我想检查变量是否存在。现在我在做这样的事情:
try:
myVar
except NameError:
# Do something.
有没有其他没有例外的方法?
我想检查变量是否存在。现在我在做这样的事情:
try:
myVar
except NameError:
# Do something.
有没有其他没有例外的方法?
当前回答
处理这种情况的一种方法通常是不显式检查变量是否存在,而是直接将可能不存在的变量的第一次使用包装在try/except NameError中:
# Search for entry.
for x in y:
if x == 3:
found = x
# Work with found entry.
try:
print('Found: {0}'.format(found))
except NameError:
print('Not found')
else:
# Handle rest of Found case here
...
其他回答
简短的变体:
my_var = some_value if 'my_var' not in globals() else my_var:
对于对象/模块,也可以
'var' in dir(obj)
例如,
>>> class Something(object):
... pass
...
>>> c = Something()
>>> c.a = 1
>>> 'a' in dir(c)
True
>>> 'b' in dir(c)
False
查询一个局部变量是否存在。
if 'myVar' in locals():
# myVar exists.
检查全局变量是否存在:
if 'myVar' in globals():
# myVar exists.
检查一个对象是否有属性:
if hasattr(obj, 'attr_name'):
# obj.attr_name exists.
处理这种情况的一种方法通常是不显式检查变量是否存在,而是直接将可能不存在的变量的第一次使用包装在try/except NameError中:
# Search for entry.
for x in y:
if x == 3:
found = x
# Work with found entry.
try:
print('Found: {0}'.format(found))
except NameError:
print('Not found')
else:
# Handle rest of Found case here
...
像这样:
def no(var):
"give var as a string (quote it like 'var')"
assert(var not in vars())
assert(var not in globals())
assert(var not in vars(__builtins__))
import keyword
assert(var not in keyword.kwlist)
之后:
no('foo')
foo = ....
如果你的新变量foo使用起来不安全,你会得到一个AssertionError异常,它会指向失败的行,然后你就知道了。 这是一个明显做作的自我指涉:
no('no')
---------------------------------------------------------------------------
AssertionError Traceback (most recent call last)
<ipython-input-88-d14ecc6b025a> in <module>
----> 1 no('no')
<ipython-input-86-888a9df72be0> in no(var)
2 "give var as a string (quote it)"
3 assert( var not in vars())
----> 4 assert( var not in globals())
5 assert( var not in vars(__builtins__))
6 import keyword
AssertionError: