我需要在Python程序中模拟一个do-while循环。不幸的是,下面的简单代码不能工作:
list_of_ints = [ 1, 2, 3 ]
iterator = list_of_ints.__iter__()
element = None
while True:
if element:
print element
try:
element = iterator.next()
except StopIteration:
break
print "done"
不是"1,2,3,done",而是输出如下:
[stdout:]1
[stdout:]2
[stdout:]3
None['Traceback (most recent call last):
', ' File "test_python.py", line 8, in <module>
s = i.next()
', 'StopIteration
']
为了捕获“停止迭代”异常并中断一段时间,我能做些什么
循环正常吗?
下面的伪代码显示了为什么需要这样一个东西的示例。
状态机:
s = ""
while True :
if state is STATE_CODE :
if "//" in s :
tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
state = STATE_COMMENT
else :
tokens.add( TOKEN_CODE, s )
if state is STATE_COMMENT :
if "//" in s :
tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
else
state = STATE_CODE
# Re-evaluate same line
continue
try :
s = i.next()
except StopIteration :
break
我不知道你想干什么。你可以像这样实现一个do-while循环:
while True:
stuff()
if fail_condition:
break
Or:
stuff()
while not fail_condition:
stuff()
你为什么要用一个do while循环来打印列表中的东西?为什么不直接使用:
for i in l:
print i
print "done"
更新:
你有台词清单吗?你想一直遍历它吗?如何:
for s in l:
while True:
stuff()
# use a "break" instead of s = i.next()
这看起来像是你想要的吗?对于您的代码示例,它将是:
for s in some_list:
while True:
if state is STATE_CODE:
if "//" in s:
tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
state = STATE_COMMENT
else :
tokens.add( TOKEN_CODE, s )
if state is STATE_COMMENT:
if "//" in s:
tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
break # get next s
else:
state = STATE_CODE
# re-evaluate same line
# continues automatically
你想知道:
为了捕捉“停止迭代”异常并正确地打破while循环,我能做些什么?
你可以这样做,如下所示,这也利用了Python 3.8中引入的赋值表达式特性(又名“海象运算符”):
list_of_ints = [1, 2, 3]
iterator = iter(list_of_ints)
try:
while (element := next(iterator)):
print(element)
except StopIteration:
print("done")
另一种可能(从Python 2.6到3.x都适用)是为内置的next()函数提供一个默认参数,以避免StopIteration异常:
SENTINEL = object() # Unique object.
list_of_ints = [1, 2, 3]
iterator = iter(list_of_ints)
while True:
element = next(iterator, SENTINEL)
if element is SENTINEL:
break
print(element)
print("done")