我在资产文件夹里有几个文件。我需要把它们都复制到一个文件夹,比如/sdcard/folder。我想从一个线程中做这件事。我该怎么做?


当前回答

这就是我的个性化文本提取类,希望对大家有用。

package lorenzo.morelli.platedetector;

import android.content.Context;
import android.content.res.AssetManager;
import android.graphics.Bitmap;

import com.googlecode.tesseract.android.TessBaseAPI;

import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

public class TextExtractor {

    private final Context context;
    private final String dirName;
    private final String language;

    public TextExtractor(final Context context, final String dirName, final String language) {
        this.context = context;
        this.dirName = dirName;
        this.language = language;
    }

    public String extractText(final Bitmap bitmap) {
        final TessBaseAPI tessBaseApi = new TessBaseAPI();
        final String datapath = this.context.getFilesDir()+ "/tesseract/";
        checkFile(new File(datapath + this.dirName + "/"), datapath, this.dirName, this.language);

        tessBaseApi.init(datapath, this.language);
        tessBaseApi.setImage(bitmap);
        final String extractedText = tessBaseApi.getUTF8Text();
        tessBaseApi.end();
        return extractedText;
    }

    private void checkFile(final File dir, final String datapath, final String dirName, final String language) {
        //directory does not exist, but we can successfully create it
        if (!dir.exists()&& dir.mkdirs()) {
            copyFiles(datapath, dirName, language);
        } //The directory exists, but there is no data file in it
        if(dir.exists()) {
            final String datafilepath = datapath + "/" + dirName + "/" + language + ".traineddata";
            final File datafile = new File(datafilepath);
            if (!datafile.exists()) {
                copyFiles(datapath, dirName, language);
            }
        }
    }

    private void copyFiles(final String datapath, final String dirName, final String language) {
        try {
            //location we want the file to be at
            final String filepath = datapath + "/" + dirName + "/" + language + ".traineddata";

            //get access to AssetManager
            final AssetManager assetManager = this.context.getAssets();

            //open byte streams for reading/writing
            final InputStream instream = assetManager.open(dirName + "/" + language + ".traineddata");
            final OutputStream outstream = new FileOutputStream(filepath);

            //copy the file to the location specified by filepath
            byte[] buffer = new byte[1024];
            int read;
            while ((read = instream.read(buffer)) != -1) {
                outstream.write(buffer, 0, read);
            }
            outstream.flush();
            outstream.close();
            instream.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

要使用它,你需要训练过的数据文件。你可以从这个链接下载trainddata文件。

一旦你下载了你想要的traineddata文件,你需要在你的Android项目中创建一个名为assets的Android资源目录。在新创建的资产文件夹中,你需要创建一个名为“tessdata”的常规目录,在那里你可以放置你的训练数据文件。 最后你必须初始化MainActivity中的“TextExtractor”类。

final TextExtractor textExtractor = new TextExtractor(this, "tessdata", "eng");

第一个参数是上下文,第二个参数是刚刚创建的目录名,最后一个参数是刚刚下载的训练数据的语言。

要提取文本,你必须调用"extractText"方法:

final String text = textExtractor.extractText(imageWithText);

注意,extractText需要一个位图图像才能工作!! 你可以用这一行从你的可绘制文件中创建一个BitMap图像:

final BitMap image = BitmapFactory.decodeResource(getResources(), R.drawable.test_image);

如果你需要更多的支持,我建议你遵循这个有用的指南:https://github.com/SamVanRoy/Android_OCR_App

其他回答

这里是一个针对当前Android设备的清理版本,功能方法设计,以便您可以将其复制到AssetsHelper类,例如;)

/**
 * 
 * Info: prior to Android 2.3, any compressed asset file with an
 * uncompressed size of over 1 MB cannot be read from the APK. So this
 * should only be used if the device has android 2.3 or later running!
 * 
 * @param c
 * @param targetFolder
 *            e.g. {@link Environment#getExternalStorageDirectory()}
 * @throws Exception
 */
@TargetApi(Build.VERSION_CODES.GINGERBREAD)
public static boolean copyAssets(AssetManager assetManager,
        File targetFolder) throws Exception {
    Log.i(LOG_TAG, "Copying files from assets to folder " + targetFolder);
    return copyAssets(assetManager, "", targetFolder);
}

/**
 * The files will be copied at the location targetFolder+path so if you
 * enter path="abc" and targetfolder="sdcard" the files will be located in
 * "sdcard/abc"
 * 
 * @param assetManager
 * @param path
 * @param targetFolder
 * @return
 * @throws Exception
 */
public static boolean copyAssets(AssetManager assetManager, String path,
        File targetFolder) throws Exception {
    Log.i(LOG_TAG, "Copying " + path + " to " + targetFolder);
    String sources[] = assetManager.list(path);
    if (sources.length == 0) { // its not a folder, so its a file:
        copyAssetFileToFolder(assetManager, path, targetFolder);
    } else { // its a folder:
        if (path.startsWith("images") || path.startsWith("sounds")
                || path.startsWith("webkit")) {
            Log.i(LOG_TAG, "  > Skipping " + path);
            return false;
        }
        File targetDir = new File(targetFolder, path);
        targetDir.mkdirs();
        for (String source : sources) {
            String fullSourcePath = path.equals("") ? source : (path
                    + File.separator + source);
            copyAssets(assetManager, fullSourcePath, targetFolder);
        }
    }
    return true;
}

private static void copyAssetFileToFolder(AssetManager assetManager,
        String fullAssetPath, File targetBasePath) throws IOException {
    InputStream in = assetManager.open(fullAssetPath);
    OutputStream out = new FileOutputStream(new File(targetBasePath,
            fullAssetPath));
    byte[] buffer = new byte[16 * 1024];
    int read;
    while ((read = in.read(buffer)) != -1) {
        out.write(buffer, 0, read);
    }
    in.close();
    out.flush();
    out.close();
}

