我的iOS应用程序为UINavigationBar使用了自定义高度，这在新的iPhone X上导致了一些问题。
是否有人已经知道如何通过编程(在Objective-C中)可靠地检测应用程序是否在iPhone X上运行?
编辑:
当然，检查屏幕的大小是可能的，但是，我想知道是否有一些“内置”的方法，如TARGET_OS_IPHONE来检测iOS…
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
if (screenSize.height == 812)
NSLog(@"iPhone X");
}
编辑2:
我不认为，我的问题是一个重复的关联问题。当然，有一些方法可以“测量”当前设备的不同属性，并使用结果来决定使用哪种设备。然而，这并不是我在第一篇编辑中试图强调的问题的实际意义。
真正的问题是:“是否有可能直接检测当前设备是否是iPhone X(例如通过某些SDK功能)，还是我必须使用间接测量?”
根据目前给出的答案，我假设答案是“不，没有直接的方法。测量是要走的路。”
所有使用高度的答案都只是故事的一半，原因只有一个。如果你想这样检查当设备朝向是landscapeLeft或landscape ight时检查会失败，因为高度和宽度互换了。
这就是为什么我的解决方案看起来像这样在Swift 4.0:
extension UIScreen {
///
static var isPhoneX: Bool {
let screenSize = UIScreen.main.bounds.size
let width = screenSize.width
let height = screenSize.height
return min(width, height) == 375 && max(width, height) == 812
}
}
随着iOS 12的发布，像iPhone X这样的设备可能会被归入这一类别。
`
extension UIDevice {
var isPortrait: Bool {
return UIDeviceOrientationIsPortrait(orientation) ||
UIInterfaceOrientationIsPortrait(UIApplication.shared.statusBarOrientation)
}
var isDeviceWith_XShape : Bool {
if self.userInterfaceIdiom == .phone {
if isPortrait
{
switch UIScreen.main.nativeBounds.height {
case 2436,2688,1792:
print("iPhone X, Xs, Xr, Xs Max")
return true
default:
print("Any other device")
return false
}
}
else
{
switch UIScreen.main.nativeBounds.width {
case 2436,2688,1792:
print("iPhone X, Xs, Xr, Xs Max")
return true
default:
print("Any other device")
return false
}
}
}
else
{
return false
}
}`
使用简单的方法检测任何设备。像下面,
func isPhoneDevice() -> Bool {
return UIDevice.current.userInterfaceIdiom == .phone
}
func isDeviceIPad() -> Bool {
return UIDevice.current.userInterfaceIdiom == .pad
}
func isPadProDevice() -> Bool {
let SCREEN_WIDTH: CGFloat = UIScreen.main.bounds.size.width
let SCREEN_HEIGHT: CGFloat = UIScreen.main.bounds.size.height
let SCREEN_MAX_LENGTH: CGFloat = fmax(SCREEN_WIDTH, SCREEN_HEIGHT)
return UIDevice.current.userInterfaceIdiom == .pad && SCREEN_MAX_LENGTH == 1366.0
}
func isPhoneXandXSDevice() -> Bool {
let SCREEN_WIDTH = CGFloat(UIScreen.main.bounds.size.width)
let SCREEN_HEIGHT = CGFloat(UIScreen.main.bounds.size.height)
let SCREEN_MAX_LENGTH: CGFloat = fmax(SCREEN_WIDTH, SCREEN_HEIGHT)
return UIDevice.current.userInterfaceIdiom == .phone && SCREEN_MAX_LENGTH == 812.0
}
func isPhoneXSMaxandXRDevice() -> Bool {
let SCREEN_WIDTH = CGFloat(UIScreen.main.bounds.size.width)
let SCREEN_HEIGHT = CGFloat(UIScreen.main.bounds.size.height)
let SCREEN_MAX_LENGTH: CGFloat = fmax(SCREEN_WIDTH, SCREEN_HEIGHT)
return UIDevice.current.userInterfaceIdiom == .phone && SCREEN_MAX_LENGTH == 896.0
}
像这样叫，
if isPhoneDevice() {
// Your code
}
SWIFT 4+回答
iPhone X, XR, XS, XSMAX, 11 Pro, 11 Pro Max:
注:需实物设备进行测试
参考
let deviceType = UIDevice.current.modelName
switch deviceType {
case "iPhone10,3", "iPhone10,6":
print("iPhoneX")
case "iPhone11,2":
print("iPhone XS")
case "iPhone11,4":
print("iPhone XS Max")
case "iPhone11,6":
print("iPhone XS Max China")
case "iPhone11,8":
print("iPhone XR")
case "iPhone12,3":
print("iPhone 11 Pro")
case "iPhone12,5":
print("iPhone 11 Pro Max")
default:
break
}
extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
return identifier
}
}
