如何计算字符串中字符出现的次数?
如。“a”在“Mary had a little lamb”中出现了4次。
如何计算字符串中字符出现的次数?
如。“a”在“Mary had a little lamb”中出现了4次。
当前回答
最简单的方法是一行代码:
'Mary had a little lamb'.count("a")
但是如果你想用这个也可以:
sentence ='Mary had a little lamb'
count=0;
for letter in sentence :
if letter=="a":
count+=1
print (count)
其他回答
你可以使用循环和字典。
def count_letter(text):
result = {}
for letter in text:
if letter not in result:
result[letter] = 0
result[letter] += 1
return result
不超过这个IMHO -你可以添加上或下的方法
def count_letter_in_str(string,letter):
return string.count(letter)
这个简单直接的函数可能会有帮助:
def check_freq(x):
freq = {}
for c in set(x):
freq[c] = x.count(c)
return freq
check_freq("abbabcbdbabdbdbabababcbcbab")
{'a': 7, 'b': 14, 'c': 3, 'd': 3}
如果需要理解:
def check_freq(x):
return {c: x.count(c) for c in set(x)}
你可以使用.count():
>>> 'Mary had a little lamb'.count('a')
4
要获得所有字母的计数,请使用集合。计数器:
>>> from collections import Counter
>>> counter = Counter("Mary had a little lamb")
>>> counter['a']
4