查询参数

org.apache.commons.httpclient.util.URIUtil
    URIUtil.encodeQuery(input);

如果你想转义URI中的字符

public static String escapeURIPathParam(String input) {
  StringBuilder resultStr = new StringBuilder();
  for (char ch : input.toCharArray()) {
   if (isUnsafe(ch)) {
    resultStr.append('%');
    resultStr.append(toHex(ch / 16));
    resultStr.append(toHex(ch % 16));
   } else{
    resultStr.append(ch);
   }
  }
  return resultStr.toString();
 }

 private static char toHex(int ch) {
  return (char) (ch < 10 ? '0' + ch : 'A' + ch - 10);
 }

 private static boolean isUnsafe(char ch) {
  if (ch > 128 || ch < 0)
   return true;
  return " %$&+,/:;=?@<>#%".indexOf(ch) >= 0;
 }

“+”是正确的。如果你真的需要%20，然后自己替换加。

警告:这个答案有很大的争议(+8 vs. -6)，所以对这个答案持保留态度。

查询参数

org.apache.commons.httpclient.util.URIUtil
    URIUtil.encodeQuery(input);

如果你想转义URI中的字符

public static String escapeURIPathParam(String input) {
  StringBuilder resultStr = new StringBuilder();
  for (char ch : input.toCharArray()) {
   if (isUnsafe(ch)) {
    resultStr.append('%');
    resultStr.append(toHex(ch / 16));
    resultStr.append(toHex(ch % 16));
   } else{
    resultStr.append(ch);
   }
  }
  return resultStr.toString();
 }

 private static char toHex(int ch) {
  return (char) (ch < 10 ? '0' + ch : 'A' + ch - 10);
 }

 private static boolean isUnsafe(char ch) {
  if (ch > 128 || ch < 0)
   return true;
  return " %$&+,/:;=?@<>#%".indexOf(ch) >= 0;
 }

该类执行application/x-www-form- urlenencoded -type编码，而不是百分比编码，因此替换为+是正确的行为。

从javadoc:

When encoding a String, the following rules apply: The alphanumeric characters "a" through "z", "A" through "Z" and "0" through "9" remain the same. The special characters ".", "-", "*", and "_" remain the same. The space character " " is converted into a plus sign "+". All other characters are unsafe and are first converted into one or more bytes using some encoding scheme. Then each byte is represented by the 3-character string "%xy", where xy is the two-digit hexadecimal representation of the byte. The recommended encoding scheme to use is UTF-8. However, for compatibility reasons, if an encoding is not specified, then the default encoding of the platform is used.

一个空格在url中被编码为%20，在表单提交的数据中被编码为+(内容类型为application/x-www-form-urlencoded)。你需要前者。

使用番石榴:

dependencies {
     compile 'com.google.guava:guava:23.0'
     // or, for Android:
     compile 'com.google.guava:guava:23.0-android'
}

你可以使用UrlEscapers:

String encodedString = UrlEscapers.urlFragmentEscaper().escape(inputString);

不要使用String。替换，这只会编码空间。使用库代替。

试试下面的方法:

添加一个新的依赖项

<!-- https://mvnrepository.com/artifact/org.apache.tomcat/tomcat-catalina -->
<dependency>
    <groupId>org.apache.tomcat</groupId>
    <artifactId>tomcat-catalina</artifactId>
    <version>10.0.13</version>
</dependency>

现在按照下面的步骤做:

String str = "Hello+World"; // For "Hello World", decoder is not required
// import java.net.URLDecoder;
String newURL = URLDecoder.decode(str, StandardCharsets.UTF_8);
// import org.apache.catalina.util.URLEncoder;
System.out.println(URLEncoder.DEFAULT.encode(newURL, StandardCharsets.UTF_8));

你会得到如下的输出:

Hello%20World