我知道一些方法来检查字符串是否只包含数字: 正则表达式,int。解析,tryparse,循环等等。

谁能告诉我最快的方法是什么?

我只需要检查值,不需要实际解析它。

通过“数字”,我是指具体的ASCII数字:0 1 2 3 4 5 6 7 8 9。

如果字符串是数字,这个问题与Identify不同,因为这个问题不仅是关于如何识别,而且是关于识别的最快方法是什么。


当前回答

我喜欢Linq,让它在第一次不匹配时退出,你可以这样做

string str = '0129834X33';
bool isAllDigits = !str.Any( ch=> ch < '0' || ch > '9' );

其他回答

如果你关心性能,不要使用int型。TryParse或Regex -编写自己的(简单的)函数(下面是DigitsOnly或DigitsOnly2,但不是DigitsOnly3 - LINQ似乎会引起很大的开销)。

另外,要注意int。如果字符串太长,不能“适合”int, TryParse将失败。

这个简单的基准测试…

class Program {

    static bool DigitsOnly(string s) {
        int len = s.Length;
        for (int i = 0; i < len; ++i) {
            char c = s[i];
            if (c < '0' || c > '9')
                return false;
        }
        return true;
    }

    static bool DigitsOnly2(string s) {
        foreach (char c in s) {
            if (c < '0' || c > '9')
                return false;
        }
        return true;
    }

    static bool DigitsOnly3(string s) {
        return s.All(c => c >= '0' && c <= '9');
    }

    static void Main(string[] args) {

        const string s1 = "916734184";
        const string s2 = "916734a84";

        const int iterations = 1000000;
        var sw = new Stopwatch();

        sw.Restart();
        for (int i = 0 ; i < iterations; ++i) {
            bool success = DigitsOnly(s1);
            bool failure = DigitsOnly(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("DigitsOnly: {0}", sw.Elapsed));

        sw.Restart();
        for (int i = 0; i < iterations; ++i) {
            bool success = DigitsOnly2(s1);
            bool failure = DigitsOnly2(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("DigitsOnly2: {0}", sw.Elapsed));

        sw.Restart();
        for (int i = 0; i < iterations; ++i) {
            bool success = DigitsOnly3(s1);
            bool failure = DigitsOnly3(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("DigitsOnly3: {0}", sw.Elapsed));

        sw.Restart();
        for (int i = 0; i < iterations; ++i) {
            int dummy;
            bool success = int.TryParse(s1, out dummy);
            bool failure = int.TryParse(s2, out dummy);
        }
        sw.Stop();
        Console.WriteLine(string.Format("int.TryParse: {0}", sw.Elapsed));

        sw.Restart();
        var regex = new Regex("^[0-9]+$", RegexOptions.Compiled);
        for (int i = 0; i < iterations; ++i) {
            bool success = regex.IsMatch(s1);
            bool failure = regex.IsMatch(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("Regex.IsMatch: {0}", sw.Elapsed));

    }

}

...产生以下结果…

DigitsOnly: 00:00:00.0346094
DigitsOnly2: 00:00:00.0365220
DigitsOnly3: 00:00:00.2669425
int.TryParse: 00:00:00.3405548
Regex.IsMatch: 00:00:00.7017648

下面是一些基于相同字符串的1000000次解析的基准测试:

更新发布数据:

IsDigitsOnly: 384588
TryParse:     639583
Regex:        1329571

下面是代码,看起来IsDigitsOnly更快:

class Program
{
    private static Regex regex = new Regex("^[0-9]+$", RegexOptions.Compiled);

    static void Main(string[] args)
    {
        Stopwatch watch = new Stopwatch();
        string test = int.MaxValue.ToString();
        int value;

        watch.Start();
        for(int i=0; i< 1000000; i++)
        {
            int.TryParse(test, out value);
        }
        watch.Stop();
        Console.WriteLine("TryParse: "+watch.ElapsedTicks);

        watch.Reset();
        watch.Start();
        for (int i = 0; i < 1000000; i++)
        {
            IsDigitsOnly(test);
        }
        watch.Stop();
        Console.WriteLine("IsDigitsOnly: " + watch.ElapsedTicks);

        watch.Reset();
        watch.Start();
        for (int i = 0; i < 1000000; i++)
        {
            regex.IsMatch(test);
        }
        watch.Stop();
        Console.WriteLine("Regex: " + watch.ElapsedTicks);

        Console.ReadLine();
    }

    static bool IsDigitsOnly(string str)
    {
        foreach (char c in str)
        {
            if (c < '0' || c > '9')
                return false;
        }

        return true;
    }
}

当然值得注意的是,TryParse确实允许前导/尾随空白以及区域性特定的符号。弦的长度也有限制。

我做了一些小改变@ theecodeking的回答。

似乎;

