# remove all the ticks (both axes), and tick labels on the Y axis
plt.tick_params(top='off', bottom='off', left='off', right='off', labelleft='off', labelbottom='on')

# remove all the ticks (both axes), and tick labels on the Y axis
plt.tick_params(top='off', bottom='off', left='off', right='off', labelleft='off', labelbottom='on')

或者，您可以传递一个空的标记位置并将其标记为

# for matplotlib.pyplot
# ---------------------
plt.xticks([], [])
# for axis object
# ---------------
# from Anakhand May 5 at 13:08
# for major ticks
ax.set_xticks([])
# for minor ticks
ax.set_xticks([], minor=True)

那些正在寻找一个短命令来关闭所有刻度和标签的人应该没问题

plt.tick_params(top=False, bottom=False, left=False, right=False,
                labelleft=False, labelbottom=False)

这允许类型bool为各自的参数，因为版本matplotlib>=2.1.1

对于自定义标记设置，文档是有帮助的:

https://matplotlib.org/api/_as_gen/matplotlib.axes.Axes.tick_params.html

以下是我在matplotlib邮件列表中找到的一个替代解决方案:

import matplotlib.pylab as plt

x = range(1000)
ax = plt.axes()
ax.semilogx(x, x)
ax.xaxis.set_ticks_position('none') 

plt。Tick_params方法对于这样的东西非常有用。这段代码关闭大刻度和小刻度，并从x轴上删除标签。

注意这里还有ax。matplotlib.axes.Axes对象的tick_params。

from matplotlib import pyplot as plt
plt.plot(range(10))
plt.tick_params(
    axis='x',          # changes apply to the x-axis
    which='both',      # both major and minor ticks are affected
    bottom=False,      # ticks along the bottom edge are off
    top=False,         # ticks along the top edge are off
    labelbottom=False) # labels along the bottom edge are off
plt.show()
plt.savefig('plot')
plt.clf()