从URL路径下载文件的简单方法是什么?
当前回答
使用System.Net.WebClient.DownloadFile:
string remoteUri = "http://www.contoso.com/library/homepage/images/";
string fileName = "ms-banner.gif", myStringWebResource = null;
// Create a new WebClient instance.
using (WebClient myWebClient = new WebClient())
{
myStringWebResource = remoteUri + fileName;
// Download the Web resource and save it into the current filesystem folder.
myWebClient.DownloadFile(myStringWebResource, fileName);
}
其他回答
在将状态打印到控制台时下载文件的完整类。
using System;
using System.ComponentModel;
using System.IO;
using System.Net;
using System.Threading;
class FileDownloader
{
private readonly string _url;
private readonly string _fullPathWhereToSave;
private bool _result = false;
private readonly SemaphoreSlim _semaphore = new SemaphoreSlim(0);
public FileDownloader(string url, string fullPathWhereToSave)
{
if (string.IsNullOrEmpty(url)) throw new ArgumentNullException("url");
if (string.IsNullOrEmpty(fullPathWhereToSave)) throw new ArgumentNullException("fullPathWhereToSave");
this._url = url;
this._fullPathWhereToSave = fullPathWhereToSave;
}
public bool StartDownload(int timeout)
{
try
{
System.IO.Directory.CreateDirectory(Path.GetDirectoryName(_fullPathWhereToSave));
if (File.Exists(_fullPathWhereToSave))
{
File.Delete(_fullPathWhereToSave);
}
using (WebClient client = new WebClient())
{
var ur = new Uri(_url);
// client.Credentials = new NetworkCredential("username", "password");
client.DownloadProgressChanged += WebClientDownloadProgressChanged;
client.DownloadFileCompleted += WebClientDownloadCompleted;
Console.WriteLine(@"Downloading file:");
client.DownloadFileAsync(ur, _fullPathWhereToSave);
_semaphore.Wait(timeout);
return _result && File.Exists(_fullPathWhereToSave);
}
}
catch (Exception e)
{
Console.WriteLine("Was not able to download file!");
Console.Write(e);
return false;
}
finally
{
this._semaphore.Dispose();
}
}
private void WebClientDownloadProgressChanged(object sender, DownloadProgressChangedEventArgs e)
{
Console.Write("\r --> {0}%.", e.ProgressPercentage);
}
private void WebClientDownloadCompleted(object sender, AsyncCompletedEventArgs args)
{
_result = !args.Cancelled;
if (!_result)
{
Console.Write(args.Error.ToString());
}
Console.WriteLine(Environment.NewLine + "Download finished!");
_semaphore.Release();
}
public static bool DownloadFile(string url, string fullPathWhereToSave, int timeoutInMilliSec)
{
return new FileDownloader(url, fullPathWhereToSave).StartDownload(timeoutInMilliSec);
}
}
用法:
static void Main(string[] args)
{
var success = FileDownloader.DownloadFile(fileUrl, fullPathWhereToSave, timeoutInMilliSec);
Console.WriteLine("Done - success: " + success);
Console.ReadLine();
}
在.NET Core MVC中,你有时可以简单地这样做:
public async Task<ActionResult> DownloadUrl(string url) {
return Redirect(url);
}
这可能假设您正在尝试下载的MIME类型被浏览器设置为可下载(例如.mp4),因此它不会尝试重定向到网页。
你也可以在WebClient类中使用DownloadFileAsync方法。它将具有指定URI的资源下载到本地文件。此外,此方法不会阻塞调用线程。
示例:
webClient.DownloadFileAsync(new Uri("http://www.example.com/file/test.jpg"), "test.jpg");
欲了解更多信息:
http://csharpexamples.com/download-files-synchronous-asynchronous-url-c/
使用System.Net.WebClient.DownloadFile:
string remoteUri = "http://www.contoso.com/library/homepage/images/";
string fileName = "ms-banner.gif", myStringWebResource = null;
// Create a new WebClient instance.
using (WebClient myWebClient = new WebClient())
{
myStringWebResource = remoteUri + fileName;
// Download the Web resource and save it into the current filesystem folder.
myWebClient.DownloadFile(myStringWebResource, fileName);
}
下面的代码包含下载文件的逻辑与原始名称
private string DownloadFile(string url)
{
HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create(url);
string filename = "";
string destinationpath = Environment;
if (!Directory.Exists(destinationpath))
{
Directory.CreateDirectory(destinationpath);
}
using (HttpWebResponse response = (HttpWebResponse)request.GetResponseAsync().Result)
{
string path = response.Headers["Content-Disposition"];
if (string.IsNullOrWhiteSpace(path))
{
var uri = new Uri(url);
filename = Path.GetFileName(uri.LocalPath);
}
else
{
ContentDisposition contentDisposition = new ContentDisposition(path);
filename = contentDisposition.FileName;
}
var responseStream = response.GetResponseStream();
using (var fileStream = File.Create(System.IO.Path.Combine(destinationpath, filename)))
{
responseStream.CopyTo(fileStream);
}
}
return Path.Combine(destinationpath, filename);
}
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