你可以用Kotlin在几个步骤中做到这一点,在这里我只复制几个文件,而不是所有从资产到我的应用程序文件目录。

private fun copyRelatedAssets() {
    val assets = arrayOf("myhome.html", "support.css", "myscript.js", "style.css")
    assets.forEach {
        val inputStream = requireContext().assets.open(it)
        val nameSplit = it.split(".")
        val name = nameSplit[0]
        val extension = nameSplit[1]
        val path = inputStream.getFilePath(requireContext().filesDir, name, extension)
        Log.v(TAG, path)
    }
}

这是扩展函数,

fun InputStream.getFilePath(dir: File, name: String, extension: String): String {
    val file = File(dir, "$name.$extension")
    val outputStream = FileOutputStream(file)
    this.copyTo(outputStream, 4096)
    return file.absolutePath
}

洛格猫

/data/user/0/com.***.***/files/myhome.html
/data/user/0/com.***.***/files/support.css
/data/user/0/com.***.***/files/myscript.js
/data/user/0/com.***.***/files/style.css

使用这个问题答案中的一些概念,我编写了一个名为assetcopyer的类来简化复制/assets/。它在github上可用,可以通过jitpack.io访问:

new AssetCopier(MainActivity.this)
        .withFileScanning()
        .copy("tocopy", destDir);

详情见https://github.com/flipagram/android-assetcopier。

如果其他人也有同样的问题,我就是这么做的

private void copyAssets() {
    AssetManager assetManager = getAssets();
    String[] files = null;
    try {
        files = assetManager.list("");
    } catch (IOException e) {
        Log.e("tag", "Failed to get asset file list.", e);
    }
    if (files != null) for (String filename : files) {
        InputStream in = null;
        OutputStream out = null;
        try {
          in = assetManager.open(filename);
          File outFile = new File(getExternalFilesDir(null), filename);
          out = new FileOutputStream(outFile);
          copyFile(in, out);
        } catch(IOException e) {
            Log.e("tag", "Failed to copy asset file: " + filename, e);
        }     
        finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    // NOOP
                }
            }
            if (out != null) {
                try {
                    out.close();
                } catch (IOException e) {
                    // NOOP
                }
            }
        }  
    }
}
private void copyFile(InputStream in, OutputStream out) throws IOException {
    byte[] buffer = new byte[1024];
    int read;
    while((read = in.read(buffer)) != -1){
      out.write(buffer, 0, read);
    }
}

参考:使用Java移动文件

基于Yoram Cohen的回答,这里有一个支持非静态目标目录的版本。

使用copyFileOrDir(getDataDir(), "")来写入应用程序内部存储文件夹/data/data/pkg_name/

Supports subfolders. Supports custom and non-static target directory Avoids copying "images" etc fake asset folders like private void copyFileOrDir(String TARGET_BASE_PATH, String path) { AssetManager assetManager = this.getAssets(); String assets[] = null; try { Log.i("tag", "copyFileOrDir() "+path); assets = assetManager.list(path); if (assets.length == 0) { copyFile(TARGET_BASE_PATH, path); } else { String fullPath = TARGET_BASE_PATH + "/" + path; Log.i("tag", "path="+fullPath); File dir = new File(fullPath); if (!dir.exists() && !path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit")) if (!dir.mkdirs()) Log.i("tag", "could not create dir "+fullPath); for (int i = 0; i < assets.length; ++i) { String p; if (path.equals("")) p = ""; else p = path + "/"; if (!path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit")) copyFileOrDir(TARGET_BASE_PATH, p + assets[i]); } } } catch (IOException ex) { Log.e("tag", "I/O Exception", ex); } } private void copyFile(String TARGET_BASE_PATH, String filename) { AssetManager assetManager = this.getAssets(); InputStream in = null; OutputStream out = null; String newFileName = null; try { Log.i("tag", "copyFile() "+filename); in = assetManager.open(filename); if (filename.endsWith(".jpg")) // extension was added to avoid compression on APK file newFileName = TARGET_BASE_PATH + "/" + filename.substring(0, filename.length()-4); else newFileName = TARGET_BASE_PATH + "/" + filename; out = new FileOutputStream(newFileName); byte[] buffer = new byte[1024]; int read; while ((read = in.read(buffer)) != -1) { out.write(buffer, 0, read); } in.close(); in = null; out.flush(); out.close(); out = null; } catch (Exception e) { Log.e("tag", "Exception in copyFile() of "+newFileName); Log.e("tag", "Exception in copyFile() "+e.toString()); } }