使用SQL Server,我如何分割一个字符串,以便我可以访问项目x?
拿一根“你好,约翰·史密斯”的绳子。我如何通过空格分割字符串并访问索引1应该返回“约翰”的项目?
使用SQL Server,我如何分割一个字符串,以便我可以访问项目x?
拿一根“你好,约翰·史密斯”的绳子。我如何通过空格分割字符串并访问索引1应该返回“约翰”的项目?
当前回答
下面的示例使用递归CTE
更新18.09.2013
CREATE FUNCTION dbo.SplitStrings_CTE(@List nvarchar(max), @Delimiter nvarchar(1))
RETURNS @returns TABLE (val nvarchar(max), [level] int, PRIMARY KEY CLUSTERED([level]))
AS
BEGIN
;WITH cte AS
(
SELECT SUBSTRING(@List, 0, CHARINDEX(@Delimiter, @List + @Delimiter)) AS val,
CAST(STUFF(@List + @Delimiter, 1, CHARINDEX(@Delimiter, @List + @Delimiter), '') AS nvarchar(max)) AS stval,
1 AS [level]
UNION ALL
SELECT SUBSTRING(stval, 0, CHARINDEX(@Delimiter, stval)),
CAST(STUFF(stval, 1, CHARINDEX(@Delimiter, stval), '') AS nvarchar(max)),
[level] + 1
FROM cte
WHERE stval != ''
)
INSERT @returns
SELECT REPLACE(val, ' ','' ) AS val, [level]
FROM cte
WHERE val > ''
RETURN
END
演示SQLFiddle
其他回答
修改@Aaron Bertrand的功能
CREATE FUNCTION [dbo].[SplitString]
(
@List NVARCHAR(MAX),
@Delim VARCHAR(255),
@Idx int
)
RETURNS NVARCHAR(1000)
AS
BEGIN
DECLARE @ValueTable TABLE(String NVARCHAR(50), Ind int)
DECLARE @Value NVARCHAR(50)
BEGIN
INSERT INTO @ValueTable
SELECT Value, idx FROM
(SELECT [Value], idx = RANK() OVER (ORDER BY n) FROM
(
SELECT n = Number,
[Value] = LTRIM(RTRIM(SUBSTRING(@List, [Number],
CHARINDEX(@Delim, @List + @Delim, [Number]) - [Number])))
FROM
(SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
FROM sys.all_objects) AS x
WHERE Number <= LEN(@List)
AND SUBSTRING(@Delim + @List, [Number], LEN(@Delim)) = @Delim
) AS y
) AS R WHERE idx = @Idx
SET @Value = (SELECT String FROM @ValueTable)
END
RETURN @Value
END
GO
Aaron Bertrand的回答很好,但也有缺陷。它不能准确地将空格作为分隔符处理(就像最初问题中的示例一样),因为长度函数将空格带在后面。
下面是他的代码,稍微调整了一下,允许使用空格分隔符:
CREATE FUNCTION [dbo].[SplitString]
(
@List NVARCHAR(MAX),
@Delim VARCHAR(255)
)
RETURNS TABLE
AS
RETURN ( SELECT [Value] FROM
(
SELECT
[Value] = LTRIM(RTRIM(SUBSTRING(@List, [Number],
CHARINDEX(@Delim, @List + @Delim, [Number]) - [Number])))
FROM (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
FROM sys.all_objects) AS x
WHERE Number <= LEN(@List)
AND SUBSTRING(@Delim + @List, [Number], LEN(@Delim+'x')-1) = @Delim
) AS y
);
可以利用Number表进行字符串解析。
创建一个物理数字表:
create table dbo.Numbers (N int primary key);
insert into dbo.Numbers
select top 1000 row_number() over(order by number) from master..spt_values
go
创建具有1000000行的测试表
create table #yak (i int identity(1,1) primary key, array varchar(50))
insert into #yak(array)
select 'a,b,c' from dbo.Numbers n cross join dbo.Numbers nn
go
创建函数
create function [dbo].[ufn_ParseArray]
( @Input nvarchar(4000),
@Delimiter char(1) = ',',
@BaseIdent int
)
returns table as
return
( select row_number() over (order by n asc) + (@BaseIdent - 1) [i],
substring(@Input, n, charindex(@Delimiter, @Input + @Delimiter, n) - n) s
from dbo.Numbers
where n <= convert(int, len(@Input)) and
substring(@Delimiter + @Input, n, 1) = @Delimiter
)
go
使用情况(在我的笔记本电脑上40秒内输出3mil行)
select *
from #yak
cross apply dbo.ufn_ParseArray(array, ',', 1)
清理
drop table dbo.Numbers;
drop function [dbo].[ufn_ParseArray]
这里的性能并不惊人,但在100万行表上调用函数并不是最好的主意。如果将字符串拆分到多行,我会避免使用该函数。
几乎所有其他答案都是替换正在分割的字符串,这浪费了CPU周期并执行不必要的内存分配。
我在这里介绍了一种更好的进行字符串拆分的方法:http://www.digitalruby.com/split-string-sql-server/
代码如下:
SET NOCOUNT ON
-- You will want to change nvarchar(MAX) to nvarchar(50), varchar(50) or whatever matches exactly with the string column you will be searching against
DECLARE @SplitStringTable TABLE (Value nvarchar(MAX) NOT NULL)
DECLARE @StringToSplit nvarchar(MAX) = 'your|string|to|split|here'
DECLARE @SplitEndPos int
DECLARE @SplitValue nvarchar(MAX)
DECLARE @SplitDelim nvarchar(1) = '|'
DECLARE @SplitStartPos int = 1
SET @SplitEndPos = CHARINDEX(@SplitDelim, @StringToSplit, @SplitStartPos)
WHILE @SplitEndPos > 0
BEGIN
SET @SplitValue = SUBSTRING(@StringToSplit, @SplitStartPos, (@SplitEndPos - @SplitStartPos))
INSERT @SplitStringTable (Value) VALUES (@SplitValue)
SET @SplitStartPos = @SplitEndPos + 1
SET @SplitEndPos = CHARINDEX(@SplitDelim, @StringToSplit, @SplitStartPos)
END
SET @SplitValue = SUBSTRING(@StringToSplit, @SplitStartPos, 2147483647)
INSERT @SplitStringTable (Value) VALUES(@SplitValue)
SET NOCOUNT OFF
-- You can select or join with the values in @SplitStringTable at this point.
下面的示例使用递归CTE
更新18.09.2013
CREATE FUNCTION dbo.SplitStrings_CTE(@List nvarchar(max), @Delimiter nvarchar(1))
RETURNS @returns TABLE (val nvarchar(max), [level] int, PRIMARY KEY CLUSTERED([level]))
AS
BEGIN
;WITH cte AS
(
SELECT SUBSTRING(@List, 0, CHARINDEX(@Delimiter, @List + @Delimiter)) AS val,
CAST(STUFF(@List + @Delimiter, 1, CHARINDEX(@Delimiter, @List + @Delimiter), '') AS nvarchar(max)) AS stval,
1 AS [level]
UNION ALL
SELECT SUBSTRING(stval, 0, CHARINDEX(@Delimiter, stval)),
CAST(STUFF(stval, 1, CHARINDEX(@Delimiter, stval), '') AS nvarchar(max)),
[level] + 1
FROM cte
WHERE stval != ''
)
INSERT @returns
SELECT REPLACE(val, ' ','' ) AS val, [level]
FROM cte
WHERE val > ''
RETURN
END
演示SQLFiddle