c')
);
$object = json_decode(json_encode($array));
那么,以下是正确的:
$object->key->k === 'value';
$object->group === array('a', 'b', 'c')