对于int类型,最快的方法是TryParse

对于长类型最快的方法是正则表达式。

我的结果如下(打勾)

For int:

TryParse Max: 355788
IsDigitsOnly Max: 787013
Regex Max: 1297691

TryParse Avg: 186007
IsDigitsOnly Avg: 430963
Regex Avg: 464657,79

TryParse Min: 162742
IsDigitsOnly Min: 335646
Regex Min: 452121


For float :

TryParse Max : 3151995
IsDigitsOnly Max: 1392740
Regex Max : 1283451

TryParse Avg: 1391636
IsDigitsOnly Avg: 824029
Regex Avg: 501176

TryParse Min: 1187410
IsDigitsOnly Min: 706646
Regex Min: 476204

代码为long:

using System.Diagnostics;
using System.Text.RegularExpressions;

class Program
{
    private static Regex regex = new Regex("^[0-9]+$", RegexOptions.Compiled);

    static void Main(string[] args)
    {
        Stopwatch watch = new Stopwatch();
        watch.Start();
        watch.Stop();
        watch.Reset();
        List<TimeSpan> tryparse = new List<TimeSpan>();
        List<TimeSpan> isdigitsonly = new List<TimeSpan>();
        List<TimeSpan> regexss = new List<TimeSpan>();

        for (int say = 0; say < 1000; say++)
        { 
            float value;

            string test = Random.Shared.NextInt64(1000,long.MaxValue).ToString();
            watch.Start();
            for (int i = 0; i < 1000000; i++)
            {
                float.TryParse(test, out value);
            }
            watch.Stop();
            //Console.WriteLine("TryParse: " + watch.Elapsed);
            tryparse.Add(watch.Elapsed);

            watch.Reset();
            watch.Start();
            for (int i = 0; i < 1000000; i++)
            {
                IsDigitsOnly(test);
            }
            watch.Stop();
            //Console.WriteLine("IsDigitsOnly: " + watch.Elapsed);
            isdigitsonly.Add(watch.Elapsed);
            watch.Reset();
            watch.Start();
            for (int i = 0; i < 1000000; i++)
            {
                regex.IsMatch(test);
            }
            watch.Stop();
            regexss.Add(watch.Elapsed);
            watch.Reset();
            //   Console.WriteLine("Regex: " + watch.Elapsed);
     
            Console.Write("---------------------% " + (Convert.ToDecimal( say)/ 999 * 100).ToString("N2") + "---------------------------");
            Console.CursorLeft = 0;
        }
        Console.WriteLine();
        Console.WriteLine($"TryParse: {tryparse.Max(t => t.Ticks)}");
        Console.WriteLine($"IsDigitsOnly: {isdigitsonly.Max(t => t.Ticks)}");
        Console.WriteLine($"Regex: {regexss.Max(t => t.Ticks)}");
        Console.WriteLine();

        Console.WriteLine($"TryParse Avg: {tryparse.Average(t => t.Ticks)}");
        Console.WriteLine($"IsDigitsOnly Avg: {isdigitsonly.Average(t => t.Ticks)}");
        Console.WriteLine($"Regex Avg: {regexss.Average(t => t.Ticks)}");
        Console.WriteLine();
        Console.WriteLine($"TryParse Min: {tryparse.Min(t => t.Ticks)}");
        Console.WriteLine($"IsDigitsOnly Min: {isdigitsonly.Min(t => t.Ticks)}");
        Console.WriteLine($"Regex Min: {regexss.Min(t => t.Ticks)}");
        Console.ReadLine();
    }

    static bool IsDigitsOnly(string str)
    {
        foreach (char c in str)
        {
            if (c < '0' || c > '9')
                return false;
        }

        return true;
    }
}

另一种方法!

string str = "12345";
bool containsOnlyDigits = true;
try { if(Convert.ToInt32(str) < 0){ containsOnlyDigits = false; } }
catch { containsOnlyDigits = false; }

在这里,如果Convert.ToInt32(str)语句失败,则字符串不仅仅包含数字。另一种可能性是,如果字符串具有“-12345”,并成功转换为-12345,则会检查转换后的数字是否小于零。

该字符已经有一个IsDigit(char c),它是这样做的:

 public static bool IsDigit(char c)
    {
      if (!char.IsLatin1(c))
        return CharUnicodeInfo.GetUnicodeCategory(c) == UnicodeCategory.DecimalDigitNumber;
      if ((int) c >= 48)
        return (int) c <= 57;
      else
        return false;
    }

你可以简单地这样做:

var theString = "839278";
bool digitsOnly = theString.All(char.IsDigit);