如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
你也可以使用ArrayObject,例如:
<?php
$arr = array("test",
array("one"=>1,"two"=>2,"three"=>3),
array("one"=>1,"two"=>2,"three"=>3)
);
$o = new ArrayObject($arr);
echo $o->offsetGet(2)["two"],"\n";
foreach ($o as $key=>$val){
if (is_array($val)) {
foreach($val as $k => $v) {
echo $k . ' => ' . $v,"\n";
}
}
else
{
echo $val,"\n";
}
}
?>
//Output:
2
test
one => 1
two => 2
three => 3
one => 1
two => 2
three => 3
其他回答
我使用以下代码将Yaml文件关联数组解析为对象状态。
这将检查所有提供的数组中是否隐藏有对象,并将它们转换为对象。
/**
* Makes a config object from an array, making the first level keys properties a new object.
* Property values are converted to camelCase and are not set if one already exists.
* @param array $configArray Config array.
* @param boolean $strict To return an empty object if $configArray is not an array
* @return stdObject The config object
*/
public function makeConfigFromArray($configArray = [],$strict = true)
{
$object = new stdClass();
if (!is_array($configArray)) {
if(!$strict && !is_null($configArray)) {
return $configArray;
}
return $object;
}
foreach ($configArray as $name => $value) {
$_name = camel_case($name);
if(is_array($value)) {
$makeobject = true;
foreach($value as $key => $val) {
if(is_numeric(substr($key,0,1))) {
$makeobject = false;
}
if(is_array($val)) {
$value[$key] = $this->makeConfigFromArray($val,false);
}
}
if($makeobject) {
$object->{$name} = $object->{$_name} = $this->makeConfigFromArray($value,false);
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
else {
$object->{$name} = $object->{$_name} = $value;
}
}
return $object;
}
这将把yaml配置为
fields:
abc:
type: formfield
something:
- a
- b
- c
- d:
foo:
bar
到由以下数组组成的数组:
array:1 [
"fields" => array:1 [
"abc" => array:2 [
"type" => "formfield"
"something" => array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => array:1 [
"d" => array:1 [
"foo" => "bar"
]
]
]
]
]
]
以…为目标:
{#325
+"fields": {#326
+"abc": {#324
+"type": "formfield"
+"something": array:4 [
0 => "a"
1 => "b"
2 => "c"
3 => {#328
+"d": {#327
+"foo": "bar"
}
}
]
}
}
}
你也可以通过在变量的左边添加(object)来创建一个新对象。
<?php
$a = Array
( 'status' => " text" );
var_dump($a);
$b = (object)$a;
var_dump($b);
var_dump($b->status);
http://codepad.org/9YmD1KsU
我使用的一个(它是类成员):
const MAX_LEVEL = 5; // change it as needed
public function arrayToObject($a, $level=0)
{
if(!is_array($a)) {
throw new InvalidArgumentException(sprintf('Type %s cannot be cast, array expected', gettype($a)));
}
if($level > self::MAX_LEVEL) {
throw new OverflowException(sprintf('%s stack overflow: %d exceeds max recursion level', __METHOD__, $level));
}
$o = new stdClass();
foreach($a as $key => $value) {
if(is_array($value)) { // convert value recursively
$value = $this->arrayToObject($value, $level+1);
}
$o->{$key} = $value;
}
return $o;
}
受到所有这些代码的启发,我尝试创建一个增强版本,支持:特定的类名,避免构造函数方法,'beans'模式和严格模式(仅设置现有属性):
class Util {
static function arrayToObject($array, $class = 'stdClass', $strict = false) {
if (!is_array($array)) {
return $array;
}
//create an instance of an class without calling class's constructor
$object = unserialize(
sprintf(
'O:%d:"%s":0:{}', strlen($class), $class
)
);
if (is_array($array) && count($array) > 0) {
foreach ($array as $name => $value) {
$name = strtolower(trim($name));
if (!empty($name)) {
if(method_exists($object, 'set'.$name)){
$object->{'set'.$name}(Util::arrayToObject($value));
}else{
if(($strict)){
if(property_exists($class, $name)){
$object->$name = Util::arrayToObject($value);
}
}else{
$object->$name = Util::arrayToObject($value);
}
}
}
}
return $object;
} else {
return FALSE;
}
}
}
我也有这个问题,但我注意到json_decode将JSON数组转换为对象。
所以,我通过使用json_encode($PHPArray)来实现我的解决方案,它返回对象的JSON字符串,然后我用Json_decode($string)解码字符串,它将返回一个完美的结构化对象。 速记
$object = json_decode(json_encode($array));
Or
$jsonString = json_encode($array);
$object = json_decode($jsonString);