如何将表单的所有元素转换为JavaScript对象？
我希望有某种方法从表单自动构建JavaScript对象，而不必遍历每个元素。我不希望使用$（'#formid'）.serialize（）；返回的字符串；，我也不希望$（'#formid'）.serializeArray（）返回映射；
当前回答
这里有一种非jQuery方法：
var getFormData = function(form) {
//Ignore the submit button
var elements = Array.prototype.filter.call(form.elements, function(element) {
var type = element.getAttribute('type');
return !type || type.toLowerCase() !== 'submit';
});
您可以这样使用：
function() {
var getFormData = function(form) {
//Ignore the submit button
var elements = Array.prototype.filter.call(form.elements, function(element) {
var type = element.getAttribute('type');
return !type || type.toLowerCase() !== 'submit';
});
//Make an object out of the form data: {name: value}
var data = elements.reduce(function(data, element) {
data[element.name] = element.value;
return data;
}, {});
return data;
};
var post = function(action, data, callback) {
var request = new XMLHttpRequest();
request.onload = callback;
request.open('post', action);
request.setRequestHeader("Content-Type", "application/json;charset=UTF-8");
request.send(JSON.stringify(data), true);
request.send();
};
var submit = function(e) {
e.preventDefault();
var form = e.target;
var action = form.action;
var data = getFormData(form);
//change the third argument in order to do something
//more intersting with the response than just print it
post(action, data, console.log.bind(console));
}
//change formName below
document.formName.onsubmit = submit;
})();
其他回答
像boss一样将表单转换为JSON
目前的来源是GitHub和Bower。
$bower安装jquery序列化对象
以下代码现已弃用。
以下代码可以处理所有类型的输入名称；按照你的预期处理它们。
例如：
<!-- All of these will work! -->
<input name="honey[badger]" value="a">
<input name="wombat[]" value="b">
<input name="hello[panda][]" value="c">
<input name="animals[0][name]" value="d">
<input name="animals[0][breed]" value="e">
<input name="crazy[1][][wonky]" value="f">
<input name="dream[as][vividly][as][you][can]" value="g">
// Output
{
"honey":{
"badger":"a"
},
"wombat":["b"],
"hello":{
"panda":["c"]
},
"animals":[
{
"name":"d",
"breed":"e"
}
],
"crazy":[
null,
[
{"wonky":"f"}
]
],
"dream":{
"as":{
"vividly":{
"as":{
"you":{
"can":"g"
}
}
}
}
}
}
用法
$('#my-form').serializeObject();
魔法（JavaScript）
(function($){
$.fn.serializeObject = function(){
var self = this,
json = {},
push_counters = {},
patterns = {
"validate": /^[a-zA-Z][a-zA-Z0-9_]*(?:\[(?:\d*|[a-zA-Z0-9_]+)\])*$/,
"key": /[a-zA-Z0-9_]+|(?=\[\])/g,
"push": /^$/,
"fixed": /^\d+$/,
"named": /^[a-zA-Z0-9_]+$/
};
this.build = function(base, key, value){
base[key] = value;
return base;
};
this.push_counter = function(key){
if(push_counters[key] === undefined){
push_counters[key] = 0;
}
return push_counters[key]++;
};
$.each($(this).serializeArray(), function(){
// Skip invalid keys
if(!patterns.validate.test(this.name)){
return;
}
var k,
keys = this.name.match(patterns.key),
merge = this.value,
reverse_key = this.name;
while((k = keys.pop()) !== undefined){
// Adjust reverse_key
reverse_key = reverse_key.replace(new RegExp("\\[" + k + "\\]$"), '');
// Push
if(k.match(patterns.push)){
merge = self.build([], self.push_counter(reverse_key), merge);
}
// Fixed
else if(k.match(patterns.fixed)){
merge = self.build([], k, merge);
}
// Named
else if(k.match(patterns.named)){
merge = self.build({}, k, merge);
}
}
json = $.extend(true, json, merge);
});
return json;
};
})(jQuery);
所有这些答案对我来说似乎都太过头了。为了简单起见，有些话要说。只要您的所有表单输入都设置了name属性，这应该只适用于jimdandy。
$（'form.myform'）.submit（函数（）{var$this=$（this），viewArr=$this.serializeArray（），视图=｛｝；for（viewArr中的var i）{view[viewArr[i].name]=viewArr[i].value；}//在这里使用视图对象（例如JSON.stringify？）});
这里有一种非jQuery方法：
var getFormData = function(form) {
//Ignore the submit button
var elements = Array.prototype.filter.call(form.elements, function(element) {
var type = element.getAttribute('type');
return !type || type.toLowerCase() !== 'submit';
});
您可以这样使用：
function() {
var getFormData = function(form) {
//Ignore the submit button
var elements = Array.prototype.filter.call(form.elements, function(element) {
var type = element.getAttribute('type');
return !type || type.toLowerCase() !== 'submit';
});
//Make an object out of the form data: {name: value}
var data = elements.reduce(function(data, element) {
data[element.name] = element.value;
return data;
}, {});
return data;
};
var post = function(action, data, callback) {
var request = new XMLHttpRequest();
request.onload = callback;
request.open('post', action);
request.setRequestHeader("Content-Type", "application/json;charset=UTF-8");
request.send(JSON.stringify(data), true);
request.send();
};
var submit = function(e) {
e.preventDefault();
var form = e.target;
var action = form.action;
var data = getFormData(form);
//change the third argument in order to do something
//more intersting with the response than just print it
post(action, data, console.log.bind(console));
}
//change formName below
document.formName.onsubmit = submit;
})();
如果要发送带有JSON的表单，则必须在发送字符串时删除[]。您可以使用jQuery函数serializeObject（）实现这一点：
var frm = $(document.myform);
var data = JSON.stringify(frm.serializeObject());
$.fn.serializeObject = function() {
var o = {};
//var a = this.serializeArray();
$(this).find('input[type="hidden"], input[type="text"], input[type="password"], input[type="checkbox"]:checked, input[type="radio"]:checked, select').each(function() {
if ($(this).attr('type') == 'hidden') { //If checkbox is checked do not take the hidden field
var $parent = $(this).parent();
var $chb = $parent.find('input[type="checkbox"][name="' + this.name.replace(/\[/g, '\[').replace(/\]/g, '\]') + '"]');
if ($chb != null) {
if ($chb.prop('checked')) return;
}
}
if (this.name === null || this.name === undefined || this.name === '')
return;
var elemValue = null;
if ($(this).is('select'))
elemValue = $(this).find('option:selected').val();
else
elemValue = this.value;
if (o[this.name] !== undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(elemValue || '');
}
else {
o[this.name] = elemValue || '';
}
});
return o;
}
对于这个问题，我找到的最简单、最准确的方法是使用bbq插件或这个插件（大约0.5K字节大小）。
它也适用于多维阵列。
$.fn.serializeObject=函数（）{return$.departam（this.serialize（））；};
